PHYSICS COLLEGE

(a) Determine the electric field strength between two parallel conducting plates to see if it will exceed the breakdown strength for air (3 ? 106 V/m). The plates are separated by2.98 mm and a potential difference of 5575 V is applied. (b) How close together can the plates be with this applied voltage without exceeding the breakdown strength?

Answers

Answer 1

Answer:

Answer:

(a) 1.87×10⁶ V/m

(b) 1.12 mm closer

Explanation:

(a)

Electric Field = Electric potential/distance.

E = V/d ................... Equation 1

Where E = Electric Field, V = Electric potential, d = distance.

Given: V = 5575 V, d = 2.98 mm = 0.00298 m.

Substitute into equation 1

E = 5575/0.00298

E = 1.87×10⁶ V/m

(b)

without exceeding the breakdown strength,

make d the subject of equation 1

d = V/E.............. Equation 2

Given: E = 3×10⁶ V/m, V = 5575 V

Substitute into equation 2

d = 5575/3000000

d = 1.86 mm.

the plate will be = 2.98-1.86 = 1.12 mm closer

Related Questions

A train accelerates at -1.5 m/s2 for 10 seconds. If the train had an initialspeed of 32 m/s, what is its new speed?A. 17 m/sB. 15 m/sC. 47 m/sD. 32 m/s
What is gravity at north pole, South pole and at different point on the equatorial regions. Give reasoning for your answers why do you think it is different or same. Can you imagine same concept for the electric charge, yes or No
How would a spinning disk's kinetic energy change if its moment of inertia was five times larger but its angular speed was five times smaller
A remote-controlled car’s wheel accelerates at 22.7 rad/s2 . If the wheel begins with an angular speed of 10.3 rad/s, what is the wheel’s angular speed after exactly twenty full turns
A farmer is using a rope and pulley to lift a bucket of water from the bottom of a well. the farmer uses a force f1=57.5 n to pull the bucket of water upwards. the total mass of the bucket of water is f2= 3.9kg. -Calculate how much work Wg in J gravity does on the bucket filled with water as the farmer lifts it up the well. -Calculate the net work Wnet in J done on the bucket of water by the two forces F1 and Fg.

A rabbit is moving in the negative x-direction at 1.10 m/s when it spots a predator and accelerates to a velocity of 13.9 m/s along the negative y-axis, all in 1.20 s. Determine the x-component and the y-component of the rabbit's acceleration. (Enter your answers in m/s2. Indicate the direction with the signs of your answers.) HINT

Answers

Answer:

Explanation:

Initial velocity u = -1.1 i m /s ( along - ve direction )

final velocity = - 13.9 j

change in velocity = -13.9 j + 1.1 i

rate of change of velocity

acceleration

= (-13.9 j + 1.1 i) / 1.2

= -11.58 j + 0.916 i

x component

= 0.916 m /s²

y component

= - 11.58 m / s²

A 600W toaster, 1200W iron and a 100W bulb are all connected to household 120V circuit. a) find the current drawn by each applianceb) the resistance of the heating element in the iron
c) the total cost of running all of the appliances non-stop for 5 days if the electricity rate is $0.1 per KW-Hr.

Answers

Answer:

(a) %a, 10 A, 0.833 A

(b) 12 ohm

Explanation:

Power of toaster, P1 = 600 W

Power of iron, P2 = 1200 W

Power of bulb, P3 = 100 W

V = 120 V

As they are in household circuit, so they are connected in parallel, so the voltage is same for all.

(a) Use the formula P = V x i

Current in toaster, i1 = P1 / V = 600 / 120 = 5 A

Current in iron, i2 = P2 / V = 1200 / 120 = 10 A

Current in bulb, i3 = P3 / V = 100 / 120 = 0.833 A

(b) Resistance of heating element of iron is R2.

V = i2 x R2

120 = 10 x R2

R2 = 12 ohm

= (600 + 1200 + 100) x 24 x 5 = 228000 Wh = 228 KWh

Cost of 1 KWh = $0.1

Cost of 228 KWh = 0.1 x 228 = $22.8

_______________________________

Answer:

(a). Toaster = 5A

Iron = 10A

Bulb = 0.833A

(b). R2 = 12Ω

(c). $ 22.8

_______________________________

Explanation:

Given,

Power of Toaster, P1 = 600W

Power of Iron, P2 = 1200W

Power of Bulb, P3 = 100W

Potential difference = 120V

They all are connected in parallel combination because they all are household circuits so that the voltage is same for all appliances in the circuit.

