PHYSICS HIGH SCHOOL

The steering wheel of a certain vehicle has a diameter of 34.6 cm, and it turns a shaft that is 8.9 cm in diameter. If a 94.8 N force is needed to turn the steering wheel, what torque is exerted on the wheel

Answers

Answer 1
Answer:

Answer: 164Nm

Explanation: the torque exerted on the wheel is given by the expression

Torque=force*radius(of steering wheel )

Given force =94.8N

Diameter of wheel=34.6cm

Radius =34.6/2 =17.3cm

to metre 17.3/10= 1.73m

Torque =94.8*1.73

=164Nm

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A fan uses 7A when connected to a 110V line. If electric power costs 10 cents per kilowatt-hour in this location, what is the cost of running the fan for 13 hours?

Answers

Power = current x voltage

So the power is 7 x 110 = 770 W = 0.77kW

0.77 x 13 = 10.01 kWh

10.01 x 10 cents = 100.1 cents (is this 1 dollar? Idk I use a different currency)

A tank with a flat bottom is filled with water to a height of 4 meters. What is the pressure at any point at the bottom of the tank? (You can ignore atmospheric pressure when calculating your answer.)A. 18.9 kPa
B. 9.8 kPa
C.39.2 kPa
D. 4.0 kPa

Answers

Answer

C.39.2 kPa


Explanation

The pressure in liquids depend on the depth or what we call the liquid column(h), the density of the liquid(σ) and the the acceleration due to gravity(g).

h = 4.00 m

σ = 1000 Kg/m³

g = 9.8m/s²


Pressure Is given by;

P = σgh

= 1000 × 9.8 × 4

= 39200 Pa

=39.2 KPa
P=pgh, remeber that g=9.8 , so ignoring the atmosheric pressure youwould just multiply 9.8x4 and you would get 39.2KPa

A car traveling with constant speed travels 150 km in 7200s. What is the speed of the car?

Answers

Speed= distance/time
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Answers

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The height of the Empire State Building is 318.00 meters. If a stone is dropped from the top of the building, what is the stone's velocity just before it strikes the ground?

Answers

This is a free-fall problem. This can be answered using one of the free-fall equations:

V^2 = 2gh or V = √(2gh)

Where V = velocity ; h = total height (given as 318m) ; g = acceleration due to gravity (as this is on Earth, let us use 9.8 m/s^2)

With the given values, we can substitute it into the equation directly like so:

V = √(2gh)
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Therefore the stone's velocity just before hitting the ground is 78.95 m/s.
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