What is a newton equal to in terms of units of mass and acceleration?

Answers

Answer 1
Answer: 1 newton =
     the force that accelerates 1 kilogram of mass at the rate of 1meter per sec²

1 N = 1 kg-m/s²
Answer 2
Answer: 1N= force needed to accelerate 1kg object to speed of 1m/s2

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Determine the mass percent (to the hundredths place) of h in sodium bicarbonate (nahco3).

A 1200 kg vehicle initially travelling at 50. km/h experiences an air resistance of 5000 N and road friction of 2200 N. The wheels deliver a force of 7500 N to the vehicle. What is its acceleration?

Answers

The forces on the car are:
-- 7,500 N forward, from the engine
-- 5,000 N backwards, from air resistance
-- 2,200 N backwards, from road friction

The net force on the car is (+7,500 - 5,000 - 2,200) = 300 N forward .

Newton said: Force = (mass) x (acceleration)
Divide each side by (mass) :
Acceleration = (force) / (mass)

Acceleration = (300 N) / (1,200 kg) = 0.25 m/s² forward.

Notice the big red herring at the beginning of the question:
It's nice to know that the vehicle starts out traveling at 50 km/hr,
but in order to answer this question, we honestly don't care !

A baseball player runs 27.4 meters from thebatter’s box to first base, overruns first base by
3.0 meters, and then returns to first base.
Compared to the total distance traveled by the
player, the magnitude of the player’s total
displacement from the batter’s box is
(1) 3.0 m shorter (3) 3.0 m longer
(2) 6.0 m shorter (4) 6.0 m longer

Answers

Distance is a measure of the length of space covered over a certain period of time. While displacement is the change in position of an object from its starting point. Displacement is 6.0 meters shorterthan distance.

  • Starting position = batter'box

  • Batter's box to first base = 27.4 meters

  • Distance beyond first base = 3 metres

  • Final position = first base

Total distance covered :

(Batter's box - > first base) + (beyond first base) + (return to first base)

  • (27.4 + 3 + 3) = 33.4 meters

Total Displacement :

(Batter's box - > first base) + (beyond first base) - (return to first base)

  • (27.4 + 3 - 3) = 27.4 meters

Difference in magnitude of Distance and Displacement :

  • 33.4 - 27.4 = 6.0 meters

Therefore, displacement is 6m shorter

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Answer:

(2) 6.0 m shorte.

Explanation:

Total distance = Distance from batter’s base to first base + Distance covered in overrunning + Distance covered in returning to first base  

Total Distance = 27.4 + 3 + 3 = 33.4 m

Total displacement = Displacement from batter’s base to first base + Displacement covered in overrunning + Displacement covered in to returning first base  

The 2nd and 3rd term will have same magnitude but opposite direction so, they will cancel out each other. Hence,  

Total Displacement = 27.4 m  

Hence, displacement will be 6.0 m shorter than distance.

How is the Maunder minimum related to climate? a. Unusually low sunspot activity correlates to unusually cold climatic events.
b. The Maunder minimum is unrelated to climate.
c. Changes in the Earth’s tilt correlate to changes in climate.
d. Changes in the Earth’s orbit correlate to changes in climate.

Answers

Maunder minimum is related to climate due to the unusually low sunspot activity correlates to unusually cold climatic events. The answer is letter A. It happened around 1645 and 1715 and also coincided with the phenomena ‘Little Ice Age’ (1500 – 1850) in the Northern Hemisphere.

The Nazca Seafloor Plate Pushes Into The South American Continental Plate. What Is The Most Likely Result?

Answers

the Nazca plate will move under the south american plate. i know its late but it will help others!

A typical carbon atom has six protons, six neutrons, and six electrons. Which of these has the least amount of mass?A) one Proton
B) one Neutron
C) six Electrons
D) These masses are too tiny to measure

Answers


One proton or one neutron have very close to the same mass.

Their mass is about the same as the mass of 1,840 electrons !
So six electrons have roughly the same mass as 0.0033 of one
proton or one neutron.

Yes, these masses are very tiny.  None of them was ever measured
until the 20th Century.  But all of them have now been measured,
very precisely and accurately.  This is very impressive, and should
give us a lot of admiration for scientists of the past hundred years.
It would be very interesting to look around online and find out
how they did it.

4. Two cars are travelling along a straight road, as shown below. The pass each other at pointB and then continue in opposite directions. The red car travels for 0.25 hours from point B
to point C at a constant velocity of 32 km/hr east. The blue car travels for 0.25 hours from
points B to point D at a constant velocity of 48 km/hr. How far has each car traveled from
point B? What is the position of each car relative to the origin, point A?

Answers

Using the speed - time relation, the distance moved by the cars from point B are 8 kilometers and 12 kilometers respectively.

Distance of car 1from Point B :

  • Speed of car × time traveled from point B

Distance traveled from point B = 32 × 0.25 = 8km

Distance of car 2from Point B :

  • Speed of car × time traveled from point B

Distance traveled from point B = 48 × 0.25 = 12km

The diagram isn't attached, hence question 2 cannot be answered accurately.

Therefore, the distance traveled from point B by car 1 and 2 is 8km and 12 km respectively.

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Final answer:

The red car has traveled 8 km east of point B, while the blue car has traveled 12 km west of point B.

Explanation:

To determine how far each car has traveled, we need to use the formula: distance = speed × time. The red car travels for 0.25 hours at a constant velocity of 32 km/hr, so the distance it travels is: distance = 32 km/hr × 0.25 hr = 8 km. The blue car travels for the same amount of time at a constant velocity of 48 km/hr, so the distance it travels is: distance = 48 km/hr × 0.25 hr = 12 km.

The position of each car relative to the origin, point A, is as follows: The red car is 8 km east of point A (since its velocity is in the east direction). The blue car is 12 km west of point A (since its velocity is in the opposite direction to the east).

Learn more about Calculating distances and positions of two cars here:

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