When the sum of all the forces acting on a block on an inclined plane is zero, the blockA) must be at rest
B) must be accelerating
C) may be slowing down
D) may be moving at constant speed

Answers

Answer 1
Answer:

Answer:

hmmm thats too hard for me.

Explanation:


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So to deal with the irrational belief in REBT, we must Group of answer choices

A. Consult with a friend and get their feeback

B. Dispute the beliefs by asking if these are true and examining the evidence

C. Seek mental health counseling

D. It is just too hard so let's just forget it.

Answers

Answer:

i believe the answer is B

Explanation:

Seeking the right answer is the best thing to do

Light with a wavelength of 495 nm is falling on a surface and electrons with a maximum kinetic energy of 0.5 eV are ejected. What could you do to increase the maximum kinetic energy of electrons to 1.5 eV?

Answers

Answer:

To increase the maximum kinetic energy of electrons to 1.5 eV, it is necessary that ultraviolet radiation of 354 nm falls on the surface.

Explanation:

First, we have to calculate the work function of the element. The maximum kinetic energy as a function of the wavelength is given by:

K_(max)=(hc)/(\lambda)-W

Here h is the Planck's constant, c is the speed of light, \lambda is the wavelength of the light and W the work function of the element:

W=(hc)/(\lambda)-K_(max)\nW=((4.14*10^(-15)eV\cdot s)(3*10^8(m)/(s)))/(495*10^(-9)m)-0.5eV\nW=2.01eV

Now, we calculate the wavelength for the new maximum kinetic energy:

W+K_(max)=(hc)/(\lambda)\n\lambda=(hc)/(W+K_(max))\n\lambda=((4.14*10^(-15)eV\cdot s)(3*10^8(m)/(s)))/(2.01eV+1.5eV)\n\lambda=3.54*10^(-7)m=354*10^(-9)m=354nm

This wavelength corresponds to ultraviolet radiation. So, to increase the maximum kinetic energy of electrons to 1.5 eV, it is necessary that ultraviolet radiation of 354 nm falls on the surface.

An electric generator contains a coil of 140 turns of wire, each forming a rectangular loop 71.2 cm by 22.6 cm. The coil is placed entirely in a uniform magnetic field with magnitude B = 4.32 T and initially perpendicular to the coil's plane. What is in volts the maximum value of the emf produced when the loop is spun at 1120 rev/min about an axis perpendicular to the magnetic field?

Answers

Answer:

11405Volt

Explanation:

To solve this problem it is necessary to use the concept related to induced voltage or electromotive force measured in volts. Through this force it is possible to maintain a potential difference between two points in an open circuit or to produce an electric current in a closed circuit.

The equation that allows the calculation of this voltage is given by,

\epsilon = BAN \omega

Where

B = Magnetic field

A= Area

N = Number of loops

\omega= Angular velocity

Our values previously given are:

N = 140

A = 71.2*10^(-2)m*22.6*10^(-2)m=0.1609m^2

B = 4.32 T

\omega = 1120 rev / min

We need convert the angular velocity to international system, then

\omega = 1120 rev/min

\omega = 1120rev/min*(2\pi)/(1rev)*(1min)/(60sec)

\omega = 117.2rad/s

Applying the equation for emf, we replace the values and we will obtain the value.

\epsilon = BAN \omega

\epsilon = (4.32)(0.1609)(140)*117.2

\epsilon = 11405Volt

A helium balloon ride lifts up passengers in a basket. Assume the density of air is 1.28 kg/m3 and the density of helium in the balloon is 0.18 kg/m3. The radius of the balloon (when filled) is R = 4.9 m. The total mass of the empty balloon and basket is mb = 121 kg and the total volume is Vb = 0.073 m3. Assume the average person that gets into the balloon has a mass mp = 73 kg and volume Vp = 0.077 m3. 1)What is the volume of helium in the balloon when fully inflated? m3 2)What is the magnitude of the force of gravity on the entire system (but with no people)? Include the mass of the balloon, basket, and helium. N

Answers

Answer:

1) The volume of helium in the ballon when is fully inflated is 492.8070 m³

2) The magnitude of the force of gravity (with no people) is 869.3119 N

Explanation:

Given:

ρair = density of air = 1.28 kg/m³

ρhelium = density of helium = 0.18 kg/m³

R = radius of balloon = 4.9 m

mtotal = 121 kg

Vtotal = 0.073 m³

mp = average mass per person = 73 kg

Vp = 0.077 m³

g = gravity = 9.8 m/s²

Questions:

1) What is the volume of helium in the balloon when fully inflated, Vhelium = ?

2) What is the magnitude of the force of gravity on the entire system (but with no people), Fg = ?

1) The volume of helium in the ballon when is fully inflated

V_(helium) =(4)/(3) \pi R^(3) =(4)/(3) \pi *4.9^(3) =492.8070m^(3)

2) First, you need to calculate the mass of helium

m_(helium) =\rho _(helium) *V_(helium) =0.18*492.8070=88.7053kg

The magnitude of the force of gravity (with no people)

F_(g) =m_(helium) *g=88.7053*9.8=869.3119N

find the area of a right triangle with sides 15.0 cm, 20.0 cm, and 25.0 cm. express your answer with the correct number of significant figures

Answers

The area of this triangle can be calculated using herons formula since th three sides are given. It is expressed as:

A=sqrt( s(s-a)(s-b)(s-c))

where s is equal to a+b+c / 2

s=15 +20 +25 /2=30
A=sqrt( 30(30-15)(30-20)(30-25))
A= 150 cm^3

If i throw up an object up at 31 m/s, how long will it take to get to its highest point

Answers

Answer:

Explanation:

vf=vi+at

vf=31 m/s

vi=0 m/s

a=g=9.8 m/s2

t=?

vf-vi=at

vf-vi/a=t

t=vf-vi/a

t=31 m/s-0/9.8

t=3.16 s