PHYSICS HIGH SCHOOL

Speakers A and B are vibrating in phase. They are directly facing each other, are 6.69 m apart, and are each playing a 75.0-Hz tone. The speed of sound is 343 m/s. What is the distance from speaker A to the first point on the line between the speakers where constructive interference occurs?

Answers

Answer 1

Answer:

Answer:

3.117 m

Explanation:

Given that:

the distance of separation between speaker A and speaker B (L) = 6.69 m

Frequency (F) = 750 -Hz tone

Velocity of speed of sound = 343 m/s

The distance from Speaker A to the first point (L₁) on the line can be calculated by using the formula:

$L_1=(L-A)/(2)$

where A = $(Velocity ofthe sound (V))/(Frequency (F))$

we have:

$L_1=(L-(V)/(F) )/(2)$

$L_1=(6.69-(343)/(750) )/(2)$

$L_1=(6.69-0.457 )/(2)$

$L_1=(6.233 )/(2)$

$L_1= 3.1165 m$

$L_1=3.117 m$

∴ the distance from speaker A to the first point on the line between the speakers where constructive interference occurs = 3.117 m

Related Questions

A person can jump a maximum horizontal distance (by using a 45◦ projectile angle) of 5 m on Earth. The acceleration of gravity is 9.8 m/s 2 . What would be his maximum range on the Moon, where the free-fall acceleration is g 6 ? Answer in units of m
The diagram shows a swinging pendulum.Which best explains what happens to the motion of the pendulum?A. The mechanical energy transforms to thermal energy as the pendulum slows and eventually stops moving. B. The mechanical energy disappears as the pendulum slows and eventually stops moving. C. The pendulum will continue moving at the same speed until someone stops it because energy cannot be destroyed. D. The pendulum will slow down but will never stop moving because energy cannot be destroyed.
Two cars collide at an intersection. Car A, with a mass of 1900 kg, is going from west to east, while car B, of mass 1500 kg, is going from north to south at 17.0 m\s. As a result of this collision, the two cars become enmeshed and move as one afterwards. In your role as an expert witness, you inspect the scene and determine that, after the collision, the enmeshed cars moved at an angle of 60.0degrees south of east from the point of impact.Part A WAS: How fast were the enmeshed cars moving just after the collision? I got 8.66 for velocity in part a which was CORRECT but i can't figure out PART B??...Part B:How fast was car A going just before the collision
What is the kinetic energy of a 1.0-kg ball moving at 3.0 m/s?
Polluted water can contribute to

A student measured the specific heat of water to be 4.29 J/g.Co. Theliterature value of the specific heat of water is 4.18 J/g.Co. What was the
student's percent error? *
A) .0256%
B) 2.56%
C) 2.63%
D) .0263%

Answers

Answer:

2.63 %.

Explanation:

Given that,

The calculated value of the specific heat of water is 4.29 J/g.C

Original value of specific heat of water is 4.18 J/g.C.

We need to find the student's percent error. The percentage error in any quantity is given by :

$P=\frac{|\text{original value-calculated value}|}{\text{original value}}* 100\n\nP=(4.29-4.18)/(4.18)* 100\n\nP=2.63\%$

So, the student's percent error is 2.63 %.

The student's percent error in measuring the specificheat of water is 2.63%.

The specificheat is the amount of heat required to increase the temperature of 1 kg of mass by 1 degree Celsius.

Given:

Experimental Value = 4.29 J/g°C (student's measured value)

Accepted Value = 4.18 J/g°C (literature value)

The percent error can be calculated using the formula:

Percent Error = ((Experimental Value - Accepted Value) / Accepted Value)×100

Substitute the given values in the above formula and calculate the percenterror:

Percent Error = [(4.29 - 4.18) / 4.18] × 100

Percent Error = (0.11 / 4.18) × 100

Percent Error = 2.63%

The student's percent error in measuring the specificheat of water is approximately 2.63%.

Therefore, the student's percent error in measuring the specific heat of water is 2.63%.

To know more about the specificheat, click here:

brainly.com/question/31608647

#SPJ3

The diagram below shows a 1.5 kilogram kitten jumping from the top of a 1.80 meter high refrigerator to a 0.90 meter highcounter.
Refrigerator
Counter
CO
The kitten's gravitational potential energy on top of the refrigerator is greater, but what is the kitten's gravitational
potential energy on top of the counter? Assume gravity as 10, if needed.

