How do I identify rational and irrational numbers?

Answers

Answer 1

Answer:

Answer: An irrational number is a number that is NOT rational. It cannot be expressed as a fraction with integer values in the numerator and denominator. When an irrational number is expressed in decimal form, it goes on forever without repeating.

Answer 2

Answer: An irrational number can be written as a decimal, but not as a fraction. An rational number can be written as a ratio.

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Whats the value of 5y if -2(3y+5)=-4

Answers

-2 (3y + 5) = -4
3y + 5 = -4 / -2
3y + 5 = 2
3y = 2 - 5
3y = -3
y = -1

5y = (-1)*5
5y = -5

5y=-5 is the value look below for the work

PLEASE HELP ME!! WILL GIVE MUCH POINTS!!

Answers

A is the answer as (-4,8), (2,6), and many others are also possible solutions.

The correct answer is A, i think because y = 12 and x= 4, 4×3=12, and you can switch any numbers like y = 24 and x = 8, it fits the equation.

Train A is traveling at 39 mph. Train B is traveling at 65 mph how man more hours will it take for train A than train B to travel 195 miles

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Train A will take 2 more hours than train B. Train A will take 5 hours while train B will only take 3 hours.

on call 3.5 hour $10 talk time 1/2 hour $1.25 what is the unit rate in dollar per hour for each company

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48. On call = 3.5 hours for 10 dollars=> ½ hour for 1.25 dollars.Now, let’s solve the unit rate for each companyfirst = 3.5 hour / 10 dollars=> 10 / 3.5=> Unit rate is 2.9 dollars/hrSecond company = ½ hour for 1.25 dollars=> 1.25 / .5=> 0.25 dollars / hr.Thus, the first company pays better than the second one because it pays 2.9 dollars every hour of talk compare to the 2nd one which pays only 0.25 dollars per hr.

What is the property of 93+(68+7)

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associative property is the answer.

Find k if (x-3) is a factor of $k^(2) x^(2) -kx-2$ .

Answers

$w(x)=k^2x^2-kx-2\n\n(x-3)\ is\ a\ factor\ w(x)\ then\ w(3)=0.\n\nSubstitute:\n\nk^2\cdot3^2-k\cdot3-2=0\n9k^2-3k-2=0\n9k^2-6k+3k-2=0\n3k(3k-2)+1(3k-2)=0\n(3k-2)(3k+1)=0\iff3k-2=0\ \vee\ 3k+1=0\n3k=2\ \vee\ 3k=-1\n\n\underline{\underline{k=(2)/(3)\ \vee\ k=-(1)/(3)}}$

k can be (-1/3) or (2/3).
since (x-3) is a factor. if you put x=3 in the equation, it must be equal to zero. So the equation becomes (9k2 - 3k -2 = 0). if you solve this you will get k=(-1/3) and k=(2/3). You can substitute this k in the original equation and check, (x-3) is a factor.

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