A straight horizontal line on a speed-time graph means the speedis constant. This means the speed is not changing over time.
How is this different from a distance-time graph?​

Answers

Answer 1
Answer:

Answer:

its devavtion is different from the distance changes process

Explanation:

Answer 2
Answer:

Final answer:

A speed-time graph and a distance-time graph represent different aspects of motion. A horizontal line on the former indicates a constant speed (zero acceleration), while a straight, upward-diagonal line on the latter shows constant speed. A flat horizontal line on a distance-time graph shows no movement.

Explanation:

A speed-time graph and a distance-time graph each depict different aspects of motion. A horizontal line on a speed-time graph does indeed indicate constant speed or zero acceleration; the object is moving at a constant speed. However, a distance-time graph shows how the position of the object changes over time.

Let's take an example. If a car is traveling at a constant speed, on a speed-time graph, this would be represented by a horizontal line. The height of the line above the time axis represents the constant speed.

On a distance-time graph, a car moving at constant speed will be represented by a straight line with a positive slope. This is because the position of the car is continuously changing (it's covering distance), and at a constant rate. The slope of the distance-time graph gives us the speed of the car.

So, while a flat horizontal line in a speed-time graph indicates constant speed, a flat horizontal line in a distance-time graph would indicate no change in position, i.e., the object is not moving at all.

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Answers

Answer: it's environment

Explanation:

An organism's overall behavior is a combination of its heredity and its environment. For example, both Krista and Blaire inherited a fear of thunder. They deal with this fear differently, however, because of differences in their environment.

Answer:

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Explanation:

Images at home that represent conduction convection and radiation

Answers

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Label the parts of the brain. medulla oblongata thalamus cerebrum cerebellum brain stem pons hypothalamus midbrain

Answers

Answer:

Medulla oblongata is lower part of brain.

Cerebrum and cerebellum are the upper hemispheres of the brain.

Explanation:

Cerebrum is the largest part of the brain and is composed of right and left hemispheres.

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Brain stem act as relay center connecting the cerebrum and cerebellum to the spinal chord.

Hypothalamus is the mid brain located near the pituitary glands. It is very small region of the brain but it plays an important role in maintaining the body temperature and releasing the hormones.

Answer:

Medulla oblongata: The bottom part of the brainstem helps regulate your breathing, heart rhythms, blood pressure and swallowing.

Explanation:

Two spheres exert a gravitational attraction on each other. Which of the following changes to this system would reduce the gravitational attraction by one half?

Answers

- Decreasing one of the masses to 1/2 of its original value

- Increasing the distance by a factor of √(2)

Explanation:

There are no options provided, however we can still answer the question.

In fact, the magnitude of the gravitational force between two objects is given by  the equation:

F=G(m_1 m_2)/(r^2)

where

G=6.67\cdot 10^(-11) m^3 kg^(-1)s^(-2) is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between them

We notice that:

  • The gravitational force is proportional to the product between the masses
  • The gravitational force is inversely proportional to the square of the distance between the masses

Therefore, in order to reduce the gravitational attraction by one half, we can do one of the following changes:

- Decreasing one of the masses to 1/2 of its original value: for example, if m_1'=(1)/(2)m_1, the gravitational force becomes

F'=G(m_1' m_2)/(r^2)=G((1)/(2)m_1m_2)/(r^2)=(1)/(2)(G(m_1m_2)/(r^2))=(1)/(2)F

- Increasing the distance by a factor of √(2): in fact, if r'=√(2)r, the gravitational force becomes

F'=G(m_1 m_2)/(r'^2)=G(m_1m_2)/((√(2)r)^2)=(1)/(2)(G(m_1m_2)/(r^2))=(1)/(2)F

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Answers


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