Given that a 90% confidence interval for the mean height of all adult males in Idaho measured in inches was [62.532, 76.478]. Use this to answer all parts. What was the point estimate used to estimate the mean height of all adult males in Idaho?

Answers

Answer 1
Answer:

The point estimate used to estimate the mean height of all adult males in Idaho was 69.505 inches.

Calculation of the estimation of the point

Since Given that a 90% confidence interval for the mean height of all adult males in Idaho measured in inches was [62.532, 76.478].

So, the estimation of the point is

= (62.532 + 76.478) / 2

= 69.505 inches

Learn more about mean here: brainly.com/question/1863752

Answer 2
Answer:

Answer:

The point estimate used to estimate the mean height of all adult males in Idaho was 69.505 inches.

Step-by-step explanation:

The point estimate is the halfway point of the confidence interval, that is, the lower bound added to the upper bound, and then this sum is divided by 2. So

Lower bound: 62.535

Upper bound: 76.478

Point estimate:

P_(e) = (62.535 + 76.478)/(2) = 69.505

The point estimate used to estimate the mean height of all adult males in Idaho was 69.505 inches.


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In this equation what do i have to change to make x equal 0 instead of 1/4
2√x+4-2=3

Answers

To solve for x:
- add 2 to both sides
2/x+4=5
- subtract 4 from both sides
2/x=1
- divide both sides by 2
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Of interest is whether the percent of managers at High Tech Inc. that pay over $8 per day for lunch is the same as the percent of technicians. Sixty managers are surveyed and forty-six of them pay over $8 per day for lunch. One hundred forty-nine technicians are surveyed and ninety-eight of them pay over $8 per day for lunch. The hypothesis test to use is Group of answer choices matched or paired samples two proportions independent group means, population standard deviations unknown independent group means, population standard deviations known.

Answers

Answer:

comparison of two sample proportions independent

Step-by-step explanation:

Given that the percent of managers at High Tech Inc. that pay over $8 per day for lunch is the same as the percent of technicians.

The data can be given as follows:

The samples are as follows

Managers             60                149

Who paid >8        46                  98

Hence we compare sample proportions here.

The appropriate test would be

comparison of two sample proportions independent

2. 4x - 2y = -6
-6x + 2y = 2

Answers

Answer:

x = 2, y =7

Step-by-step explanation:

4x - 2y = -6

-6x + 2y = 2

Add the equations together

4x - 2y = -6

-6x + 2y = 2

-----------------------

-2x = -4

Divide each side by -2

-2x/-2 = -4/-2

x = 2

now find y

-6x+2y =2

-6(2) +2y =2

-12+2y =2

Add 12 to each side

-12+12+2y = 2+12

2y =14

Divide by 2

2y/2 =14/2

y =7

Suppose you are climbing a hill whose shape is given by the equation z = 900 − 0.005x2 − 0.01y2, where x, y, and z are measured in meters, and you are standing at a point with coordinates (120, 80, 764). The positive x-axis points east and the positive y-axis points north. (a) If you walk due south, will you start to ascend or descend? ascend descend Correct: Your answer is correct.

Answers

Answer:

Ascend

Step-by-step explanation:

In order to solve this problem, we are going to use some principles of vector calculation. The concepts we are going to use are Partial derivatives, gradient vector, velocity vector, direction vector, and directional derivative.

The gradient vector is a vector that describes how is the 'slope' in the space of a multivariable function at a specified point; it is built as a vector of partial derivatives. The vector velocity is a vector that describes the direction and speed of the movement of a body, if we make the velocity a unitary vector (a vector whose norm is 1), we obtain the direction vector (because we are not considering the real norm of the vector, just direction). Finally, the directional derivative is a quantity (a scalar) that describes the slope that we get on a function if we make a displacement from a particular point in a specific direction.  

The problem we have here is a problem where we want to know how will be the slope of the hill if we stand in the point (120, 80, 764) and walk due south if the hill has a shape given by z=f(x,y). As you see, we have to find the directional derivative of z=f(x,y) at a specific point (120, 80, 764) in a given displacement direction; this directional derivative will give us the slope we need. The displacement direction 'u' is (0,-1): That is because 'y' axis points north and our displacement won't be to the east either west (zero for x component), just to south, which is the opposite direction of that which the y-axis is pointing (-1 for y component). Remember that the direction vector must be a unitary vector as u=(0,-1) is.

