What happens to the negative charges
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Answers

Answer 1
Answer:

Answer:

The correct option is C) spreads out over a large area on the object.

Explanation:

In physics, a ground can be described as a reservoir object in which charge can be stored. Grounding refers to the removal of charge in an object by using the ground object. When an object with excess if charge is placed on the ground object, the electrons are transferred from the charges object to the ground object. This charge begins to spread evenly in the ground object with the passage of time.


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A star has a size of 0.1 solar radius. How many times larger is the sun than this star?

Answers

-- The sun's radius is 10 times the radius of that other one.

-- The sun's surface area is 100 times the surface area of that other one.

-  The sun's volume is 1,000 times the volume of that other one.

Why cant the moon be eclipsed when it is halfway between the nodes of its orbit?

Answers

The reason why the moon can't be eclipsed when it's halfway between the nodes of the orbit because the moon's orbit is at it's maximum deviation, meaning that it is leaving it's course from the sun's path, which would make the shadow fall way below or above the moon. Because of that, the moon can't eclipsed.


Final answer:

The Moon cannot be eclipsed when it is halfway between the nodes of its orbit due to its 5° tilt relative to the ecliptic. Eclipses can only happen during 'eclipse season' when the Moon's path crosses the ecliptic. The apparent varying sizes of the Moon and Sun from Earth also factor into whether an eclipse can occur.

Explanation:

The Moon cannot be eclipsed when it is halfway between the nodes of its orbit because of the tilt in its orbit relative to the ecliptic, or the path of the Sun on the celestial sphere. The Moon's orbit is tilted by about 5° relative to the ecliptic. So, if you imagine two hula hoops with a common center, representing the orbits of the Moon and Sun, they are tilted slightly towards each other. This means that most months, the Moon is above or below the ecliptic plane and thus cannot enter into Earth's shadow for an eclipse to occur.

Only when the path of the Moon crosses the ecliptic, during what's known as an 'eclipse season', can eclipses occur. This happens twice a year. In other words, an eclipse can only happen if the Moon is at or very near to one of the nodes of its orbit when it is at full for a lunar eclipse or new for a solar eclipse.

An additional factor causing the Moon to avoid being eclipsed is the varying apparent sizes of the Sun and the Moon from our viewpoint. At times, the Moon appears smaller than the Sun, meaning it can't entirely cover the Sun even with perfect alignment for a total solar eclipse to occur. This is known as an 'annular eclipse' that leaves a ring of sunlight visible around the Moon.

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What is the law of reflection?

Answers

You can observe this law in practice if a ray of light reflects off of a flat mirror

Law of reflection states that both direction of both incoming and outgoing rays of light make the same angle with respect to surface normal.
The law of reflection are, as follows:

The incident Ray, the reflected Ray and the normal to the reflection surface at the point of the incidence lie in the same plane.

If this does not make since than I hope you know I tried.

The potential energy of a 40 kg cannon ball is 14000 J. How high was the cannon ball to have this much potential energy?

Answers

From the information given, cannon ball weighs 40 kg and has a potential energy of 14000 J.

 We need to find its height.

We will use the formula P.E = mgh

Therefore h = P.E / mg

where P.E is the potential energy,

 m is mass in kg,  

g is acceleration due to gravity (9.8 m/s²)

 h is the height of the object's displacement in meters.

h = P.E. / mg

h = 14000 / 40 × 9.8

h = 14000 / 392

h = 35.7

Therefore the canon ball was 35.7 meters  high.



Final answer:

The height of the cannon ball to have 14000 J of potential energy is approximately 357.14 meters. This is calculated using the formula for potential energy: PE = mgh, and solving for 'h'.

Explanation:

The potential energy (PE) of an object is given by the formula PE = mgh, where 'm' is the mass of the object, 'g' is the acceleration due to gravity (standard approximate value is 9.8 m/s² on Earth), and 'h' is the height. In your question, we want to find the height 'h'. Given that the potential energy is 14000 J and the mass of the cannon ball is 40 kg, we can rearrange the formula to solve for 'h': h = PE / (m*g).

So, inputting the given values, h = 14000 J / (40 kg * 9.8 m/s²). Solving this, we find that the height is approximately 357.14 meters. This means the cannon ball was at around this height to have 14000 J of potential energy.

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Your shopping cart has a mass of 65 kilograms, In order to accelerate the shopping cart down an aisle at 0.3 m/sec2, what force would you need to use or apply to the cart?

Answers

remember Newton's second law: F=ma

to get the force in newtons, mass should be in kg and acceleration in m/s^2

conveniently, we don't need to convert units

we just need to multiply the two to get the force

65* 0.3 = 19.5 kg m/s^2 or N

if significant digit is an issue, the least number if sig figs is 1 so the answer would be 20 N

Final answer:

To accelerate a shopping cart with a mass of 65kg at a rate of 0.3 m/sec2, you would need to exert a force of 19.5 Newtons, according to Newton's second law of motion.

Explanation:

The subject of this problem is physics, specifically the concept of force, mass, and acceleration within the domain of Newton's second law of motion. The law states that the force needed to accelerate an object is equal to the mass of the object multiplied by the desired acceleration.

Given the mass of the cart is 65 kilograms and the acceleration is 0.3 m/sec2, you can calculate the required force using the formula:
Force = mass * acceleration.

So, Force = 65 kg * 0.3 m/sec2 = 19.5 Newtons. Therefore, you would have to exert a force of 19.5 Newtons to accelerate the shopping cart at the specified rate.

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A beaker of vegetable oil contains a beam of light that is aimed at a surface at an angle of 34 degrees as shown. If the index off refraction of the oil is 1.47, what is the angle of reflection?

Answers

Answer:

Angle of reflection of light is 34 degree

Explanation:

As per law of reflection of light we know that

angle of incidence of light = angle of reflection of light

So here we know that

angle of incidence on the surface of oil is given as

\theta_i = 34 degree

so we know that

\theta_i = \theta_r

so here we can say that reflection angle of light will be same as angle of incidence

\theta_r = 34 degree

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