CHEMISTRY HIGH SCHOOL

What is the empirical formula of C7H14?

Answers

Answer 1
Answer:

Answer:

Explanation:

C7H14 has 3 isomers. Cycloheptane, methylcyclohexane and heptene all share the same formula.
Answer 2
Answer:

Final answer:

The empirical formula of C7H14 is C7H14.

Explanation:

The empirical formula of C7H14 is C7H14. An empirical formula represents the simplest ratio of elements in a compound. In this case, there are 7 carbon (C) atoms and 14 hydrogen (H) atoms. The ratio between the two elements is 1:2, so the empirical formula is C7H14.

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An electron has a charge ofA. –1 and the same mass as a proton
B. +1 and the same mass as a proton
C. –1 and a smaller mass than a proton
D. +1 and a smaller mass than a proton

Answers

The correct answer is C. An electron has a charge of -1 and a smaller mass than a proton. Proton has the same mass with the neutron. The ratio between the mass of a proton and an electron is about 2000. An electron has an equal value but negative charge with the proton.

You are on an alien planet where the names for substances and the units of measures are very unfamiliar. Nonetheless, you obtain 69 quibs of a substance called skvarnick. You can trade this Skvarnick for gold coins, but the vendors all measure skvarnick units of sleps; not quibs. 9 sleps is equal to 6 quibs. If you have 14 quibs of skvarnick, how many sleps do you have? Round your answer to the nearest tenth (one decimal place). Type only the number; not the number and unit.

Answers

Answer: 21 sleps

Explanation:

Given information: The substance skvarnick can be traded for gold coins in units of sleps and not quibs. Thus we need to convert the units of quibs to sleps.

It is given that 9 sleps is eqaul to 6 quibs, 14 quibs = ____ sleps.

6\text{ quibs} = 9\text{ sleps}

14\text{ quibs} = (9)/(6)* {14}\text{ sleps}

                       =21\text{ sleps}

What is the ph of a solution with [H+]=3.3x10

Answers

pH=-log[H⁺]

That means that the pH=-log(3.3×10)=-1.52

I hope this helps.  Let me know if anything is unclear.

Would the following errors increase, decrease, or have no effect on the calculated moles of gas collected in the experiment? Explain your answers in complete sentences.a) The measured mass of the magnesium was smaller than the true mass.
b) The actual temperature of the hydrogen gas is less than room temperature.

Answers

a. If the actual mass of Magnesium used was larger then the measured and the amount of gas produced should be greater
b. when gas was cooler than its surroundings its density would be greater and the volume would appear to be smaller. This is because the gas molecules are very active and when heated they will expand.
so they both bound increase the calculated moles of gas collected in the experiment

How many grams of KClO3 are needed to produce of 4.26 moles of O2? 2 KClO3 2 KCl + 3 O2 a. 348 g b. 136 g c. 174 g d. 522 g e. 783 g

Answers

Answer:

The answer is c. 173 g

Explanation:

You know the reaction :

KClO3 ⇒ 2 KCl + 3 O2

By stoichiometry, that is, the amount of reagents and products in a chemical reaction when it is balanced (as in this case), it is known that for 2 moles of O2, 1 mole of KCLO3 is needed. So you can do the following rule of three to know the number of moles to produce 4.26 moles of 02:

If 1 mole of KClO3 is necessary to produce 3 moles of O2, how many moles are needed to produce 4.26 moles of 02?

(4.26moles 02*1 mol KClO3)/(3 moles O2) = 1.42

So you need 1.42 moles of KClO3

Now it is necessary to know the molar mass of KClO3, which is the mass that contains 1 mole of the substance. For that you need to know the mass of K, Cl and O:

  • K: 39 g/mol
  • Cl: 35.45 g/mol
  • O:  16 g/mol

So, the molar mass of KClO3 is:

39 g/mol + 35.45 g/mol + 3*16 g/mol=122.45 g/mol

because it contains 1 atom of K, 1 atom of Cl and 3 atoms of O.

Now, to calculate the mass representing 1.42 moles of KClO3 (needed to produce 4.26 moles of O2) you simply multiply that amount of moles by the molar mass:

1.42moles*122.45(g)/(mol) =173.88 g

This means that approximately 174 g of KClO3 are necessary to produce 4.26 moles of O2.
Ok so this is what we know :

2KClO3 -> 2KCl + 3O2         (Always check if equation is balanced - in this                                               case it is)
                              4.26moles
So we know that we have 4.26 moles of oxygen (O2). Now lets look at the ratio between KClO3 and O2.
We see that the ratio is 2:3 meaning that we need 2KClO3 in order to produce 3O2.
Therefore divide 4.26 by 3 and then multiply by 2.
4.26/3 = 1.42
1.42 * 2 = 2.84
Now we know that the molarity of KClO3 is 2.84 moles.
Multiply by R.M.M to find how many grams of KClO3 we have.

R.M.M of KClO3
K- 39
Cl- 35.5
3O- 3 * 16 -> 48
---------------------------
                      122.5
2.84 * 122.5 = 347.9 grams therefore the answer is (a)
                       348 grams needed of KClO3 to produce 4.26 moles of O2.
Hope this helps :).

Which equation represents a change that results in an increase in disorder?

Answers

This equation represents a change that results in an increase in disorder I2(s)=>I2(g).
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