Which one of the following temperatures is equal to 5°C? A. 465 K
B. 0 K
C. 41 K
D. 278 K

Answers

Answer 1
Answer:

Answer : The correct option is, (D) 278 K

Explanation :

We are given temperature 5^oC.

Now the conversion factor used for the temperature is,

K=^oC+273

where, K is kelvin and ^oC is Celsius.

Now put the value of temperature, we get

K=5^oC+273=278K

Therefore, the temperature 278 K is equal to the 5^oC



Related Questions

What should you do if the exercise schedule you make for yourself is not working out well by midweek?
Which statement best explains the relationship between the electric force between two charged objects and the distance between thema) As the distance increases by a factor, the electric force increases by the square of that factor. b) As the distance increases by a factor, the electric force increases by twice that factor. c) As the distance increases by a factor, the electric force decreases by twice that factor. d) As the distance increases by a factor, the electric force decreases by the same factor. e) As the distance increases by a factor, the electric force decreases by the square of that factor.
Examples of the period, frequency, speed of a wave in a sentence?
The Sun emits a lot of radiation. The different types of radiation are the electromagnetic spectrum. Which of the following wave types are part of the spectrum?
What fuel(s) are the main energy source during short, intense bursts of exercise?Metabolism of protein onlyMetabolism of fat onlyMetabolism of carbohydrate onlyCarbohydrates and vitaminsCaffeineMedium-chain triglyceridesErythropoietinCarnitine

In scientific terms, how is power related to work? A.Power is the ability to do work.


B.Power is the force of work over a certain distance.


C.Power is the rate at which work is accomplished.


D.Power is the energy supplied in a force.

Answers

C. the rate at which work is done. hope i helped!

What is the total magnification of a microscope with two lenses when one lenses has a magnification of 15 and the other lens has magnification of 30- 15

- 30

- 45

- 450

Answers

Answer:

45 easy and if u ever need anything holla

At 400 K, a volume of gas has a pressure of 0.40 atmospheres. What is the pressure of this gas at 273 K?

Answers

The pressure of the sample of gas at 273 K is equal to 0.273 atm assuming the volume is constant.

What is Gay Lussac's law?

Gay-Lussac's law can be described as that when the volume of the gas remains constant then the pressure (P) of the gas and the absolute temperature (T) in a direct relationship.

Gay Lussca's law can be  described as mentioned below:

P/T = k

The pressure of gas is directly proportional to absolute temperature of the gas.

P ∝ T                               ( Volume of gas is constant)

or,    P₁/T₁ = P₂/T₂                                            .................(1)

Given, the initial temperature of the gas, T₁ = 400 K

The final temperature of the gas, T₂ = 273 K

The initial pressure of the gas, P₁ = 0.40 atm

The final pressure of the given gas can be calculated from Gay Lussac's law as:

\displaystyle P_2 =(P_1)/(T_1)* T_2

P₂ = (0.40/400) ×273

P₂ = 0.273 atm

Therefore, the pressure of this gas at 273 K is 0.273 atm.

Learn more about Gay Lussac's law, here:

brainly.com/question/11387781

#SPJ2

The ratio p/T is constant. So, you'd get 273*0.40/400

Which of the following is a true statement? A) It's easier to lift a heavy weight straight up than to slide it up a ramp. B) When you use a lot of effort, a load becomes lighter. C) When you use a minimum amount of effort, a load becomes heavier. D) When you increase the distance over which effort is expended, you don't have to work as hard.

Answers

Answer:

D) When you increase the distance over which effort is expended, you don't have to work as hard.

Explanation:

This statement reflects one of the principles of mechanical advantage. When you increase the distance over which effort is applied (in situations like using a lever or a simple machine), it allows you to achieve the same work with less force. It's the concept of trading off force for distance, which is a fundamental principle in physics and mechanics.

How are the types of energy in the electromagnetic spectrum defined? (Points : 3)by their atomic structure

by their color

by their amplitude

by their wavelength

Answers

The energy associated with the electromagnetic spectrum is given by the wavelength of the spectrum.

