In a charging process, 4 × 1013 electrons are removed from one small metal sphere and placed on a second identical sphere. Initially, both metal spheres were neutral. After the charging process, the electrical potential energy associated with the two spheres is found to be −0.063 J. What is the distance between the two spheres?
Answers
Answer:
The distance between the two spheres is 914.41 X 10³ m
Explanation:
Given;
4 X 10¹³ electrons, and its equivalent in coulomb's is calculated as follows;
1 e = 1.602 X 10⁻¹⁹ C
4 X 10¹³ e = 4 X 10¹³ X 1.602 X 10⁻¹⁹ C = 6.408 X 10⁻⁶ C
V = Ed
where;
V is the electrical potential energy between two spheres, J
E is the electric field potential between the two spheres N/C
d is the distance between two charged bodies, m
where;
K is coulomb's constant = 8.99 X 10⁹ Nm²/C²
d = (8.99 X 10⁹ X 6.408 X 10⁻⁶)/0.063
d = 914.41 X 10³ m
Therefore, the distance between the two spheres is 914.41 X 10³ m
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Answer:
1kg
Explanation:
this box is the smallest and weighs the least. Hope this helps :]
Answers
Answer:
Explanation:
Given that,
Frequency of the radio signal,
It is detected at a pint 2.1 km from the transmitter tower, x = 2.1 km
The amplitude of the electric field is, E = 800 mV/m
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So, the intensity of the radio signal at that point is . Hence, this is the required solution.
Answers
Explanation:
The reason for the more concentration of carbon dioxide in the atmosphere of Venus than in the Earth -
On the Earth , most amount of the carbon dioxide is in the ocean water and in sea sediments .
Considering Venus , in the planet Venus , there is no Ocean water , hence , carbon dioxide can not get dissolved into the water , hence , it is found in the atmosphere .
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Answers
Answer:
Explanation:
Magnetic moment of current carrying loop
= current x area
= 2 x π x .1²
M = .0628 unit . it is in j direction so vecor form of it
M = .0628 j
Magnetic field B = 3i + 4 j
Energy
= - M.B
- .0628 j . ( 3i + 4 j )
= - .2512 J
Answers
7 true
8 false
9 false
10 false
11 false
12 true
13 true
hope this helps!
Answers
Answer:
T1 = 499.9N, T2 = 865.8N, T3 = 1000N
Explanation:
To find the tensions we need to find the vertical and horizontal components of T1 and T2
T1x = T1 cos60⁰, T1y = T1 sin60⁰
Also, T2x = T2 cos30⁰, T2y = T2 sin30⁰
For the forces to be in equilibrium,
the sum of vertical forces must be zero and the sum of horizontal forces must also be zero
Sum of Fx = 0
That is, T1x - T2x=0
NB: T2x is being subtracted because T1x and T2x are in opposite directions
T1 cos60⁰ - T2 cos30⁰ = 0
0.866T1 - 0.5T2 = 0 ............ (1)
Sum of Fy = 0
T1y + T2y - 1000 = 0
T1 sin60⁰ + T2 sin30⁰ - 1000 = 0
NB: The weight of the bag of cement is also being subtracted because it's in an opposite direction.
0.5T1 - 0.866T2 - 1000 = 0 ........(2)
From (1)
make T1 the subject
T1 = 0.5T2/0.866
Substitute T1 into (2)
0.5 (0.5T2/0.866) - 0.866T2 = 1000
(0.25/0.866)T2 - 0.866T2 = 1000
0.289T2 - 0.866T2 = 1000
1.155T2 = 1000
T2 = 865.8N
Then T1 = 0.5 x 865.8 / 0.866
T1 = 499.9N
T3 = 1000N
NB: The weight of the bag is the Tension above the rope, which is T3