discrete random variable X has the following probability distribution: x 13 18 20 24 27 P ( x ) 0.22 0.25 0.20 0.17 0.16 Compute each of the following quantities. P ( 18 ) . P(X > 18). P(X ≤ 18). The mean μ of X. The variance σ 2 of X. The standard deviation σ of X.

Answers

Answer 1
Answer:

Answer:

(a) P(X = 18) = 0.25

(b) P(X > 18) = 0.53

(c) P(X ≤ 18) = 0.47

(d) Mean = 19.76

(e) Variance = 22.2824

(f) Standard deviation = 4.7204

Step-by-step explanation:

We are given that discrete random variable X has the following probability distribution:

            X                    P (x)             X * P(x)            X^(2)             X^(2) * P(x)

           13                    0.22              2.86              169              37.18

           18                    0.25              4.5                324               81

           20                   0.20               4                  400               80

           24                    0.17              4.08              576              97.92

           27                    0.16              4.32              729             116.64

(a) P ( X = 18) = P(x) corresponding to X = 18 i.e. 0.25

     Therefore, P(X = 18) = 0.25

(b) P(X > 18) = 1 - P(X = 18) - P(X = 13) = 1 - 0.25 - 0.22 = 0.53

(c) P(X <= 18) = P(X = 13) + P(X = 18) = 0.22 + 0.25 = 0.47

(d) Mean of X, \mu = ∑X * P(x) ÷ ∑P(x) = (2.86 + 4.5 + 4 + 4.08 + 4.32) ÷ 1

                                                         = 19.76

(e) Variance of X, \sigma^(2) = ∑X^(2) * P(x) - (\sum X * P(x))^(2)

                                 = 412.74 - 19.76^(2) = 22.2824

(f) Standard deviation of X, \sigma = √(variance) = √(22.2824) = 4.7204 .

Answer 2
Answer:

Final answer:

The probabilities for the given X values are calculated by summing the relevant given probabilities. The mean of X is computed as a weighted average, and the variance and standard deviation are calculated using formula involving the mean and the individual probabilities.

Explanation:

The probability P(18) is given as 0.25 according to the distribution. The probability P(X > 18) is the sum of the probabilities for all x > 18, so we add the probabilities for x=20, x=24, and x=27, giving us 0.20 + 0.17 + 0.16 = 0.53. The probability P(X ≤ 18) includes x=18 and any values less than 18. As 18 is the lowest value given, P(X ≤ 18) is just P(18), or 0.25.

The mean μ of X is the expected value of X, computed as Σ(xP(x)). That gives us (13*0.22) + (18*0.25) + (20*0.20) + (24*0.17) + (27*0.16) = 2.86 + 4.5 + 4 + 4.08 + 4.32 = 19.76.

The variance σ 2 of X is computed as Σ [ (x - μ)^2 * P(x) ]. That gives us [(13-19.76)^2 * 0.22] + [(18-19.76)^2 * 0.25] + [(20-19.76)^2 * 0.20] + [(24-19.76)^2 * 0.17] + [(27-19.76)^2 * 0.16] = 21.61. The standard deviation σ of X is the sqrt(σ^2) = sqrt(21.61) = 4.65.

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The table shows the height of water in feet at different times. The water rises and falls in a cyclical pattern.A 2-column table with 5 rows. Column 1 is labeled x with entries 12 a m, 3 a m, 6 a m, 9 a m, 12 p m. Column 2 is labeled y with entries 6, 10, 6, 2, 6.

Which equation models the data in the table?

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y = 4 sine (StartFraction pi Over 6 EndFraction x) + 10

Answers

Modeling the data in the table is done via the equation y = 4 sine (pi/6x) + 6.

What is a cyclic pattern?

Over a period of years, a cyclical pattern recurs with considerable regularity. Cyclical patterns are distinct from seasonal patterns in that they last across a number of years as opposed to only one year for seasonal trends.

Given, The table shows the height of water in feet at different times. The water rises and falls in a cyclical pattern.

Table:

12 AM                      6  

3 AM                        10

6 AM                        6  

9 AM                        2  

12 PM                       6  

from the general formula of wave

y = A sin(bx + c)

Substituting values in the equation from the graph attached below:

6 = A sin(0*b + c)......(1)

10 = A sin3b + c...(2)

6 = A sin6b + c......(3)

2 = A sin9b +c........(4)

Since -c/b is a phase shift of the graph

Thus

-c/b = 6

c = -6b

from equations 2 and 1

2* 6 = Asin(-3b) = -Asin3b

2 * 6 = Asin(-6b) = -Asin6b

2* 6/6 =sin6b/sin3b

1 = Cos3b

Thus b = π/6

from substitution in equations 3

6 = A sin6b + c

=> 6 = Asin 6* pi/6  + c

=> c = 6

\begin{table}[]\begin{tabular}{ll}12 AM & 6  \n3 AM  & 10 \n6 AM  & 6  \n9 AM  & 2  \n12 PM & 6 \end{tabular}\end{table}from substitution in equations 2

10 = A sin3b + c

A = 4

therefore, The equation that models data in the table is y = 4 sine (pi/6x) + 6.

