A local ice hockey pond is at 4°C when the air temperature falls, causing the water temperature to drop to 0°C with 10.9 cm of ice forming at the surface at a temperature of 0°C. How much heat was lost if the unfrozen pond is 1 m deep and 50 m on each side?

Answers

Answer 1
Answer:

Answer: 114.4 GJ

Explanation:

Heat loss Q=U×A×ΔT

Heat loss of size A is determined by the U value of materials and the difference in temperature.

From 10.9cm from the ice

50m= 5000cm

A= 5000×5000

Q== (10.9) (5000) (5000)(4.184)(1×4 + 80)

Q = 95,771,760,000J

Q≈ 95.8 GJ

Linear gradient from the bottom of the pond to the ice:

Q = (89.1)(5000)(5000)(4.184)(1*2)

Q = 18,639,720,000J

Q ≈ 18.6 GJ

Total heat loss:

Q= 95.8GJ + 18.6GJ

Q= 114.4 GJ


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Select the correct answer.Which statement is true if the refractive index of medium A is greater than that of medium B?
A.
O B.
Total internal reflection is possible when light travels from air to medium B to medium A.
Total internal reflection is possible when light travels from medium A to medium B.
Total internal reflection is possible when light travels from medium B to medium A.
D. Total internal reflection is possible when light travels from air to medium A.
E. Total internal reflection is possible when light travels from air to medium B.
C
C.

Answers

Final answer:

If the refractive index of medium A is greater than that of medium B, then total internal reflection is possible when light travels from medium B to medium A.


Explanation:

If the refractive index of medium A is greater than that of medium B, then total internal reflection is possible when light travels from medium B to medium A.


Learn more about Refraction of light

We know we have exerted of force even when we have done no work this is called _____

Answers

Answer: The correct answer is zero work done.

Explanation:

Work is said to be done when the object moves through a distance when the force is applied to the object.

If the object does not move a distance even the force is exerted on the object then the work done is zero in this case.

Therefore, when the force is exerted even when no work is done then this is called zero work done.

Final answer:

Force is experienced even when no work is done, such as when pushing against a wall. This is due to the fact that work in physics requires force to be applied over a distance. When no movement occurs, no work is done, yet a force was still exerted.

Explanation:

The concept you're referring to is known as force, a fundamental aspect in Newton's laws of motion. According to Newton's third law, every action has an equal and opposite reaction. So, when you push against a wall, it pushes back with an equal amount of force, even though no movement occurs, and therefore no work is done. This is due to the role distance plays in the calculation of work. In the physics sense, work is done when a force is applied over a certain distance.

This is also tied to the concept of potential energy. For example, when a force causes an object to deform, such as compressing a spring, the work done is stored as potential energy in the object until it is released. Yet, if the object does not move or deform, no work has been done, but a force was still exerted.

Learn more about Force without Work here:

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A 600W toaster, 1200W iron and a 100W bulb are all connected to household 120V circuit. a) find the current drawn by each applianceb) the resistance of the heating element in the iron
c) the total cost of running all of the appliances non-stop for 5 days if the electricity rate is $0.1 per KW-Hr.

Answers

Answer:

(a) %a, 10 A, 0.833 A

(b) 12 ohm

(c) $22.8

Explanation:

Power of toaster, P1 = 600 W

Power of iron, P2 = 1200 W

Power of bulb, P3 = 100 W

V = 120 V

As they are in household circuit, so they are connected in parallel, so the voltage is same for all.

(a) Use the formula P = V x i

Current in toaster, i1 = P1 / V = 600 / 120 = 5 A

Current in iron, i2 = P2 / V = 1200 / 120 = 10 A

Current in bulb, i3 = P3 / V = 100 / 120 = 0.833 A

(b) Resistance of heating element of iron is R2.

