Answers
Answer:
The magnitude of the force you must exert on the rope in order to accelerate upward is 705.6 N
Explanation:
The magnitude of force, you must exert can be estimated as follows;
Since it is upward motion, we must consider acceleration due to gravity which opposes the upward motion.
F = m(a+g)
where;
F is the magnitude of the upward force
m is your mass, which is the measure of inertia = 63kg
a is the acceleration of the rope = 1.4 m/s²
F = 63(1.4 + 9.8)
F = 63(11.2)
F = 705.6 N
Therefore, the magnitude of the force you must exert on the rope in order to accelerate upward is 705.6 N
Answer:
705.6 N
Explanation:
Force: This can be defined as the product of mass a acceleration.
The S.I unit of force is Newton.
The expression for the force on the rope in order to accelerate upward is given as,
F-W = ma .......................... Equation 1
Where F = Force exerted on the rope, W = weight of the rope, m = mass of the rope, a = acceleration.
But,
W = mg........................ Equation 2
Where g = acceleration due to gravity
substitute equation 2 into equation 1
F-mg = ma
F = ma+mg
F = m(a+g).............. Equation 3
Given: m = 63 kg, a = 1.4 m/s²
Constant: g = 9.8 m/s²
Substitute into equation 3
F = 63(1.4+9.8)
F = 63(11.2)
F = 705.6 N
The magnitude of the force exerted on the rope = 705.6 N
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Answers
Answer:
A. A tractor trailer rig moving at 2 m/s
Explanation:
Inertia can be defined as the tendency of an object or a body to continue in its state of motion or remain at rest unless acted upon by an external force.
In physics, Sir Isaac Newton's first law of motion is known as law of inertia and it states that, an object or a physical body in motion will continue in its state of motion at continuous velocity (the same speed and direction) or, if at rest, will remain at rest unless acted upon by an external force.
The inertia of an object such as a tractor trailer rig is greatly dependent or influenced by its mass; the higher quantity of matter in a tractor trailer rig, the greater will be its tendency to continuously remain at rest.
Hence, the object that has more inertia is a tractor trailer rig moving at 2 m/s because it has more mass than all the other objects in the category. Also, the mass of an object is directly proportional to its inertia.
Answers
Solution:
With reference to Fig. 1
Let 'x' be the distance from the wall
Then for DAC:
⇒
Now for the BAC:
⇒
Now, differentiating w.r.t x:
For maximum angle, = 0
Now,
0 = [/tex]\frac{d}{dx}[tan^{-1} \frac{d + h}{x} - tan^{-1} \frac{d}{x}][/tex]
0 =
After solving the above eqn, we get
x =
The observer should stand at a distance equal to x =
Final answer:
For optimum viewing of a painting in a gallery, an observer should position themselves a distance away from the painting calculated using Pythagoras theorem, forming a right-angled triangle with the painting and the floor. This distance can be expressed as c = √[(h/2 + d)² + (h/2)²], where h is the height of the painting and d is the height from the observer's eye to the bottom of the painting.
Explanation:
In the physics of optics, the viewer should position themselves to where they form a right-angled triangle with the ceiling and the painting leading to the best viewing experience. This is widely known as the 'normal viewing distance'.
Given that the painting has a height h and its lower edge is at a distance d above the observer's eye, the observer should stand a distance away from the wall, which can be calculated using Pythagoras' theorem in right triangles, which states that the square of the hypotenuse (c) is equal to the sum of the square of the other two sides (a and b), i.e., c² = a² + b²
Since the painting height and viewer height forms the right-angle in this case, we have: a = (h/2 + d), and b = h/2. Substituting a and b in Pythagoras equation, we can solve for c which is the required distance: c = √[(h/2 + d)² + (h/2)²]
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Answers
Answer:
1391 N
Explanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 1300 × 1.07
We have the final answer as
1391 N
Hope this helps you
b. tension and gravity
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d. tension, gravity, the centripetal force, and friction
Answers
Final answer:
The forces directly acting on the ball hanging from a rear-view mirror while a car drives in a circle are tension, gravity, and the centripetal force.
Explanation:
The correct answer is c. tension, gravity, and the centripetal force.
When the car is driving in a circle, the ball experiences both tension and gravity. The tension in the string is what keeps the ball from falling, while gravity pulls the ball downward.
In addition to tension and gravity, the ball also experiences the centripetal force. This force is directed towards the center of the circular motion and keeps the ball moving in a circular path.
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person with male and female traits?
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XXX
XXY
XY
Answers
Answers
Answer:
b) 68,9 km/h a) picture
Explanation:
In this problem, since velocity is expressed in km/h and time in minutes, we have to convert either time to hours or velocity to km/min. It is easier to use hours.
Using this formula we pass time to hours:
Now we can plot speed vs time (image 1). The problem says that the driver uses constant speed, so all lines have to be horizontal.
Using the values of the speed we calculate the distance in each interval
Using these values and the fact that she was having lunch in the third one (therefore stayed in the same position), we plot position vs time, using initial position zero (image 2, distance is in km, not meters).
Finally, we compute the average speed with the distance over time: