In the standing broad jump, one squats and then pushes off with the legs to see how far one can jump. Suppose the extension of the legs from the crouch position is 0.55 m and the acceleration achieved during the time the jumper is extending their legs is 1.2 times the acceleration due to gravity, g .How far can they jump? State your assumptions. (Increased range can be achieved by swinging the arms in the direction of the jump.)

Answers

Answer 1
Answer:

Answer:

1.32 m.

Explanation:

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A rocket with a mass of 62,000 kg (including fuel) is burning fuel at the rate of 150 kg/s and the speed of the exhaust gases is 6,000 m/s. If the rocket is fired vertically upward from the surface of the Earth, determine its height after 744 kg of its total fuel load has been consumed. Since the mass of fuel consumed is small compared to the total mass of the rocket, you can consider the mass of the rocket to be constant for the time interval of interest.

Answers

Answer:

h≅ 58 m

Explanation:

GIVEN:

mass of rocket M= 62,000 kg

fuel consumption rate =  150 kg/s

velocity of exhaust gases v= 6000 m/s

Now thrust = rate of fuel consumption×velocity of exhaust gases

=6000 × 150 = 900000 N

now to need calculate time t = amount of fuel consumed÷ rate

= 744/150= 4.96 sec

applying newton's law

M×a= thrust - Mg

62000 a=900000- 62000×9.8

acceleration a= 4.71 m/s^2

its height after 744 kg of its total fuel load has been consumed

h= (1)/(2)at^2

h= (1)/(2)4.71*4.96^2

h= 58.012 m

h≅ 58 m

A rescue helicopter is hovering over a person whose boat has sunk. One of the rescuers throws a life preserver straight down to the victim with an initial velocity of 1.50 m/s and observes that it takes 1.2 s to reach the water. How high above the water was the preserver released? Note that the downdraft of the helicopter reduces the effects of air resistance on the falling life preserver, so that an acceleration equal to that of gravity is reasonable. Round your answer to the nearest whole number.

Answers

Answer:

The answer is 9 m.

Explanation:

Using the kinematic equation for an object in free fall:

y = y_o - v_o-(1)/(2)gt^(2)

In this case:

v_o = \textrm{Initial velocity} = 1.5[m/s]\nt = \textrm{air time} =  1.2 [s]y_o = 0

g = \textrm{gravity} = 9.8 [m/s^(2) ]

Plugging those values into the previous equation:

y = 0 - 1.5*1.2-(1)/(2)*9.8*1.2^(2) \ny = -8.85 [m] \approx -9 [m]

The negative sign is because the reference taken. If I see everything from the rescuer point of view.

A string is attached to the rear-view mirror of a car. A ball is hanging at the other end of the string. The car is driving around in a circle, at a constant speed. Which of the following lists gives all of the forces directly acting on the ball?a. tension
b. tension and gravity
c. tension, gravity, and the centripetal force
d. tension, gravity, the centripetal force, and friction

Answers

Final answer:

The forces directly acting on the ball hanging from a rear-view mirror while a car drives in a circle are tension, gravity, and the centripetal force.

Explanation:

The correct answer is c. tension, gravity, and the centripetal force.

When the car is driving in a circle, the ball experiences both tension and gravity. The tension in the string is what keeps the ball from falling, while gravity pulls the ball downward.

In addition to tension and gravity, the ball also experiences the centripetal force. This force is directed towards the center of the circular motion and keeps the ball moving in a circular path.

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A truck traveling with an initial velocity of 44.1 m/s comes to a stop in 15.91 secs. What is theacceleration of the truck?

Answers

Answer:

a=-2.77 m/s^2

Explanation:

Assuming constant acceleration,

v=at + v_0

where v_0 is the initial velocity.

At rest, v=0, so

0=at+v_0

So solving the equation for a:

a=(-v_0)/t

Inserting the numbers yields

a=-2.77 m/s^2

The Richter scale is used to determine how strong the earthquake is (magnitude) of the earthquake. It touches the ground and feels the earth shaking. With the momentum of the earth shaking the device the needle on the device moves creating a wave looking line. According to the theory of plate tectonics, what happens at transform, divergent and convergent boundaries? On which of these boundary types would a volcano most likely take place, and why?

Answers

convergent, because it is where the tectonic plates shove themselves together usually resulting in a mountain or volcano

Final answer:

In plate tectonics theory, transform boundaries occur when two plates slide past each other, divergent boundaries occur when two plates move away from each other, and convergent boundaries occur when two plates collide. A volcano is most likely to occur at a divergent boundary because the plates move away from each other, allowing magma from the mantle to reach the surface and create new crust.

Explanation:

In plate tectonics theory, Transform boundaries occur when two plates slide past each other horizontally, creating earthquakes. Divergent boundaries occur when two plates move away from each other, creating volcanic activity.

Convergent boundaries occur when two plates collide, and depending on the type of plates involved, can result in volcanic activity as one plate is forced beneath the other.

A volcano is most likely to occur at a divergent boundary because the plates move away from each other, allowing magma from the mantle to reach the surface and create new crust.

The Richter scale indicates the magnitude of an earthquake. The figure drawn by the needle during shaking is an outcome of earthquake's energy. This energy is what results in seismic waves travelling through various layers of earth causing shaking on the surface.

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A conveyor belt is used to move sand from one place to another in a factory. The conveyor is tilted at an angle of 18° above the horizontal and the sand is moved without slipping at the rate of 2 m/s. The sand is collected in a big drum 5 m below the end of the conveyor belt. Determine the horizontal distance between the end of the conveyor belt and the middle of the collecting drum.

Answers

The motion of sand is due to the movement of conveyor belt. The horizontal distance between the end of the conveyor belt and the middle of the collecting drum is 2.044 meters.

What is equation of motion?

The equation of motion is the relation between the distance, velocity, acceleration and time of a moving body.

The second equation of the motion for distance can be given as,

y=ut+(2)/(2)gt^2

Here, u is the initial body, g is the acceleration of the body due to gravity and t is the time taken by it.


Given information-

The conveyor is tilted at an angle of 18° above the horizontal.

The Sand is moved without slipping at the rate of 2 m/s.

The sand is collected in a big drum 5 m below the end of the conveyor belt.

The horizontal component of the velocity is given as,

v_y=2\cos 18

The vertical component of the velocity is given as,

v_y=2\sin18

Put the value in the above equation as,

y-y_0=v_yt+(1)/(2)gt^2

0-5=2\sin18 (t)+(1)/(2)*9.8\tiems t^2\nt=1.075\rm sec

The horizontal distance between the end of the conveyor belt and the middle of the collecting drum is,

d=v_xt\nd=2\cos18*1.075\nd=2.044\rm m

Thus, the horizontal distance between the end of the conveyor belt and the middle of the collecting drum is 2.044 meters.

Learn more about the equation of motion here;

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Answer:

x = 2.044 m

Explanation:

given data

initial vertical component of velocity = Vy = 2sin18

initial horizontal component of velocity = Vx = 2cos18

distance from the ground yo = 5m

ground distance y = 0

from equation of motion

y = yo+ V_y t +(1)/(2)gt^2

0 = 5 + 2sin18+ (1)/(2)*9.8t^2

solving for t

t = 1.075 sec

for horizontal motion

x = V_x t

x = 2cos18*1.075

x = 2.044 m