15. P(-3, 14). Q(2, -1), R(4,8), S(-2.-10) Types of lines m(PQ) -3 m(s) 3 neitherEXPLANASION PLZZZZ

Answers

Answer 1

Answer:

Final answer:

The slope of line PQ calculated using the the formula (y₂-y₁)/(x₂-x₁) comes out to be -3 as given in the question. However, the complete information for line S is not provided, so its slope cannot be calculated.

Explanation:

The question is related to the types of lines formed by the given points in a Cartesian plane. Here, m(PQ) and m(S) represent the slopes of the lines formed by points P and Q, and line S respectively.

We calculate the gradient or slope of a line using the formula m = (y₂-y₁)/(x₂-x₁) where (x₁, y₁) and (x₂, y₂) are the coordinates of two distinct points on the line.

So, for line PQ the slope m(PQ) = (-1-14)/(2-(-3)) = -15/5 = -3. This matches the value given for m(PQ) in the question, thus establishing that PQ is a line with slope -3 in the Cartesian plane.

However, you haven't provided the complete information about the line S (only one coordinate is given). So, we cannot compute its slope. Please check the information given.

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Answer 2

Answer:

Answer:

Step-by-step explanation:

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A baker is calculating the charge for two types of cookies. what formula tells the cost, in dollars, if chocolate chip cookies are $1.50/dozen and lemon frosted cookies $1.00/dozen. c=number of dozen of chocolate chip cookies; L=number of dozen lemon frosted; T=total charge.

Answers

Answer: Each dozen of chocolate chip cookies costs $1.50/dozen. So if you sell C dozens of them, you win C*$1.50 dollars, where C is a positive integer number. Similar case for the lemon ones, the baker will win L*$1.00 dollars if he sells L dozens of them ( where L is a positive integer), the total charge is the sum of both parts; T = L*$1.00 + C*$1.50.

$1.50c(chocolate chips) + $1.00L(lemon frosted)=T(total cost)

Use the Distributive Property to solve the equation.2x - 4(x-3) = -5+2x-3
The solution of the equation is .
(Type the value of x.)

Answers

Answer:

x=14/4

Step-by-step explanation:

2x-4x+12 = -5+2x+3

-2x+12 = -2+2x

-2x-2x = -12-2

-4x=-14

x=-14/-4

x=14/4

What is the slope of the line through (−10,1)(-10,1)
(−10,1)
left parenthesis, minus, 10, comma, 1, right parenthesis
and
(0,−4)(0,-4)
(0,−4)
left parenthesis, 0, comma, minus, 4, right parenthesis
?

Answers

Answer:

-1/2

Step-by-step explanation:

The slope formula can be used:

m = (y2 -y1)/(x2 -x1)

m = (-4 -1)/(0 -(-10)) = -5/10

m = -1/2

The slope of the line through the given points is -1/2.

The slope of the line passing through (-10, 1) and (0, -4) is -1/2 the answer is -1/2.

What is the slope?

The ratio that y increase as x increases is the slope of a line. The slope of a line reflects how steep it is, but how much y increases as x increases. Anywhere on the line, the slope stays unchanged (the same).

$\rm m =(y_2-y_1)/(x_2-x_1)$

We have two points:

(-10, 1) and (0, -4)

The slope:

$\rm m =(-4-1)/(0-(-10))$

m = -5/10

m = -1/2

Thus, the slope of the line passing through (-10, 1) and (0, -4) is -1/2 the answer is -1/2.

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I need help finding the domain and range, I already know is not a function

Answers

Answer:

Domain: [-4, 4]

Range: [-3, 5]

Function? No

Step-by-step explanation:

Domain is all x-values that can be inputted in the graph that returns an output.

Range is all y-values that are outputted when x is inputted.

A function has to pass the Vertical Line Test.