Let's find the gradient vector:

z=900-0.005x^2-0.01y^2\n(\partial z)/(\partial x)=-0.005*2*x=-0.01x\n(\partial z)/(\partial y)=-0.01*2*y=-0.02y\n \nabla (z)=(-0.01x,-0.02y)

Evaluate the gradient vector at (120,80) (764 is z=f(120,80); you may confirm)

\nabla (z(120,80))=(-0.01*120,-0.02*80)=(-1.2,-1.6)

Finally, find the directional derivative; if you don't remember, it can be found as a dot product of the gradient vector and the direction vector):

D_(u,P_0)= \nabla (z)_(P_0)\cdot u\nD_(u,P_0)= (-1.2,-1.6)\cdot (0,-1)=1.6

As you see, the slope we find is positive, which means that we are ascending at that displacement direction.

There are twenty classes at each of two middle schools. The number of students in each class at each school is shown in the dot plots below.Number of Students in Each Class at Poplar Middle School
A dot plot. A number line going from 20 to 29 labeled Number of Students. There are 3 dots above 20, 5 above 21, 7 above 22, 4 above 23, 1 above 24, and 0 above 25, 26, 27, 28, and 29.

Number of Students in Each Class at Oak Middle School
A dot plot. A number line going from 20 to 29 labeled Number of Students. There is 1 dot above 20, 2 above 21, 2 above 22, 4 above 23, 3 above 24, 2 above 25, 2 above 26, 2 above 27, 1 above 28, and 1 above 29.

Which statement correctly compares the mean number of students for the data in the plots?
There are about 2 more students in each class at Poplar Middle School than at Oak Middle School.
There are about 2 more students in each class at Oak Middle School than at Poplar Middle School.
There are about 5 more students in each class at Poplar Middle School than at Oak Middle School.
There are about 5 more students in each class at Oak Middle School than at Poplar Middle School.

Answers

The dot plot is missing, so i have attached it.

Answer:

B: there are about 2 more students in each class at Oak Middle School than at Poplar Middle School.

Step-by-step explanation:

From the dot plot attached, we can find the average number of students per class for each school.

For Poplar Middle School;

Total number of students = (20 × 3) + (21 × 5) + (22 × 7) + (23 × 4) + (24 × 1) = 435 students.

There are 20 classes.

Thus;

average number of students per class = 435/20 = 21.75

For Oak Middle School;

Total number of students = (20 × 1) + (21 × 2) + (22 × 2) + (23 × 4) + (24 × 3) + (25 × 2) + (26 × 2) + (27 × 2) + (28 × 1) + (29 × 1) = 483

Average number of students per class ; 483/20 = 24.15

Difference in average = 24.15 - 21.75 = 2.40

This implies that there are about 2 more students in each class at Oak Middle School than at Poplar Middle School.

Answer:

da answer is B lesss goooo

Step-by-step explanation:

Please help me I’ve been stuck for hours

Answers

Answer/Step-by-step explanation:

Given that a and b are two corresponding sides of two similar figures, it follows that the ratio of their areas = a²/b².

We would use the above knowledge to solve the questions given as follows:

✔️The first pair similar of shapes:

Missing area = x cm²

Therefore,

x/9 = 8²/4²

x/9 = 64/16

x/9 = 4

Cross multiply

x = 4 × 9

x = 36 cm²

✔️The second pair similar of shapes:

Missing area = x cm²

Therefore,

x/240 = 8²/32²

x/240 = 64/1,024

Cross multiply

x*1,024 = 64*240

x*1,024 = 15,360

Divide both sides by 1,024

x = 15,360/1,024

x = 15 cm²

✔️The third pair similar of shapes:

Missing area = x cm²

Therefore,

x/40 = 3²/2²

x/40 = 9/4

Cross multiply

x*4 = 9*40

x*4 = 360

Divide both sides by 4

x = 360/4

x = 90 cm²