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Answer:

c

Step-by-step explanation:

HELP ME!!!! MY HOMEWORK IS SOOO CONFUSING

Answers

i thing the answer is D the last chart

Please Help Me For the figure below m<ABC = 70°. Which theorem or postulate can be used to determine m<DBC? What is m<DBC? (pic of the drawing below)​

Answers

Answer:

38°

Step-by-step explanation:

<ABD and <DBC are two interior angles that make up <ABC.

Based on the Angle Addition Theorem, the following equation can be used to find m<DBC:

(3x + 5) + (6x - 16) = 70

Find x

3x + 5 + 6x - 16 = 70

9x - 11 = 70

9x = 70 + 11

9x = 81

x = (81)/(9)

x = 9

We are given that, m<DBC = (6x - 16)°

Plug in the value of x to find the measure

m<DBC = 6(9) - 16 = 54 - 16 = 38°

According to a government study among adults in the 25- to 34-year age group, the mean amount spent per year on reading and entertainment is $1,999. Assume that the distribution of the amounts spent follows the normal distribution with a standard deviation of $574. (Round your z-score computation to 2 decimal places and final answers to 2 decimal places.) What percent of the adults spend more than $2,550 per year on reading and entertainment?

Answers

Answer:

The probability is  P(X >  x  ) = 0.19215

Step-by-step explanation:

From the question we are told that

   Th The population mean \mu  =  \$ 1,999

    The  standard deviation is  \sigma =  \$ 574

    The  values considered is  x =   \$ 2,500

Given that the distribution of the amounts spent follows the normal distribution then the  percent of the adults spend more than $2,550 per year on reading and entertainment is mathematically represented as

    P(X >  x  ) =  P(( X -  \mu)/(\sigma )  > ( x -  \mu)/(\sigma )  )

Generally  

            X -  \mu}{\sigma }  =  Z (The \ standardized \ value \  of  \  X )

So

      P(X >  x  ) =  P(Z > ( x -  \mu)/(\sigma )  )

substituting values

      P(X >  2500  ) =  P(Z > ( 2500 -  1999)/(574 )  )

      P(X >  2500  ) =  P(Z >0.87 )

From the normal distribution table the value of P(Z >0.87 ) is  

       P(Z >0.87 ) = 0.19215

Thus  

       P(X >  x  ) = 0.19215

Final answer:

We calculate the z-score for the amount $2,550 using the given mean and standard deviation. The z-table gives us the percentage of people who spend less than this, which we subtract from 1 to find the percentage who spend more. Approximately 16.85% of adults in the 25- to 34-year age group spend more than $2,550 on reading and entertainment each year.

Explanation:

To compute the percentage of adults spending more than $2,550 per year, we must first find the z-score associated with this value. The z-score is a measurement of how many standard deviations a particular data point is from the mean.

The formula for calculating the z-score is: Z = (X - μ) / σ.

Where:
- X is the value we are interested in.
- μ is the mean.
- σ is the standard deviation.

Using this formula, the z-score for $2,550 is:
Z = ($2,550 - $1,999) / $574 = 0.96.

Next, we need to use a z-table or a standard normal distribution table to find out the probability that lies below the calculated z-score. Looking this up on a z-table, we get a value of 0.8315, meaning that 83.15% of the population will spend $2,550 or less per year on reading and entertainment. Since we want to know the percentage spending more than $2,550, we subtract this value from 1: 1 - 0.8315 = 0.1685.

Therefore, based on the given mean and standard deviation, about 16.85% of adults in the 25- to 34-year age group spend more than $2,550 on reading and entertainment each year.

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A Microgates Industries bond has a 10 percent coupon rate and a $1,000 face value. Interest is paid semiannually, and the bond has 20 years to maturity. If investors require a 12 percent yield, what is the bond’s value? * a. $849.45 b. $879.60 c. $985.18 d. $963.15 e. None of the above

Answers

Answer:

a. $849.45

Step-by-step explanation:

In the above question, we are given the following information

Coupon rate = 10%

Face value = 1000

Maturity = n = 20 years

t = number of periods = compounded semi annually = 2

Percent yield = 12% = 0.12

Bond Value formula =

C/t × ([1 -( 1/ 1 + r/t)-^nt ÷] r/t) +( F/ (1 + r/t)^nt)

C = coupon rate × face value = 10% × 1000 = 100

Bond value:

= 100/2 × ( [1 - (1 /1 + 0.12/2)^-20×2]÷ 0.12/2)+ (1000/( 1 + 0.12/2)^20×2

= 50 × ( [1 - (1 /1 + 0.06) ^40] ÷ 0.06) + ( 1000/ (1 + 0.06) ^40

= 50 × ( [1 - (1/ (1.06) ^40] ÷ 0.06 ) + (1000/(1.06)^40)

= 50 × 15.046296872 + 97.222187709

= $849.45

Bond value = $849.45

The heights, in centimeters, of five students in a school’s class team are: 165, 175, 176, 159, and 170. What is the mean of the heights of the five students?

Answers

Answer:

169 cm

Step-by-step explanation:

Mean is the average of a group of numbers. You calculate it by adding all your numbers and dividing by how many numbers you have. In this question you would solve with these steps...

Add all of your numbers

165 + 175 + 176 + 159 + 170 = 845

Divide your solution by the number of numbers you have

845 / 5 = 169

The mean of the heights of the five students is 169cm.

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