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We must use substitution to do this second integral. We can use the substitution t = 7x, which will give dx = Correct: Your answer is correct. dt. Ignoring the constant of integration, we have sin(7x) dx =

Answers

Answer 1

Answer:

Answer:

Therefore, the solution is:

$\boxed{\int \sin 7x\, dx=-(\cos 7x)/(7)}$

Step-by-step explanation:

We calculate the given integral. We use the substitution t = 7x.

$\int \sin 7x\, dx=\begin{vmatrix} 7x=t\n 7\, dx=dt\n dx=(dt)/(7) \end{vmatrix}\n\n=\int \sin t \cdot (1)/(7)\, dt\n\n=(1)/(7)\cdot (-\cos t)\n\n=-(\cos 7x)/(7)$

Therefore, the solution is:

$\boxed{\int \sin 7x\, dx=-(\cos 7x)/(7)}$

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Lydia has money in two savings accounts. One rate is 7% and the other is 13%. If she has $300 more in the 13% account and the total interest is $252, how much is invested in each savings account?

Answers

Answer:

7%: $1065
13%: $1365

Step-by-step explanation:

If x represents the amount invested at 7%, then the amount invested at 13% is x+300. Lydia's total interest is ...

0.07x +0.13(x +300) = 252

0.20x = 213 . . . . . subtract 39

x = 213/0.20 = 1065

Lydia has $1065 invested at 7% and $1365 invested at 13%.

Final answer:

Using the given conditions, we set up and solve an equation where x is the amount invested at a 7% rate and x + $300 is the amount at a 13% rate. After solving, we find that Lydia has $1065 in the 7% account and $1365 in the 13% account.

Explanation:

Let's assume Lydia's investment at 7% to be x and her investment at 13% to be x + $300. Since the total interest is $252, we can create an equation to solve for the values of x.

The equation will look like this:

0.07x + 0.13(x + 300) = 252

Let's solve the equation:

0.07x + 0.13x + 39 = 252

Combine like terms to get 0.2x + 39 = 252

Subtract 39 from both sides to get 0.2x = 213

Divide by 0.2 to solve for x, which gives x = 1065.

So, Lydia has $1065 in the 7% account and $1065 + $300 = $1365 in the 13% account.

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Who can access your credit report?a friends
b. employers
c. neighbors
d. teachers
Please select the best answer from the choices provided.
Ο Α
С В
ОС
D

Answers

This answer would be B

Answer:

B) employers

Step-by-step explanation:

EDGE 2021

A carpet company advertises that it will deliver your carpet within 15 days of purchase. A sample of 49 past customers is taken. The average delivery time in the sample was 16.2 days. Assume the population standard deviation is known to be 5.6 days. a. State the null and alternative hypotheses.
b. Using a critical value, test the null hypothesis at the 5% level of significance.
c. Using a p-value, test the hypothesis at the 5% level of significance.
d. What type of error may have been committed for this hypothesis test

Answers

Answer:

a) $H_0: \mu\leq15\n\nH_1: \mu>15$

b) The z-value (1.5) is smaller than z=1.645 (critical value), so it is in the "acceptance region". It failed to reject the null hypothesis.

c) The p-value (0.07) is greater than the significance level (0.05), so it failed to reject the null hypothesis.

d) In this case, the error we may hae comitted is a Type II error (failed to reject a null hypothesis that is false).

Step-by-step explanation:

We have to perfomr a hypothesis test on the mean, with known standard deviation of the population.

a) The null hypothesis is that the deliver time is 15 days or less.

The null and alternative hypothesis are then:

$H_0: \mu\leq15\n\nH_1: \mu>15$

The significance level is defined as 0.05.

b) The critical value of z for a one-side test (rigth side) and a significance level of 0.05 is z=1.645.

If the z-value for this sample is higher than 1.645, it is in the "rejection region".

Calculating the z-value:

$z=(M-\mu)/(\sigma/√(n))=(16.2-15)/(5.6/√(49))=(1.2)/(0.8)=1.5$

The z-value (1.5) is smaller than z=1.645 (critical value), so it is in the "acceptance region". It failed to reject the null hypothesis.

c) The p-value for z=1.5 is:

$P(z>1.5)=0.067$

The p-value (0.07) is greater than the significance level (0.05), so it failed to reject the null hypothesis.

d) There are two types of error:

Type I errors: happen when we reject a null hypothesis that is true.

Type II errors: happen when we failed to reject a null hypothesis that is false.

In this case, the error we may hae comitted is a Type II error.

The null hypothesis at 5% significance level is 1.50

Data;

n = 49
mean = 16.2
standard deviation = 5.6

Null and Alternative Hypothesis

The alternative hypothesis are

$H_-;\mu \leq 15 : H_1 : \mu > 15$

H_o = mean = 15

standard deviation = 5.6 days

using z-test,

n is greater than or equal to 30

Assuming standard deviation is known

$z = (x-\mu)/(\sigma - √(n) ) \nz = (16.2-15)/(5.6/√(49) )\nz = 1.50$

z-critical value is 1.96 at 95% confidence level.

