1. What structural property of sodium 4-amino-1-naphthalenesulfonate makes it very soluble in water? 2. You will have to look up the structure of this compound and comment on why it is water-soluble. Simply stating that it's polar

Answers

Answer 1
Answer:

1. Sodium 4-amino-1-naphthalenesulfonate makes it very soluble in water as it contains a hydrate salt sodium sulfate NaO_4S.

2. In the structure of this compound, sodium sulphate is polar in nature.

Molecular formula:

The molecular structure of sodium 4-amino-1-naphthalenesulfonate is C_(10)H_(10)NNaO_4S.

The polar part of the structure sodium sulfate NaO_4S makes sodium 4-amino-1-naphthalenesulfonate a hydrate salt. Salt are polar and are usually soluble in water.

Find more information about Molecular formula here:

brainly.com/question/11951743

Answer 2
Answer:

Answer: it contains a hydrate salt sodium sulfate NaO4S.

4-amino-1-naphthalenesulfonate is a sodium salt. Sodium sulfate is Polar.

Explanation:

The molecular structure of sodium 4-amino-1-naphthalenesulfonate is

C10H10NNaO4S

The polar part of the structure sodium sulfate NaO4S makes sodium 4-amino-1-naphthalenesulfonate a hydrate salt. Salt are polar and are usually soluble in water.


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Identify the true statements about introns.a- they code for polypeptide proteinsb- they have a branch site located 20 to 50 nucleotides upstream of the 3' splice sitec- they end with the nucleotides AG at the 3' endd- they begin with the nucleotides GU at the 5' ende- they tend to be common in bacterial genes

Answers

Answer:

The answer is "Option b, c, and d".

Explanation:

In such a gene, Autosomes are also the sequence for code and transposable elements, not the series of encoding. Through the expression of genes, such fragments of its introns are split through protein complexes throughout the translation process. There has been no kenaf fiber in the genomes of prokaryotic cells.

What may happen to the human body when exposed to an infectious agent? A. When infectious agents get into the human body, your body responds by functioning normally.

B. When infectious agents get into the human body, the body gets a surge of energy, causing a slight increase in body temperature, and you feel great.

C. When infectious agents get into the human body, your body responds by raising the core body temperature, causing a fever.

D.Nothing happens when the human body is exposed to an infectious agent.

Answers

Answer:

when infectious agents get into the human body your body responds by raising the core body temperature causing a fever

The answer is C it will raise your body temp and cause a fever

What will be the theoretical yield of tungsten(is) ,W, if 45.0 g of WO3 combines as completely as possible with 1.50 g of H2

Answers

Answer:

35.6 g of W, is the theoretical yield

Explanation:

This is the reaction

WO₃  +  3H₂  →   3H₂O  +  W

Let's determine the limiting reactant:

Mass / molar mass = moles

45 g / 231.84 g/mol = 0.194 moles

1.50 g / 2 g/mol = 0.75 moles

Ratio is 1:3. 1 mol of tungsten(VI) oxide needs 3 moles of hydrogen to react.

Let's make rules of three:

1 mol of tungsten(VI) oxide needs 3 moles of H₂

Then 0.194 moles of tungsten(VI) oxide would need (0.194  .3) /1 = 0.582 moles (I have 0.75 moles of H₂, so the H₂ is my excess.. Then, the limiting is the tungsten(VI) oxide)

3 moles of H₂ need 1 mol of WO₃ to react

0.75 moles of H₂ would need (0.75 . 1)/3 = 0.25 moles

It's ok. I do not have enough WO₃.

Finally, the ratio is 1:1 (WO₃ - W), so 0.194 moles of WO₃ will produce the same amount of W.

Let's convert the moles to mass (molar mass  . mol)

0.194 mol . 183.84 g/mol = 35.6 g

The information below describes a redox reaction.Cr3+(aq)+2Cl-(aq)---->Cr(s)+Cl2(s)
2Cl-(aq)--->Cl2(g)+2e-
Cr3+(aq)+3e- ---->Cr(s)

What is the final, balanced equation for this reaction?
1.) 2cr3+(aq)+6Cl-(aq) ------> 2Cr(s)+3Cl2(g)
2.) 2Cr3(aq)+2Cl-(aq)+6e- --->Cl2(g)+2Cr(s)
3.) Cr3+(aq)+6Cl-(aq)+3e- ---->2Cr(g)+3Cl2(g)
4.) Cr3+(aq)+2Cl-(aq)------>Cr(s)+Cl2(g)

Answers

Answer: option 1)  2Cr3+(aq)+6Cl-(aq) ------> 2Cr(s)+3Cl2(g)

Explanation:

1) Write the oxidation half-reaction:

2Cl^-(aq)---\ \textgreater \ Cl_2(g)+2e^-

2) Write the reduction half-raction:

Cr^(3+)(aq)+3e^(-)---\ \textgreater \ Cr(s)

3) Multiply each half-reaction by the appropiate coefficient to equal the number of electrons of both half-reactions.

6Cl^(-)(aq)---\ \textgreater \ 3Cl_2(g)+6e^(-) 2Cr^(3+)(aq)+6e^(-)---\ \textgreater \ 2Cr(s)

4) Add both half-reactions

2Cr^(3+)+6Cl^(-)(aq)---\ \textgreater \ 2Cr(s) +3Cl_2(g)

And that is the answer. You can count the atoms and charges on every side and check they are equal.

Answer:

A

Explanation:

got it correct on edge

In chemical reactions, what does the law of conservation of mass mean?Group of answer choices

Matter is not created nor destroyed.

The total mass of the products is greater than the total mass of the reactants.

The total mass of the reactants is less that the total mass of the products.

Matter is not changed.

Answers

Answer

The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.

In the following structure, carbons (I),(2),(3) and (4) are classified respectively as

Answers

Answer:

Carbon (i) : quaternary carbon

Carbon (ii) : secondary carbon

Carbon (iii) : tertiary carbon

Carbon (iv) : secondary carbon

Explanation:

Carbons can be classified into 4 categories:

(1) Primary carbon(1^o): These are the atoms where the carbon atom is attached to one other carbon atom.

(2) Secondary carbon(2^o): These are the atoms where the carbon atom is attached to two other carbon atoms.

(3) Tertiary carbon(3^o): These are the atoms where the carbon atom is attached to three other carbon atoms.

(4) Quaternary carbon(4^o): These are the atoms where the carbon atom is attached to four other carbon atoms.

In the given structure:

Carbon (i) is attached to 4 further carbon atoms and hence, it is a quaternary carbon.

Carbon (ii) is attached to 2 further carbon atoms and hence, it is a secondary carbon.

Carbon (iii) is attached to 3 further carbon atoms and hence, it is a tertiary carbon.

Carbon (iv) is attached to 2 further carbon atoms and hence, it is a secondary carbon.