Answers

Answer:

E = 27 J

Explanation:

It is given that,

Mass of a kitten is 1.5 kg

Initially, it was at a height of 1.8 m refrigerator and finally jumps to a 0.9 m height counter.

We need to find the kitten's gravitational potential energy on top of the counter. Potential energy is possessed due to the position of an object. It can be given by :

$E=mgh$

g is acceleration due to gravity

$E=1.5\ kg* 10\ m/s^2* 1.8\ m\nE=27\ J$

So, the kitten's gravitational potential energy on top of the counter is 27 J.

Can you think of a scenario when the kinetic and gravitational potential energy could both be zero ? Describe or draw how this could be possible below

Answers

Both kinetic and gravitational potential energy can become zero at infinite distance from the Earth.

Consider an object of mass m projected from the surface of the Earth with a velocity v.

The total energy of the body on the surface of the Earth is the sum of its kinetic energy $(1)/(2) mv^2$ and gravitational potential energy $-(GMm)/(R^2)$ .

here, M is the mass of the Earth, R is the radius of Earth and G is the universal gravitational constant.

The gravitational potential energy of the object is negative since it is in an attractive field, which is the gravitational field of the Earth.

The energy of the object on the surface of the earth is given by,

$E_i=(1)/(2) mv^2-(GMm)/(R^2)$

As the object rises upwards, it experiences deceleration due to the gravitational force of the Earth. Its velocity decreases and hence its kinetic energy decreases.

The decrease in kinetic energy is manifested as an equal increase in potential energy. The potential energy becomes less and less negative as more and more kinetic energy is converted into potential energy.

At a height h from the surface of the Earth, the energy of the object is given by,

$E_h=(1)/(2) mv_h^2-(GMm)/((R+h)^2)$

The velocity $v_h$ is less than v.

When h =∞, the gravitational potential energy increases from a negative value to zero.

If the velocity of projection is adjusted in such a manner that the velocity decreases to zero at infinite distance from the earth, the object's kinetic energy also becomes equal to zero.

Thus, it is possible for both kinetic and potential energies to be zero at infinite distance from the Earth. In this case, kinetic energy decreases from a positive value to zero and the gravitational potential energy increases from a negative value to zero.

The picture above shows 3 sets of balloons, all with a particular charge. Which of the picture(s) is true? Explain. Then explain why the other 2 pictures are incorrect. Make sure to explain all 3 sets.

Answers

Among all of the others Picture 3 is correct.

We know, Like charges repel each other whereas unlike charges attract each other, In picture 3 they are like charges (both are positive) so, we can repulsion hence, picture is correct!

In picture 1, they are unlike charges, & showing repulsion which is wrong, same In picture 2, they are like charges & showing attraction so they are wrong as well

Hope this helps!

A car rolls down a hill from rest and reaches a velocity of 18.0 m/s in a distance of 25.0m. Find the acceleration of the cart.

Answers

Answer:

I’m so sorry I tried solving it but I don’t understand it can you explain the question a little bit more ty

Explanation:

it is said that a fool and his money ate soon parted.Suppose we place the fool and gold brick in the middle of a frictionless,frozen lake (Galileo's ideal frozen lake).How can the fool rescue himself?Is he still a fool?

Answers

He could theoretically push the gold brick away from himself, and due to Newton's 3rd law (Every action has an equal and opposite reaction), the same amount of force would recoil back at him from the gold brick. As a result, he will move in the opposite direction from the gold brick, and since it as an ideal frozen lake (meaning there is no friction present), he will keep going until he reaches the edge of the lake.

And I don't know if he's still a fool. That's up to you.

Other Questions

The gravitational strength on Earth is less than the gravitational strength on Jupiter. What will happen to a satellite when it travels from Earth to Jupiter? a Its mass will increase. b Its mass will decrease. c Its weight will increase. d Its weight will decrease.

What conditions are typcial of the soil the deeper we dig into it?

A graph of the motion of a pendulum shows that it swings from +5 centimeters to -5 centimeters for each cycle. What is the amplitude of the pendulum?

What activities can you do on Jupiter?!