V = i2 x R2

120 = 10 x R2

R2 = 12 ohm

(c) Total energy consumed in 24 hours for 5 days

                              = (600 + 1200 + 100) x 24 x 5 = 228000 Wh = 228 KWh

Cost of 1 KWh = $0.1

Cost of 228 KWh = 0.1 x 228 = $22.8

_______________________________

Answer:

(a). Toaster = 5A

Iron = 10A

Bulb = 0.833A

(b). R2 = 12Ω

(c). $ 22.8

_______________________________

Explanation:

Given,

Power of Toaster, P1 = 600W

Power of Iron, P2 = 1200W

Power of Bulb, P3 = 100W

Potential difference = 120V

They all are connected in parallel combination because they all are household circuits so that the voltage is same for all appliances in the circuit.

Solution of(a)

By using the formula of powerwe can find out the current.

P=V×I

Here, power is directly proportional to the potential difference and electric current flowing through the circuit.

[.°.I=P/V]

Here,electriccurrent is inversely proportional to the potential differenceandelectric currentisdirectly proportional topower.

Current in Toaster, I1 = P1/V = 600/120 = 5A

Current in Iron, I2 = P1/V = 1200/120 = 10A

Current in Bulb, I3 = P1/V = 100/120 = 0.833A

Solutionof(b)

Resistance of Heating coil of Iron

By using theformula of Ohm's Law we can find out the resistance of heatingcoil of iron.

V=I×R

Here, the potential difference is directly proportional to the current carrying wire and potential difference is directly proportional to the resistance off the wire present in the Iron.

[.°.R=V/I]

Here, resistance is directly proportional to the potential difference and resistance is inversely proportional to the electric current.

R=V/I

=> R = 120/10

.°. R = 12Ω

Solutionof(c)

Total consumption of Energy in 24 hours for 5 days = (600W + 1200W + 100W) × 24 hours × 5 days

= 228000Wh

= 228kWh

When the cost of 1kWh = $ 0.1

So,

The cost of 228 kWh = $ 0.1 × 228 = $ 22.8

_______________________________

A conducting loop of radius r=0.1 m, carrying a current I=2 A has a magnetic moment \vec{\mu} μ ​ that is entirely in the j-hat direction. The loop is immersed in a magnetic field \vec{B} B = [3 i-hat + 4 j-hat] T. What is the potential energy of the loop in this configuration?

Answers

Answer:

Explanation:

Magnetic moment of current carrying loop

= current x area

= 2 x π x .1²

M  = .0628 unit . it is in j direction so vecor form of it

M = .0628 j

Magnetic field   B = 3i + 4 j

Energy

=  -  M.B

-  .0628 j . ( 3i + 4 j )

= - .2512 J

Inductance is usually denoted by L and is measured in SI units of henries (also written henrys, and abbreviated H), named after Joseph Henry, a contemporary of Michael Faraday. The EMF E produced in a coil with inductance L is, according to Faraday's law, given byE=−LΔIΔt.
Here ΔI/Δt characterizes the rate at which the current I through the inductor is changing with time t.
Based on the equation given in the introduction, what are the units of inductance L in terms of the units of E, t, and I (respectively volts V, seconds s, and amperes A)?
What EMF is produced if a waffle iron that draws 2.5 amperes and has an inductance of 560 millihenries is suddenly unplugged, so the current drops to essentially zero in 0.015 seconds?

Answers

Answer:

Explanation:

E= −L ΔI / Δt.

L = E Δt / ΔI

Hence the unit of inductance may be V s A⁻¹

or volt s per ampere .

In the given case

change in current ΔI = - 2.5 A

change in time = .015 s

L = .56 H

E = − L ΔI / Δt.

= .56 x 2.5 / .015

= 93.33 V .

An electron is moving in the presence of an electric field of 400 N/C. What force does the electron experience?

Answers

Answer:

Explanation:

Given

Electric Field strength E=400\ N/C

charge of electron q=1.6* 10^(-19)\ C

Force on the charge particle is given by

F=qE

F=1.6* 10^(-19)* 400

F=640* 10^(-19)\ N

but this force will be acting in the direction opposite to the direction of Electric field because electron is negatively charged