Further Explanation:

The electromagnetic waves are the waves which travel through the space and do not require any medium for their propagation. The Electromagnetic waves are the waves which are transverse in nature.

There are several waves of various wavelength and frequency present in the Electromagnetic spectrum. The different waves present in the electromagnetic spectrum are:

  • Gamma rays.
  • X-rays.
  • Ultraviolet rays.
  • Visible rays.
  • Infrared rays.
  • Micro waves.
  • Radio waves.

The wavelength and the frequency of the electromagnetic waves are the key properties of the wave which describe several other parameters of the waves like intensity, power, energy of the wave etc.

The energy associated with the electromagnetic radiation is given by:

 E=\frac{{hc}}{\lambda}

Here, E  is the energy of the radiation, h  is the plank’s constant, c  is the speed of the light and \lambda  is the wavelength of the radiation.

Therefore, the above expression shows that the energy of the electromagnetic spectrum depends on the wavelength of the spectrum.

Thus, Option (d) is correct. The energy of the electromagnetic spectrum is defined by their wavelength.

Learn More:

1. What is the threshold frequency ν0 of cesium brainly.com/question/6953278

2. Calculate the wavelength of an electron (m = 9.11 × 10-28 g) moving at 3.66 × 106 m/s brainly.com/question/1979815

3. What is the kinetic energy of the emitted electrons when cesium is exposed to UV rays brainly.com/question/9059731

Answer Details:

Grade: High School

Subject: Physics

Physics: Electromagnetic spectrum

Keywords:

Electromagnetic spectrum, energy, frequency, wavelength, radiation, speed of light, defined by their wavelength, E=hc/lamda, waves, transverse nature.

The correct answer to the question is : C) By their wavelength

EXPLANATION:

Before going to answer this question, first we have to understand the electromagnetic spectrum.

An electromagnetic wave is the transverse wave which contains time varying electric field and magnetic field which are perpendicular to each other as well as perpendicular to the direction of propagation.

There are various electromagnetic waves which are named as gamma ray, X-ray, U.V ray, visible light, infrared wave, micro wave and radio waves respectively. Out of these waves, only visible light can be visualized by human eye.

Every electromagnetic wave is characterized by its wavelength. Different waves have different range of wavelength.

The electromagnetic spectrum is the the arrangement of electromagnetic waves either in ascending order of wavelength or in descending order.

The gamma ray has the minimum wavelength in the spectrum, and radio wave has the maximum wavelength.

The energy carried by electromagnetic waves having wavelength \lambda is calculated as-

                  Energy = (hc)/(\lambda)

Here, c is the velocity of light and h is the Planck' s constant.

Hence, the correct answer to the question is wavelength which will signify the energy of different types of electromagnetic waves.


The Otto-cycle engine in a Mercedes-Benz SLK230 has a compression ratio of 8.8.Part A. What is the ideal efficiency of the engine? Use γ=1.40.
Part B. The engine in a Dodge Viper GT2 has a slightly higher compression ratio of 9.6. How much increase in the ideal efficiency results from this increase in the compression ratio?

Answers

Answer:

58.1%

59.533%

1.433%

Explanation:

(V_1)/(V_2) = Compression ratio

\gamma = Specific heat ratio = 1.4

Efficiency in the Otto cycle is given by

\eta=1-(1)/(\left((V_1)/(V_2)\right)^(\gamma-1))\n\Rightarrow \eta=1-(1)/(\left(8.8\right)^(1.4-1))\n\Rightarrow \eta=0.581

The ideal efficiency of the engine is 58.1%

\eta=1-(1)/(\left((V_1)/(V_2)\right)^(\gamma-1))\n\Rightarrow \eta=1-(1)/(\left(9.6\right)^(1.4-1))\n\Rightarrow \eta=0.59533

The ideal efficiency of the engine is 59.533%

Increase in efficiency is 59.533-58.1 = 1.433%