Since z-critical value is greater than the test statistic, so we tail to subject H_o.

There's no evidence that mean delivery time is different from 15 days.

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Hi what is 398÷45.

Answers

Answer:

8.84444444444

Step-by-step explanation:

Answer:

the answered would be 8.8444444

Consider the following functions. f(x) = x − 3, g(x) = x2 Find (f + g)(x). Find the domain of (f + g)(x). (Enter your answer using interval notation.) Find (f − g)(x). Find the domain of (f − g)(x). (Enter your answer using interval notation.) Find (fg)(x). Find the domain of (fg)(x). (Enter your answer using interval notation.) Find f g (x). Find the domain of f g (x). (Enter your answer using interval notation.)

Answers

Answer:

$(f+g)(x)=x-3+x^2$ ; Domain = (-∞, ∞)

$(f-g)(x)=x-3-x^2$ ; Domain = (-∞, ∞)

$(fg)(x)=x^3-3x^2$ ; Domain = (-∞, ∞)

$((f)/(g))(x)=(x-3)/(x^2)$ ; Domain = (-∞,0)∪(0, ∞)

Step-by-step explanation:

The given functions are

$f(x)=x-3$

$g(x)=x^2$

$(f+g)(x)=f(x)+g(x)$

Substitute the values of the given functions.

$(f+g)(x)=(x-3)+x^2$

$(f+g)(x)=x-3+x^2$

The function $(f+g)(x)=x-3+x^2$ is a polynomial which is defined for all real values x.

Domain of (f+g)(x) = (-∞, ∞)

$(f-g)(x)=f(x)-g(x)$

Substitute the values of the given functions.

$(f-g)(x)=(x-3)-x^2$

$(f-g)(x)=x-3-x^2$

The function $(f-g)(x)=x-3-x^2$ is a polynomial which is defined for all real values x.

Domain of (f-g)(x) = (-∞, ∞)

$(fg)(x)=f(x)g(x)$

Substitute the values of the given functions.

$(fg)(x)=(x-3)x^2$

$(fg)(x)=x^3-3x^2$

The function $(fg)(x)=x^3-3x^2$ is a polynomial which is defined for all real values x.

Domain of (fg)(x) = (-∞, ∞)

$((f)/(g))(x)=(f(x))/(g(x))$

Substitute the values of the given functions.

$((f)/(g))(x)=(x-3)/(x^2)$

The function $((f)/(g))(x)=(x-3)/(x^2)$ is a rational function which is defined for all real values x except 0.

Domain of (f/g)(x) = (-∞,0)∪(0, ∞)

$(f + g)(x) = x^2 + x - 3$ , domain: all real numbers.

$(f - g)(x) = -x^2 + x - 3$ , domain: all real numbers.

$(fg)(x) = x^3 - 3x^2$ , domain: all real numbers.

$f(g(x)) = x^2 - 3$ , domain: all real numbers.

To find (f + g)(x), we need to add the functions f(x) and g(x).

The function f(x) = x - 3 and the function $g(x) = x^2.$

So, $(f + g)(x) = f(x) + g(x) = (x - 3) + (x^2).$

Expanding this equation, we get $(f + g)(x) = x^2 + x - 3.$

To find the domain of (f + g)(x), we need to consider the domain of the individual functions f(x) and g(x).

Since both f(x) = x - 3 and $g(x) = x^2$ are defined for all real numbers, the domain of (f + g)(x) is also all real numbers.

To find (f - g)(x), we need to subtract the function g(x) from f(x).

So, $(f - g)(x) = f(x) - g(x) = (x - 3) - (x^2).$

Expanding this equation, we get $(f - g)(x) = -x^2 + x - 3.$

The domain of (f - g)(x) is also all real numbers, since both f(x) and g(x) are defined for all real numbers.

To find (fg)(x), we need to multiply the functions f(x) and g(x).

So, $(fg)(x) = f(x) * g(x) = (x - 3) * (x^2).$

Expanding this equation, we get $(fg)(x) = x^3 - 3x^2.$

The domain of (fg)(x) is all real numbers, since both f(x) and g(x) are defined for all real numbers.

To find f(g(x)), we need to substitute g(x) into the function f(x).

So, $f(g(x)) = f(x^2) = x^2 - 3.$

The domain of f(g(x)) is also all real numbers, as $g(x) = x^2$ is defined for all real numbers, and f(x) = x - 3 is defined for all real numbers.

In summary:

- $(f + g)(x) = x^2 + x - 3$ , domain: all real numbers.

- $(f - g)(x) = -x^2 + x - 3$ , domain: all real numbers.

- $(fg)(x) = x^3 - 3x^2$ , domain: all real numbers.

- $f(g(x)) = x^2 - 3$ , domain: all real numbers.

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Where can I watch My hero academia for free without any ads if you don't know then you could suggest something with adds

Answers

I don't think there is a way to watch ad-less

I watch it with Premium Hulu.

Answer:

Anime Plus

You can watch it ad free on Anime plus and you don't have to pay for it

Edit: My apologies mha is not on there only the movies are

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