MATHEMATICS HIGH SCHOOL

A rectangle’s width is 2 meters shorter than its length, l. Its area is 168 square meters. Which equation can be used to find the length of the rectangle?l(l – 2) = 168
l(l + 2) = 168
2l 2 = 168
1/2l 2 = 168

Answers

Answer 1

Answer: Since area of a triangle is;
l*w=area
l(l-2)=168

Answer 2

Answer:

Answer:

Step-by-step explanation:

the anwser is A or the first one trust

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Answers

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Answers

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Answers

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The regular octagon has a perimeter of 122.4 cm. Which statements about the octagon are true? Check all that apply.

Answers

Answer:

The length of segment XY can be found by solving for a in

$20^2-7.65^2=a^2$

The measure of the central angle $\angle ZXW$ is $45\degree$ .

Step-by-step explanation:

If the regular octagon has a perimeter of 122.4cm, then each side is $(122.4)/(8)=15.3cm$

The measure of each central angle is $(360\degree)/(8)=45\degree$

The angle between the apothem and the radius is $(45)/(2)=22.5\degree$

The segment XY=a is the height of the right isosceles triangle.

We can use the Pythagoras Theorem with right triangle XYZ to get:

$a^2+7.65^2=20^2$

$a^2=20^2-7.65^2$

Therefore, the correct options are:

The length of segment XY can be found by solving for a in

$20^2-7.65^2=a^2$

The measure of the central angle $\angle ZXW$ is $45\degree$ .

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