Answer:
Step-by-step explanation:
The function representing the sales of digital cameras (in millions of units) in year t is
f(t) = 3.06t + 6.84 (0 ≤ t ≤ 3)
Also,
The function representing the sales of film cameras (in millions of units) is given by
g(t) = −1.85t + 16.48 (0 ≤ t ≤ 3)
a) where t = 0 corresponds to the end of 2001,
The number of digital cameras sold in 2001 would be
3.06 × 0 + 6.84 = 6.84 digital cameras.
The number of film cameras sold in 2001 would be
−1.85 × 0 + 16.48 = 16.48 film cameras.
Therefore, more film cameras than digital cameras were sold in 2001.
b) 3.06t + 6.84 = −1.85t + 16.48
3.06t + 1.85t = 16.48 - 6.84
4.91t = 9.64
t = 9.64/4.91 = 1.96
Therefore, the sales of digital cameras first exceed those of film cameras at t = 2 and that is in 2003.
answer with coding and answer is attached in word file below
The doublePennies() function is an illustration of a recursive function in Java
The base case of the doublePennies() function is that:
When the number of days is 0, then the total available pennies is the same as the total number of pennies.
The algorithm of the above highlight is:
if numDays equals 0 then
totalPennies = numPennies
Using the above algorithm, the complete base case is:
if(numDays == 0){
totalPennies = numPennies;
}
Read more about Java programs at:
Answer:
Weighted mean hourly charge = $168.28 (Approx)
Given:
Charge for research = $125 per hour
Charge for consultations = $80 per hour
Charge for writing a brief = $250 per hour
Research work = 12 hour
Consultations = 8 hour
Writing = 15 hour
Computation:
Total hours = 12 + 8 + 15 = 35 hours
Total charge for researching = $125 × 12 = $1,500
Total charge for consulting = $80 × 8 = $640
Total charge for writing = $250 × 15 = $3,750
Total charge = $5,890
Weighted mean hourly charge = 5890 / 35
Weighted mean hourly charge = $168.28 (Approx)
Answer:
answers is 2/3 ok hi your answers
Answer:
option 3
Step-by-step explanation:
We know this is a cube-root parent function due to the shape of the curve. Option C moves the graphed function from the origin (0,0) to two units to the left and one unit upward.
A B C
X
3
В В В
The value of ABC is 340.
The multiplication problem can be written as follows:
ABC
x 3
-----
BBBB
The product of the two numbers is a 4-digit number, so the product of the units digits must be 4. Since 3 x 4 = 12, and the product of the units digits is 4, the units digit of the product is 4, and the carryover is 1.
The product of the tens digits must be a multiple of 10, since the product of the units digits is 4 and the carryover is 1. The only possibility is 3 x B = 1B, where B is an even digit. Since B is a single digit, the only even digit that works is 4. Therefore, B = 4, and the carryover is 1.
The product of the hundreds digits must be a multiple of 100, since the product of the tens digits is a multiple of 10 and the carryover is 1. The only possibility is 3 x A + 1 = 1A, where A is a digit greater than or equal to 3. Since A is a single digit, the only digit greater than or equal to 3 that works is 3. Therefore, A = 3, and the product of the hundreds digits is 10.
The product of the thousands digits must be 0, since the product of the hundreds digits is 10 and the carryover is 0. Therefore, C = 0.
Therefore, the value of ABC is 340.
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Answer:
ABC = 148, 3*148 = 444
Step-by-step explanation:
We know that 111 = 3* 37, so all numbers of the form BBB has the factor 37.
So we need a multiple of 37 such thant when multiplied, we get three digits the same as the middle digit.
Try 4*37 = 148, 148*3 = 444, bingo, we got the right combination.
So ABC is 148.