★Solution of(a)

By using the formula of powerwe can find out the current.

P=V×I

Here, power is directly proportional to the potential difference and electric current flowing through the circuit.

[.°.I=P/V]

Here,electriccurrent is inversely proportional to the potential differenceandelectric currentisdirectly proportional topower.

Current in Toaster, I1 = P1/V = 600/120 = 5A

Current in Iron, I2 = P1/V = 1200/120 = 10A

Current in Bulb, I3 = P1/V = 100/120 = 0.833A

★Solutionof(b)

Resistance of Heating coil of Iron

By using theformula of Ohm's Law we can find out the resistance of heatingcoil of iron.

V=I×R

Here, the potential difference is directly proportional to the current carrying wire and potential difference is directly proportional to the resistance off the wire present in the Iron.

[.°.R=V/I]

Here, resistance is directly proportional to the potential difference and resistance is inversely proportional to the electric current.

R=V/I

=> R = 120/10

.°. R = 12Ω

★Solutionof(c)

Total consumption of Energy in 24 hours for 5 days = (600W + 1200W + 100W) × 24 hours × 5 days

= 228000Wh

= 228kWh

When the cost of 1kWh = $ 0.1

So,

The cost of 228 kWh = $ 0.1 × 228 = $ 22.8

_______________________________

A motorcycle is following a car that is traveling at constant speed on a straight highway. Initially, the car and the motorcycle are both traveling at the same speed of 19.0m/s , and the distance between them is 52.0m . After t1 = 5.00s , the motorcycle starts to accelerate at a rate of 5.00m/s^2. a. How long does it take from the moment when the motorcycle starts to accelerate until it catches up with the car? In other words. b. Find t2−t1

Answers

Answer:

$t\approx4.561\ s$

Explanation:

Given:

initial speed of car and motorcycle, $v=19\ m.s^(-1)$

initial distance between the car and motorcycle, $s=52\ m$

time after which the motorcycle starts to accelerate, $t_1=5\ s$

rate of acceleration of motorcycle, $a=5\ m.s^(-2)$

The initially the relative velocity of the motorcycle is zero with respect to car.

Now using the equation of motion in the relative quantities:

$s=u.t+(1)/(2) .a.t^2$

here:

$s =$ relative distance of motorcycle with respect to the car

$u=$ initial relative velocity of the motorcycle with respect to the car

$t=$ time taken to cover the distance gap from the car.

$52=0+0.5* 5* t^2$

$t\approx4.561\ s$

A runner first runs a displacement A of 3.20 km due south, and then a second displacement B that points due east. (a) The magnitude of the resultant displacement A + B is 5.38 km. What is the magnitude (in m) of B?

Answers

Answer: 4,438.96m

Explanation:

(kindly find attachment below)

From the attachment below, it can be seen that the resultant displacement and the other 2 displacements form a right angle triangle, with A+B as the hypotenus, 3.2km as the opposite and the displacement B as the adjacent.

By using phythagoras theorem

H² = O² + A²

(5.38)² = (3.20)² + B²

28.944 = 10.24 + B²

B² = 28.944 - 10.24

B² = 18.7044

B = √18.7044

B = 4.439km to meter is 4.439 * 1000 = 4,438. 96m

Answer:

B = 4325 m

Explanation:

Resolving the displacement into x and y components.

Let north = positive y component

East = positive x component

So,

Rx = B

Ry = -3.20 km

Magnitude of the resultant displacement is

R = √(B^2 + (-3.20)^2)

R is given as R = 5.38 km

Making B the subject of formula;

B = √(R^2 - (-3.20)^2)

B = √(5.38^2 - (-3.20)^2)

B = 4.325 km

B = 4325 m

Write as ordinary number 3 x 10^0

Answers

Answer:

Explanation:

10⁰ = 1 because anything to the power of 0 is 1.

3×1= 3

The position of a particle changes linearly with time, i.e. as one power of t, as given by the following: h(t) = ( 4.1 t + 5.5 ) meters. Find the speed of the particle, in meters per second.