A solution is prepared by dissolving 91.7 g fructose in 545 g of water. Determine the mole fraction of fructose if the final volume of the solution is 576 mL.

Answers

Answer 1
Answer:

Answer:

Mole fraction = 0,0166

Explanation:

Mole fraction is defined as mole of a compound per total moles of the mixture. In the solution, the solute is fructose and the solvent is water. That means you need to find moles of fructose and moles of water.

The molecular mass of fructose is 180,16g/mol and mass of water is 18,02 g/mol. Using these values:

91,7g fructose × (1mol / 180,16g) = 0,509 moles of fructose

545g water × (1mol / 18,02g) = 30,24 moles of water

Thus, mole fraction of fructose is:

(0,509 moles)/(0,509mol + 30,24mol) = 0,0166

Mole fraction = 0,0166

I hope it helps!


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What is the pH of a solution with [H+] = 1.25 mc015-1.jpg 10–10 M?

Answers

Answer : The pH of a solution is, 9.903

Explanation : Given,

Concentration of hydrogen ion = 1.25* 10^(-10)M

pH : It is defined as the negative logarithm of hydrogen ion concentration.

Formula used :

pH=-\log [H^+]

Now put the value of hydrogen ion concentration in this formula, we get the pH of a solution.

pH=-\log (1.25* 10^(-10))

pH=9.903

Therefore, the pH of a solution is, 9.903

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[H+]=0.1

What is a solution for deforestation



(full sentences please)

Answers

The best solution to deforestation is to curb the felling of trees by enforcing a series of rules and laws to govern it. Deforestation in the current scenario may have reduced; however, it would be too early to assume. The money-churner nature of forest resources can be tempting enough for deforestation to continue.

The best solution to deforestation is to curb the felling of trees by enforcing a series of rules and laws to govern it. Deforestation in the current scenario may have reduced; however, it would be too early to assume. The money-churner nature of forest resources can be tempting enough for deforestation to continue.

Considering the law of conservation of mass, if 56 g samples of solid iron (Fe) reacts with 24 g of oxygen (O2), how many grams of Iron Oxide (FeO) are obtained?

Answers

Answer:

62_grams of FeO

Explanation:

Molar mass of Fe = 55.845_g/mol

Molar mass of O2 = 15.999_g/mol

From law of conservation of mass

2 moles of Fe combines with one mole of O2 to form 2 moles of FeO

Number of moles of Fe and O2 present = mass/(molar mass) = 56/55.845~1

and 24/16 = 1.1.5

Therefore

1 part of Fe will react with 0.5 part of one mole of O2

which is 54_g of Fe reacts with 8_g to form 54+8 = 62_grams of FeO

Solids, liquids, and gases can be distinguished by their

Answers

The three states of matter are solid, liquid and gas phase. The solid has a more definite shape and volume. The particles are locked into place. It cannot be further compressed due to the bond that exists between the molecules. The kinetic energy of the molecules is close to none because the molecules are so close and so compact with each other. For liquids, it has a medium shape and volume. The particles can move or slide past each other due to the small space available for movement. It cannot be compressed further due to the repulsive forces that acts between them. The kinetic energy is medium. For gases, it has no shape and volume because the particles can move freely from one other. Their collisions are rare due to the distance between them. The kinetic energy of the molecules is high because there is room for movement. It can be compressed easily.

Mark and Ann took a two week hiking trip through Yosemite National Park. While hiking through the park they witnessed two large blocks of rock break away from Glacier Point. What is the initial transfer of energy that accelerates the rock down the side of the mountain?

Answers

Potential energy. The energy you gain when it is at rest. 

Potential energy is converted into kinetic energy.

In which process does a solid change directly into a vapor?(1) condensation (3) deposition
(2) sublimation (4) solidification

Answers

In Sublimation, a solid changes directly into a vapor.