Vaporized gases and released dust form a bright cloud called a(n) ____ around the solid part of a comet.

Answers

Answer 1

Answer: The mixture of gases round the body or nucleus of the comet is called a coma.

Answer 2

Answer:

the right answer is gonna be Coma

Related Questions

When the sum of all the forces acting on a block on an inclined plane is zero, the blockA) must be at restB) must be acceleratingC) may be slowing downD) may be moving at constant speed
2H is a loosely bound isotope of hydrogen, called deuterium or heavy hydrogen. It is stable but relatively rare — it form only 0.015% of natural hydrogen. Note that deuterium has Z = N, which should tend to make it more tightly bound, but both are odd numbers.Required:Calculate BE/A, the binding energy per nucleon, for 2H in megaelecton volts per nucleon
An electron in a vacuum chamber is fired with a speed of 7400 km/s toward a large, uniformly charged plate 75 cm away. The electron reaches a closest distance of 15 cm before being repelled. What is the plate's surface charge density?
The minimum charge on any object cannot be less than
John and Suzie are trying to improve the speed of their race car by adjusting the angle of the rear spoiler. Which choice is the controlled variable(s)?the maximum speed and the angle of the rear spoilerthe type of tire and the type of fuelonly the maximum speedonly the angle of the rear spoiler

A long wire carries a current density proportional to the distance from its center, J=(Jo/ro)•r, where Jo and ro are constants appropriate units. Determine the magnetic field vector inside this wire.

Answers

Answer:

$B = \mu_0((1)/(3) (J_0)/(r_0) r^2)$

Explanation:

As the current density is given as

$J = (J_0)/(r_0)r$

now we have current inside wire given as

$i = \int J(2\pi r)dr$

$i = \int (J_0)/(r_0) r(2\pi r)dr$

$i = 2\pi (J_0)/(r_0) \int r^2 dr$

$i = (2)/(3) \pi (J_0)/(r_0) r^3$

Now by Ampere's law we will have

$\int B. dl = \mu_0 i$

$B. (2\pi r) = \mu_0((2)/(3) \pi (J_0)/(r_0) r^3)$

$B = \mu_0((1)/(3) (J_0)/(r_0) r^2)$

The electrons in the beam of a television tube have an energy of 19.0 keV. The tube is oriented so that the electrons move horizontally from north to south. At the electron's latitude the vertical component of the Earth's magnetic field points down with a magnitude of 42.3 μT. What is the direction of the force on the electrons due to this component of the magnetic field?

Answers

Answer:

The direction is due south

Explanation:

From the question we are told that

The energy of the electron is $E = 19.0keV = 19.0 *10^3 eV$

The earths magnetic field is $B = 42.3 \muT = 42.3 *10^(-6) T$

Generally the force on the electron is perpendicular to the velocity of the elecrton and the magnetic field and this is mathematically reresented as

$\= F = q (\= v * \=B)$

On the first uploaded image is an illustration of the movement of the electron

Looking at the diagram we can see that in terms of direction the magnetic force is

$\= F =q(\=v * \= B)= -( -\r i * - \r k)$

$= -(- (\r i * \r k))$

generally i cross k = -j

so the equation above becomes

$\= F = -(-(- \r j))$

$= - \r j$

This show that the direction is towards the south

Light from a sodium lamp (λ = 589 nm) illuminates two narrow slits. The fringe spacing on a screen 150 cm behind the slits is 4.0 mm. What is the spacing (in mm) between the two slits?

Answers

The spacing between the two slits is 0.221mm.

The spacing between the two slits is given as,

$D=(\lambda L)/(y)$

Where $\lambda$ is wavelength, y is fringe spacing and L is length of screen.

Given that, $\lambda=589nm,L=150cm,y=4mm$

Substitute in above equation.

$D=(589*10^(-9)*150*10^(-2) )/(4*10^(-3) )\n \nD=2.21*10^(-4) m\n\nD=0.221mm$

Hence, the spacing between the two slits is 0.221mm.

Learn more about the sodium lamp here:

brainly.com/question/24867424

Which volcanoes are formed by pyroclastic deposits? Select all that apply. A. cinder cone B. stratovolcano C. shield volcano

Answers

Answer:

Its a cinder cone cause after it all falls down to make deposits.

cinder cone and stratovolcano

An early model of the atom, proposed by Rutherford after his discovery of the atomic nucleus, had a positive point charge +Ze (the nucleus) at the center of a sphere of radius R with uniformly distributed negative charge −Ze. Z is the atomic number, the number of protons in the nucleus and the number of electrons in the negative sphere. Show that the electric field inside this atom is : Ein=Ze4πϵ0(1r^2−rR^3). b. What is the electric field at the surface of the atom? Is this the expected value? Explain.c. A uranium atom has Z = 92 and R = 0.10 nm. What is the electric field at r = R/2?

Answers

Answer:

Part a)

$E = (Ze)/(4\pi\epsilon_0)((1)/(r^2) - (r)/(R^3))$

Part b)

$E = 0$

Yes it is the expected value of electric field at the surface of an atom

Part c)

$E = 4.64 * 10^(13) N/C$

Explanation:

Since negative charge of electrons in uniformly distributed in the atom while positive charge is concentrated at the nucleus

So the electric field due to positive charge of the nucleus is given as

$E = (kq)/(r^2)$

$E_1 = (Ze)/(4\pi \epsilon_0 r^2)$

now charge due to electrons inside a radius "r" is given as

$q = (-Ze r^3)/(R^3)$

now we will have electric field given as

$E_2 = ((-Zer^3)/(R^3))}{4\pi\epsilon_0 r^2}$

now net electric field is given as

$E = E_1 + E_2$

$E = (Ze)/(4\pi \epsilon_0 r^2) - (Zer)/(4\pi \epsilon_0 R^3)$

$E = (Ze)/(4\pi\epsilon_0)((1)/(r^2) - (r)/(R^3))$

Part b)

At the surface of an atom

$r = R$

$E = 0$

Yes it is the expected value of electric field at the surface of an atom

Part c)

If Z = 92

R = 0.10 nm

$r = (R)/(2)$

so we will have

$E = 92(1.6 * 10^(-19)) * (9 * 10^9)((4)/(R^2) - (1)/(2R^2))$

$E = (4.64 * 10^(-7))/((0.10 * 10^(-9))^2)$

$E = 4.64 * 10^(13) N/C$

We can calculate the force that the atmospheric pressure produces on a surface. Consider a living room that has a 4.0m×5.0m floor and a ceiling 3.0m high. What is the total force on the floor due to the air above the surface if the air pressure is 1.00 atm?