Geothermal energy cannot meet all of our energy needs because access to geothermal energy is _________.a. limited to certain regions.
b. the earth is not hot enough.
c. geothermal energy is intermittent.
d. geothermal sources do not have enough energy to generate electricity

Answers

Answer 1

Answer:

Answer:

a. Limited to certain regions.

Explanation:

It will be wrong to say that the earth is not hot enough, geothermal energy is intermittent or this source is not enough to generate electricity. It is not the fuel, it's the earth which is continuously emitting radiation or heat and it will keep on emitting that. So it's the most consistent source of energy and is abundant enough to produce electricity. So the problem is, it's the location specific source of energy and can only be utilized at the places lying at the edges of the tectonic plates. So the correct option is a.

Answer 2

Answer:

B. Electrical energy

Among the choices given, the type of energy associated with electric currents is electrical energy. By its definition, electric current is the flow of charged particles through a conductor or a conduction medium, for example, a wire. Basically, it involves electricity. It is similar to water current but instead of water molecules, charged particles move down a conductor. These charged particles are mostly electrons which move freely and at random. When all the free electrons move in the same direction, a current is created.

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consider the following scenario: you live near the shoreline and hear a report that an earthquake hit the ocean floor near your location. your town may experience

Answers

Tsunamis because earthquakes caused in or near water and the energy creates massive waves

Which of the following types of energy originates below Earth's surface?A. electrical energy
B. geothermal energy
C. mechanical energy
D. electromagnetic energy

Answers

Geothermal energy. Electromagnetic energy originates at the sun (think UV rays; they are part of the electromagnetic spectrum). Electrical energy technically can be anywhere, as long as there are positive and negative charges. Mechanical energy is like a generator or an engine; there is always something working to get things done/made. I hope this answer and these explanations helped!

Type 2 diabetes accounts for _______ percent of all cases of diabetes

Answers

Type 2 diabetes is a common and illness that is largely preventable. In adults, types about 90 to 95 percent of all diagnosed cases of diabetes; the remainder are adult-onset (or adult-diagnosed) type 1 diabetes, a form of diabetes for which the cause is unknown

90-95 Percent, (I took the test and got an 100).

A machine uses a force of 200 newtons to do 20,000 joules of work in 20 seconds. Find the distance the object moved and the power of the machine.

Answers

work=force * distance
20,000 joules= 200 newtons * d
divide both sides by 200

100= distance

A hobo hops a freight train traveling at 2.5 m/s due east. The man boards the train from the rear of the boxcar and walks from the southwest corner to the north east corner of the car at a rate of 5.0 m/s. The boxcar is 15 meters long and 3 meters wide. What is the velocity of the man relative to the train tracks?

Answers

Since it isn't specified, I have to assume that when he's walking inside, along
the diagonal of the car, at 5m/s, that speed is relative to the floor of the car.
The reason I have to assume that is because I think it makes the problem
easier. I could be wrong. And it's still troubling, because 5 m/s is a hefty
11.18 mph, which is a pretty energetic walk. (In fact, it's a 5min 22sec mile,
which I for one never accomplished, even when I was running.) But so be it.

-- The length of the car's diagonal is √(3² + 15²) = √(9 + 225) = √334

-- The angle of his walk along the diagonal is the angle whose tangent is 3/15.

-- His velocity consists of the components [ 5 cos(angle) east ] and
[ 5 sin(angle) north ].

That's [ 5 x 15/√334 east ] and [ 5 x 3/√334 ] north .

The train's motion adds to the easterly component of his velocity,
and that becomes [ (2.5) + (5 x 15/√334) ] . The train's motion has
no effect on the northerly component of his velocity.

So now we're ready to put the components together and find his velocity
relative to the tracks. I think it'll be easier to go ahead and get the numerical
value of each component, and then combine them.

Easterly component: (2.5) + (5 x 15/√334) = 6.6038 m/s

Northerly component: 5 x 3/√334 = 0.8208 m/s

Just before finding the magnitude, we note that the direction of his velocity
is (the angle whose tangent is 0.8208/6.6038) north of east. That's about
7.085 degrees north of east ...the compass bearing of 82.92 degrees.

Now for the magnitude. It's the square root of the sum of the squares of
the easterly component and the northerly component.

√ (6.6038² + 0.8208²) = √44.2841 = 6.655 m/s

(All numbers are rounded.)

That's my story, and I'm sticking with it.

Which is a chemical change