If the metabolic rate of cockroaches at 15°C is 0.01 ml O2/hr and their metabolic rate at 25°C is 0.015 ml O2/hr. What is its metabolic rate at 20°C?

Answers

Answer 1
Answer:

Answer:

0.0035 mL of oxygen per hour is metabolic rate at 20°C at cockroach.

Explanation:

  • Metabolic rate of cockroaches at 15°C is 0.01 ml O2/h
  • Metabolic rate of cockroaches at 25°C is 0.015 ml O2/hr

From the data we can see that metabolic rate of cockroach is in direct relation with temperature.

Rate \propto Time

On graph, with metabolic rate on y-axis and temperature on x axis straight line will obtained , and the equation of the line can be determined by the help of point slope:

(y-y_1)=m(x-x_1)

m = Slope of the line = (y_2-y_1)/(x_2-x_1)

As per information given , :

(x_1,y_1) , (x_2,y_2) = (15,0.01) (25,0.015)

m=(0.015-0.01)/(25-15)=(0.005)/(10)=0.0005

(y-0.01)=0.0005(x-15)

y-0.001=0.0005x-0.0075

y=0.0005x-0.0065

x = temperature

y = metabolic rate

Now , put x = 20

y=0.0005* 20-0.0065

y = 0.0035

0.0035 mL of oxygen per hour is metabolic rate at 20°C at cockroach.


Related Questions

Addiction is a disease that disrupts the brain systems that regulate self-discipline. a. True b. False
Chinstrap and Gentoo penguins are two species of penguins that both feed on krill in the Antarctic Ocean. (These are different penguin populations from those shown in figure 38.4.) Drag the correct word or phrase from the left to complete the following sentences. Not all choices will be used. These two populations occupy the same area and have the same food source. They compete because they have the same niche. Over many generations, Gentoo penguins are driven to local extinction by the better adapted Chinstrap penguins. This is an example of _________. Over many generations. Gentoo penguins in another area adapt to feed on krill at greater depths than the Chinstrap penguins. This is an example of __________.
Describe how the body’s mechanisms maintain homeostasis?
You are examining the phylogenic relationship of a newly discovered plant species (Species 2). You amplify the RUBISCO barcode and sequence the DNA. After entering your sequence into BOLD the following comparison comes up.Species 1. ATGCAAATTTGGGCATCCGAATGGTTGCAASpecies 2. ATGCAAATTTTTTGGGCATCCGAATGGCAAWhat DNA modifications have occurred in Species 2 that makes it different from Species 1? Check all that apply.a. Inversionb. Duplicationc. Deletion
Which one is NOT a secondary consumerA. herbivoreB. lionC. carnivoreD. ominvore

As a ribosome translocates along an mRNA molecule by one codon, which of the following occurs? a. The polypeptide enters the E site. b. The tRNA that was in the A site departs from the ribosome via a tunnel. c. The tRNA that was in the P site moves into the A site. d. The tRNA that was in the A site moves to the E site and is released. e. The tRNA that was in the A site moves into the P site.

Answers

Answer:

e. The tRNA that was in the A site moves into the P site.

Explanation:

Translation comprises 3 steps :

1) Translation initiation

2) Translation elongation

3) Translation termination

Translocation step is a part of translation elongation step which is followed by the peptidyl transferase activity of ribosome. Due to the peptidyl transferase activity of ribosome, the N terminal of newly entered amino acid (amino acid attached with tRNA i.e. aminoacyl tRNA or charged tRNA) at 'A site' attacks the C terminus of amino acid which is already present in the 'P site' of complex and amide bond is formed between amino acids leading to elongation of peptide chain. Then after, the uncharged tRNA which is present in the 'P site' is expelled out the complex via 'E site' while the tRNA that was in 'A site' moves into the 'P site'.

Once M’Kenna’s small intestine healed, she started eating foods with dairy again and these foods no longer made her sick. Lactase is an enzyme that helps break down foods with dairy. In a healthy system, lactase is released from the tips of the villi in the small intestine. Using this information, make a prediction for why the damage caused by celiac disease causes problems when a person eats dairy.

Answers

Answer:

Damage to the villi means less lactase released, so the body can't break down dairy.

Explanation:

If the small intestine is damaged, then that can mean that the villi are damaged. The villi usually release lactase, so this process will be compromised.

Less lactase released means that the body will have less of the enzyme required to break down lactose, the sugar present in dairy. Thus, individuals with celiac disease will struggle to digest dairy products

A mutation is found in a tRNA-encoding gene. The wild type allele produces a tRNA that recognizes the codon GAA, and is charged with the amino acid Glutamic acid. The mutant tRNA is still charged with Glu, but the anticodon is mutated such that it recognizes the codon UAA. What effect will this have on translation in these cells

Answers

Answer:

It will bring about a stop to the translation process

Explanation:

The mutant tRNA despite still being charged with Glu, since it's anticodon is mutated and then recognizes and reads the codon UAA which is one of the  stop codons (UAA, UAG and UGA) on the mRNA strand causes the translation process of that particular mRNA strand to stop. And the growing polypeptide chain to be released if any from the ribosomes.

Answer:

The anticodon will be unable to recognize the mRNA codon that is GAA, and the translation of this protein/polypeptide will be abruptly stopped. This may result in a truncated protein which is defected and hence, will be degraded by the relevant mechanisms in place. Since, UAA is actually one of the stop codons, the ribosome will not continue onward with the translation and fall off the mRNA.

Hope that answers the question, have a great day!

Pattern of evolution in which long stable periods (stasis) are interrupted by brief periods of rapid change

Answers

Answer:

punctuated equilibrium

What makes ribosomal RNA useful as a molecular clock? (2 points) A large portion of the DNA ring is not vital to structure or function, allowing it to accumulate neutral mutations. Its rate of mutation increases over time as organisms continue to evolve and differentiate from each other. A slow mutation rate makes it useful for determining evolutionary relationships between ancient species. It is only found in select organisms, making it easier to compare relationships between species that have it.

Answers

Answer:

The correct statement is that a slow mutation rate makes it useful for determining evolutionary relationships between ancient species.

Explanation:

The rRNA or ribosomal RNA has an application as a molecular clock because of many factors. It exhibits a very slow mutation rate, that is, around one million years because of which it stays highly conserved in all the organisms. In the ribosomal RNAs of two organisms, the degree of mutations can be associated directly with the time they were originated in the past.  

In supplementation, it possesses essential biological function because of which it can be witnessed in almost all the species.  

Answer:

A slow mutation rate

Which of the following statements about hormone transport and distribution is not true? a. free hormone concentration is not influenced by plasma protein concentration b. hormones bind to certain types of plasma proteins c. hormones can be transported bound to plasma protein or free in the plasma d. only free hormones can diffuse through capillary walls and bind to target tissues e. All of the statements are true.

Answers

E . all of the statements are true hope i’m correct