Consider the following balanced chemical equation. 4 KO 2 + 2 H 2 O ⟶ 4 KOH + 3 O 2 How is the rate of appearance of O 2 , Δ [ O 2 ] Δ t , related to the rate of disappearance of KO 2 ?

Answers

Answer 1

Answer:

The appearance of Oxygen molecule is directly related or dependent to the rate of disappearance of potassium superoxide (KO2).

The rate of appearance of O2 is directly related to the rate of disappearance of KO2 because potassium superoxide (KO2) has oxygen molecule which is attached to the potassium so when the potassium reacts with water molecules, the potassium hydroxide (KOH ) and oxygen molecules is formed.

If the chemical reaction occurs then we get oxygen molecules so we can conclude that appearance of Oxygen molecule is directly related or dependent to the rate of disappearance of potassium superoxide (KO2).

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Answer 2

Answer:

Answer : The rate of appearance of $O_2$ related to the rate of disappearance of $KO_2$ is,

$(d[O_2])/(dt)=-(3)/(4)(d[KO_2])/(dt)$

Explanation :

The general rate of reaction is,

$aA+bB\rightarrow cC+dD$

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The expression for rate of reaction will be :

$\text{Rate of disappearance of A}=-(1)/(a)(d[A])/(dt)$

$\text{Rate of disappearance of B}=-(1)/(b)(d[B])/(dt)$

$\text{Rate of formation of C}=+(1)/(c)(d[C])/(dt)$

$\text{Rate of formation of D}=+(1)/(d)(d[D])/(dt)$

$Rate=-(1)/(a)(d[A])/(dt)=-(1)/(b)(d[B])/(dt)=+(1)/(c)(d[C])/(dt)=+(1)/(d)(d[D])/(dt)$

From this we conclude that,

In the rate of reaction, A and B are the reactants and C and D are the products.

a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.

The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.

The given rate of reaction is,

$4KO_2+2H_2O\rightarrow 4KOH+3O_2$

The expression for rate of reaction :

$\text{Rate of disappearance of }KO_2=-(1)/(4)(d[KO_2])/(dt)$

$\text{Rate of disappearance of }H_2O=-(1)/(2)(d[H_2O])/(dt)$

$\text{Rate of formation of }KOH=+(1)/(4)(d[KOH])/(dt)$

$\text{Rate of formation of }O_2=+(1)/(3)(d[O_2])/(dt)$

The overall rate expression is:

$\text{Rate of reaction}=-(1)/(4)(d[KO_2])/(dt)=-(1)/(2)(d[H_2O])/(dt)=+(1)/(4)(d[KOH])/(dt)=+(1)/(3)(d[O_2])/(dt)$

Now we have to determine the rate of appearance of $O_2$ related to the rate of disappearance of $KO_2$ .

$-(1)/(4)(d[KO_2])/(dt)=+(1)/(3)(d[O_2])/(dt)$

or,

$+(1)/(3)(d[O_2])/(dt)=-(1)/(4)(d[KO_2])/(dt)$

$(d[O_2])/(dt)=-(3)/(4)(d[KO_2])/(dt)$

Thus, the rate of appearance of $O_2$ related to the rate of disappearance of $KO_2$ is,

$(d[O_2])/(dt)=-(3)/(4)(d[KO_2])/(dt)$

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20 g of sugar is stirred into a beaker containing 100 g of water. After the sugar has completely dissolved, the solution is put on a scale. What is the mass of the solution?

Answers

The mass of the solution of sugar and water is 120 grams.

What is mass?

Mass is the quantity of matter of a physical body.

The mass of the sugar is given is 20g

The mass of the water is 100 g.

100 + 20 = 120 gram

Thus, the mass of the solution of sugar and water is 120 grams.

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The mass of the solution should be 120g since 20g of sugar were added to 100g and 100+20=120.
I hope this helps. Let me know in the comments if anything is unclear.

Why is CCl4 a nonpolar molecule, but PCl3 is a polar molecule?

Answers

The CCl₄ molecule has a tetrahedral geometry. It is a symmetrical molecule. The polarised bond thus cancels out each other due to the geometry of the molecule and that is why CCl₄is nonpolar.

Chlorine has a higher electronegativity than phosphorous. As a result, the chlorine atom has a partial negative charge relative to phosphorous. Since all three chlorine atoms pull electrons from the phosphate atom, the molecule is a polar molecule.

The reason why CCl₄is not soluble in water is because it is not soluble in polar solvents. Both PCl₃ and water are polar molecules. This is due to their shape and the electronegativity difference between the H and O molecules in water and the P and Cl molecules in PCl₃. Therefore, PCl₃in water is soluble.

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If you follow the octet rule, you know that an element must have 8 outside (or valence) electrons to be energetically favorable.

In CCl4, the carbon molecule forms four bonds; one for each chlorine atom. Each bond contains 2 electrons, so it is satisfied.

In PCl3, Phosphorous forms only 3 bonds with chlorine, which means in order to have 8 valence electrons, it also has a lone pair of electrons, not bonded with chlorine.

Now, in CCl4, picture the shape of the molecule like a plus sign, with the carbon in the middle and the chlorine at the four ends. It is symmetrical, and therefore is nonpolar.

In PCl3, the lone pair electrons push, so to speak, the 3 chlorine atoms away, making a T-shaped molecule. Since the chlorine is more electronegative than carbon, the molecule is unbalenced, making it polar.

describe the process that ice on mount everest goes through when being heated from 10 degree fahrenheit to 305 degree kelvin. then explain how the energy requiresment change at different steps of the heating curve. and what are the energy transfers that happen in the ice on mount everest everest?

Answers

I think the ice is warmed from 10 degrees Fahrenheit to 32 degrees Fahrenheit. The ice then melts (I believe 333kj/kg K) and then it warms up to 305 K. For that this occurs the heat capacity of the water is 4.19 kj/kg K.

Which statement best describes the collisions of gas particles according to the kinetic-molecular theory? a. When particles pass close enough to one another, their attractions pull them together, and then they bounce apart with no gain or loss of energy.
b. As particles travel in straight lines, their paths sometimes meet, and then they bounce apart with no gain or loss of energy.
c. When particles pass close enough to one another, their attractions pull them together, and then they bounce apart with a loss of energy.
d.As particles travel in straight lines, their paths sometimes meet, and then they bounce apart with a loss of energy.

Answers

Answer:

b. As particles travel in straight lines, their paths sometimes meet, and then they bounce apart with no gain or loss of energy.

Explanation:

Kinetic - molecular theory -

According to this theory , gas is considered to be as a large number of very small particles , which moves randomly , and due to this randomness collisions occurs , as the particles collide with each other and the wall of the container .

During these collisions , there is no loss or gain of energy , there is only transfer of energy .

Answer:

As particles travel in straight lines, their paths sometimes meet, and then they bounce apart with no gain or loss of energy.

Explanation:

Was right on edge

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