There were 88 vendors at the craft fair. They needed to set up an equal number in each of the rows and needed 4 flags to mark each row. How many rows and flags were needed?
Answers
Answer:
22 rows and 22 flags are needed
Step-by-step explanation:
Total number of vendors = 88
Existing number of rows and flags= 4
Number of rows and flags needed= 88/4 =22
Answer:
4rows and 16flags
Step-by-step explanation:
Since there were 88 vendors at the craft fair and 4flags on each rows. To set up equal number of vendors on each row, we will use the expression;
Number of vendors per row = Total number of vendors/total number of flags per row = 88/4 = 22 vendors
If there are 22 vendors in a rows and there are 88vendors in total, the total of rows will be;
Total number of vendors/number of vendors per row
= 88/22
= 4 rows
If there are four rows in total and 4flags in each row, the total of flags needed will be;
Total number of row × total flag per row
= 4×4
= 16flags
This shows that there are 4rows and 16flags were needed.
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Which equation represents a nonlinear function?
Answers
Answer:0.028
Step-by-step explanation:
Answer:
0.028
Step-by-step explanation:
I used a calculator.
Answers
2/4x - 14/4 = 4...multiply by 4 to get rid of fractions (this is optional)
2x - 14 = 16...add 14 to both sides
2x = 16 + 14
2x = 30...divide by 2
x = 30/2
x = 15
Answers
8p + 4 = 4p + 7 <== simplified form
Answers
y-y1=m(x-x1)
points are (x1,y1) (1,5) m=2/5
y-5=2/5(x-1)
How many seconds did it take for the object to hit the ground?
How many seconds did it take for the object to reach 1000 feet
Answers
Answer:
time = 0 seconds
Time to hit ground = 7.906 seconds
time = 0 seconds
Step-by-step explanation:
t = 0
-16(0)^2 +1000 = 1000
Time for ball to reach ground:
-16t^2 +1000 = 0
-16t^2 = -1000
t^2 = -1000/-16
t = squareRoot (-1000/-16) = 7.906 seconds
f(t) = 4(t − 1)2 + 3; the minimum height of the roller coaster is 1 meter from the ground
f(t) = 4(t − 1)2 + 2; the minimum height of the roller coaster is 2 meters from the ground
f(t) = 4(t − 1)2 + 2; the minimum height of the roller coaster is 1 meter from the ground
Answers
f(t) = 4(t² - 2t) + 7
f(t) - 7 = 4(t² - 2t - __)
t² ⇒ t * t
2t ⇒ 2 * 1t
1² ⇒ 1 * 1
f(t) - 7 + 4(1) = 4(t² - 2t + 1)
(t-1)(t-1) = t(t-1) -1(t-1) = t² - t - t + 1 = t² - 2t + 1
f(t) = 4(t-1)² + 3
Answer:
A f(1) =4(1)^2 – 8(1) +7 min height 3
Step-by-step explanation:
The function is a parabola, and the problem asks to transform the equation into f(t)=a(x-h)2 + k
Given f(t) = 4t2 -8t +7
= (4t2 - 8t + 4) + 7 - 4
=4 (t2 - 2t + 1) + 3
= 4 (t-1) 2 +3
This removes C and D from the viable choices.
Differentiating the f(t),
f’(t) = 8t – 8, the maximum/minimum value occurs at f’(t) = 0
0 = 8t – 8
t = 1
determining if maximum or minimum, f”(t) > 0 if minimum, f”(t) < 0 maximum
f”(t) = 8 > 0, therefore minimum
f(1) =4(1)^2 – 8(1) +7
= 3
Therefore, minimum height is 3.