In clinical brachytherapy, the supervision of radio elements and dose interpretation are performed by the therapeutic ____________________ (two words).
Answers
Answer:
Radiation oncologist.
Explanation:
Cancer is one of the most deadly disease and half of the world population died due to cancer every year. Cancer might occur due to the mutation in the genes that control the cell cycle.
The oncologist may be defined as the individual that has specialized in the cancer and its treatment. The different radiation might use to kill the cancerous cell and the radio elements are administered in the drugs used during the chemotherapy.
Thus, the answer is radiation oncologist.
Related Questions
an organic compound on analysis yielded 2.04g carbon, 0.34g hydrogen, 2.73g oxygen. calculate the empirical formula
Why is Neon in the same group of the periodic table as Helium?
Elements in Group 17 form which ion?A. 1B. +1C. -1D. 0
The following three solutions are mixed: 100.0mL of 0.100M Na₂SO₄, 50.0mL of 0.300M ZnCl₂, and 100.0mL of 0.200M Ba(CN)₂. Cyanide (CN-) solubilities are not in most tables, but Ba(CN)₂ is soluble, Zn(CN)₂ is not. a. What ionic compounds will precipitate out of solution? b. What is the molarity of each ion remaining in the solution, assuming complete precipitation of all insoluble compounds, and assuming that volumes are additive?
Answers
Word Equation: Calcium chloride + Silver nitrate → Calcium nitrate + Silver chloride (precipitate).
Type of Reaction: Double displacement (precipitation).
The chemical equation can be converted into a word equation as follows:
Word Equation:
Calcium chloride (aqueous) + Silver nitrate (aqueous) → Calcium nitrate (aqueous) + Silver chloride (solid)
Type of Reaction:
This is a double displacement reaction, specifically a precipitation reaction. In a double displacement reaction, the cations and anions of two compounds switch places, resulting in the formation of two new compounds. In this particular case, when calcium chloride and silver nitrate are mixed, calcium nitrate and silver chloride are formed.
Furthermore, it's a precipitation reaction because one of the products, silver chloride, is insoluble in water and forms a solid (precipitate) rather than remaining in solution. The solid silver chloride is observed as a white, cloudy precipitate that settles at the bottom of the reaction vessel.
For more such information on: Word Equation
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The question probable may be;
CaCl2(aq) + 2AgNO3(aq)) → Ca(NO3)2(aq) + 2AgCl(s)
Convert this into word equation and tell what type of reaction is this?
Calcium Chloride + Silver Nitrate = Calcium Nitrate + Silver Chloride
( double replacement )
hope this helps!
Answers
Answer:
The final solution will be clear and colorless.
Explanation:
The balanced reaction equation is:
NaOH + HCl ⇒ H₂O + NaCl
The amount of NaOH that is added is calculated as follows:
(20.0mL)(1.0mol/L) = 20 mmol NaOH
Similarly, the amount of HCl that is added is as follows:
(10.0mL)(1.0mol/L) = 10 mmol HCl
Since HCl and NaOH react in 1:1 proportions, the HCl is the limiting reaction. 10 mmmol of HCl will neutralize 10 mmol of NaOH, leaving 10 mmol of NaOH. The volume of the mixed solution is 30.0 mL, so the concentration of NaOH in the final solution is:
(10 mmol)/(30.0mL) = 0.3333 M NaOH
The pOH of the final solution is:
pOH = -log([OH⁻) = -log(0.3333) = 0.477
The pOH is related to the pH as follows:
pH = 14 - pOH = 14 - 0.477 = 13.5
At a pH of 13.5, phenolphthalein is colorless. The final solution will be observed as clear and colorless.
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% by mass = 31.8 g LiCl / 225 g water + 31.8 g LiCl x 100%
% by mass = 12.38%
(2) 0.480 M (4) 0.801 M
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The molarity of the HCl acid is 0.480 M. The correct option is 2.
What is molarity?
Molarity is the division of the mass of the solution to the volume of the solution.
The formula that is used is
Putting the values in the equation
0.620 * 12.7 = M1 * 16.4 = 0.480
Thus, the molarity of the HCl acid is 2). 0.480 M.
Learn more about molarity
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Molarity is equal to the moles of solute over liters of solvent. In getting the molarity of HCl, you must know the formula for two solutions which is equal to M1V1 = M2V2. (16.4 milliliters of HCl)M1 = (12.7 milliliters) (0.620 M KOH) and you have 0.480M HCl. The answer is number 2.
Answers
Answer:
Light Emitting Diode (LED) lighting device.
Explanation:
Light Emitting Diode (LED) is an electrical component that produces light when a current flows through its terminals. It has a long life span and conserves energy coupled with brilliant lightning effects. Also, it is light in weight and generate no heat compared to other lighting devices. It is majorly recomended because of its diverse properties and efficient functions.
This componet can be incorporated to produce an energy efficient and long lasting lighting device. So, Ron should use a Light Emitting Diode (LED) lighting device.
2. more valence electrons
3. fewer electron shells
4. more electron shells
Answers
Compared to the atoms of nonmetals in period 3, the atoms of metals in period 3 have fewer valence electrons.
Option 1 is correct.
In the periodic table, the period runs from left to right on the table while the group runs from top to bottom on the table.
In period 3, the period starts with Sodium Na(alkali metal), Magnesium Mg(alkaline earth metals), Aluminium Al(other non metals), Silicon Si (non metals), Phosphorus (non-metals), Sulfur (non-metals). etc.
From left to right across period 3, the valence electrons in the outermost increase.
Hence, the metals will have fewer valence electrons since the metals start period 3.
Therefore, we can conclude that compared to the atoms of nonmetals in period 3, the atoms of metals in period 3 have fewer valence electrons.
Learn more about the periodic table here:
Answer : Option A) Fewer valence electrons
Explanation : Compared to the atoms of non metals in period 3, atoms of metals in period 3 have fewer valence electrons.
There are 8 elemental members in third period which are eight: sodium, magnesium, aluminium, silicon, phosphorus, sulfur, chlorine, and argon.
The first 2 elements belong to s-block whereas the other elements belong to p-block. The atomic radius is found to decrease across the period.
The electrons in the valence shell increases as we go from left to right in the period, which means when we move from metal to non-metal side the number of valence electrons also increases. This clearly shows that metals have fewer valence electrons as compared to the non-metals.