A bacteria culture is initially 10 grams at t=0 hours and grows at a rate proportional to its size. After an hour the bacteria culture weighs 11 grams. At what time will the bacteria have tripled in size?

Answers

Answer 1
Answer:

A bacteria culture is initially 10 grams at t=0 hours & grows at a rate proportional to its size , After an hour the bacteria culture weighs 11 grams , The bacteria takes 11.56 hours to have tripled in size.

To find the time of bacteria when increasing the growth to tripled.

Given :    when time=0 hours , weight=10 grams.

               when time=1  hours , weight=11 grams.

To find:   when time= ? hours , weight=30grams.

Here according to question, initial size = 10 grams we have asked for tripled in size i.e. 30 grams.

Now we knows that,

The formula for exponential growth in population or size is

              \rm (P)=P_0e^(rt)  where,

               \rm P_0=initial\;size\n\nr= rate\;of\;growth\n\nt= time \;period

Now, we put the value in formula we get,

\rm P_0=10\;grams \n\nwhen ,\n\;\;t=1\;hour P(t)=11 grams\nThen,\n11=10e^{r(1)\n1.1 =e^r\n\n\rm Taking \;log(natural)\;both\;the\; side \;on \;solving\;we\;get,\nln(1.1)=r\;ln(e)\nr=ln(1.1)\nr=0.953101798043\approx0.095

Now when the bacteria increase its size to triple

\rm P(t) = 3 * 10 = 30

Then, according to the formula we substitute values in the formula,

\rm 30=10e^(0.095t)\n\n3=e^(0.095t)\n\nAgain \;we \;take\;natural\;log\;on \;both\;the\;sides, we\;get\nln\;3=0.095t\n\nt=(\rm ln\;3)/(0.095)\n\n\n\n\rm t= (1.09861228867)/(0.095) \n\n\ t=approx \; 11.56

Therefore, The bacteria takes 11.56 hours to have tripled in size.

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Answer 2
Answer:

Answer: It will take 11.56 hours .

Step-by-step explanation:

Exponential growth in population or size formula :

P(t)=P_0e^(rt)

, where P_0 = initial size

r= rate of growth

t= time period

As per given , we have

P_0=10 grams

At t= 1 , P(t)= 11 grams

Then,

11=10e^(r(1))\n\n 1.1= e^r\n\n\text{Taking natural log on both sides , we get} \n\n\ln (1.1)=r\ln (e)\n\n r=\ln (1.1)\n\n r=0.0953101798043\approx0.095

When, the  bacteria have tripled in size , P(t) = 3 x10 = 30

Then,

30=10e^(0.095t)\n\n 3=e^(0.095t)

\text{Taking natural log on both sides , we get}\n\n \ln 3=0.095t\n\n t=(\ln3)/(0.095)\n\n t=(1.09861228867)/(0.095)\approx11.56

Hence, it will take 11.56 hours .


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