In a manual on how to have a number one song, it is stated that a song must be no longer than 210 seconds. A simple random sample of 40 current hit songs results in a mean length of 241.4 sec. and a standard deviation of 57.59 sec. Use a 0.05 significance level and the accompanying minitab display to test the claim that the sample is from a population of songs with a mean great thatn 210 sec. What do these results suggest about the advice given in the manual.The mini tab displays the following:

One-sample T

Test of mu=210 vs.>210

N Mean St. Dev SE Mean 95% lower bound T p

40 241.40 57.59 9.11 226.06 3.45 0.001

A H0 u>210 sec. H1 u < 210sec

B H0 u=210 sec. H1 u < 210sec

C H0 u<210 sec. H1 u> 210sec

D H0 u=210 sec. H1 u> 210sec

Identify the test statistic:

T =

Identify the P-Value

P-value=

Stat the final conclusion that addresses the original claim. Choose from below:

A. Reject H0. There is insufficient evidence to support the claim that the sample is from a population of songs with a mean length greater than 210 sec.
B. Fail to reject H0. There is insufficient evidence to support the claim that the sample is from a population of songs with a mean length great thatn 210 sec.
C. Reject H0. There is sufficient evidence to spport the claim that the sample is from a population of songs with a mean length greater than 210 sec.
D. Fail to reject H0. There is sufficient evidence to support the claim tha tthe sample is from a population of songs with a mean lenght greater than 210 sec.

What do the results suggest about the advice given in the manual?

A. The results do not suggest that the advice of writing a song that must be no longer than 210 seconds is not sound advice.
B The results suggest that the advice of writing a song that must be no longer than 210 seconds is not sound advice
C. The results suggest that 241.4 seconds is the best song lenght.
D. The results are inconclusive because the average length of a hit song is constantly changing.

Answers

Answer:

D H0 u=210 sec. H1 u> 210sec

$t=(241.4-210)/((57.59)/(√(40)))=3.448$

$p_v =P(t_((39))>3.448)=0.000684$

C. Reject H0. There is sufficient evidence to spport the claim that the sample is from a population of songs with a mean length greater than 210 sec.

Step-by-step explanation:

Data given and notation

$\bar X=241.4$ represent the sample mean

$s=57.59$ represent the sample standard deviation for the sample

$n=40$ sample size

$\mu_o =210$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is greater than 210 seconds, the system of hypothesis would be:

Null hypothesis: $\mu \leq 210$

Alternative hypothesis: $\mu > 210$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=(\bar X-\mu_o)/((s)/(√(n)))$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=(241.4-210)/((57.59)/(√(40)))=3.448$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=40-1=39$

Since is a one side test the p value would be:

$p_v =P(t_((39))>3.448)=0.000684$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v<\alpha$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is significantly higher than 210 seconds.

C. Reject H0. There is sufficient evidence to spport the claim that the sample is from a population of songs with a mean length greater than 210 sec.

Find the product of (5.2 · 10^-6) and (8 · 10^3).A) 416 · 106-4
B) 4.16 · 10^-2
C) 41.6 · 10^-3
D) 0.416 · 10^-1

Answers

Answer: B) $4.16\cdot10^(-2)$

Step-by-step explanation:

The given product : $(5.2\cdot10^(-6))\cdot (8\cdot10^3)$

First open parenthesis :

$5.2\cdot10^(-6)\cdot 8\cdot10^3$

Write decimal values together and power of 10s together.

$5.2\cdot 8\cdot10^(-6)\cdot10^3$

Using Law of exponent : $a^m\cdot a^n= a^(m+n)$

The above expression becomes.

$41.6\cdot10^(-6+3)=41.6*10^(-3)$

In scientific notation, the decimal must be placed after one digit (from left).

$41.6*10^(-3)=4.16*10*10^(-3)\n\n=4.16\cdot10^(-3+1)\n\n=4.16\cdot10^(-2)$

Hence, the correct answer is B) $4.16\cdot10^(-2)$ .

$\displaystyle\n(5.2\cdot10^(-6))*(8\cdot10^3)=\n\n=\underbrace{5.2*8}_(41.6)*\underbrace{10^(-6)*10^(3)}_(10^(-6+3))=\n\n=41.6*10^(-6+3)=\boxed{\bf41.6*10^(-3)}\n\n\texttt{Correct answer:}~~\boxed{\bf C)}$