A concave lens can only form a. A. real image. B. reversed image. C. virtual image. D. magnified image.
Answers
C. virtual image.
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Special relativity questions?1.) A rocket is moving at 1/4 the speed of light relative to Earth. At the center of this rocket, a light suddenly flashes. To an observer at rest on Earth a. the light will reach the front of the rocket after it reaches the back of the rocket. b. the light will reach the front of the rocket at the same instant that it reaches the back of the rocket. c. the light will reach the front of the rocket before it reaches the back of the rocket. 2.) A rocket is moving at 1/4 the speed of light relative to Earth. At the center of this rocket, a light suddenly flashes. To an observer at rest in the rocket a. the light will reach the front of the rocket before it reaches the back of the rocket. b. the light will reach the front of the rocket at the same instant that it reaches the back of the rocket. c. the light will reach the front of the rocket after it reaches the back of the rocket. 3.) An astronaut in an inertial reference frame measures a time interval Δt between her heartbeats. What will observers in all other inertial reference frames measure for the time interval between her heartbeats? a. Δt b. less than Δt c. more thanΔt d. The answer depends on whether they are moving toward her or away from her. 4.) You are a passenger on a spaceship. As the speed of the spaceship increases, you would observe that a. the length of your spaceship is getting shorter. b. the length of your spaceship is not changing. c. the length of your spaceship is getting longer. 5.) A star is moving towards the earth with a speed at 90% the speed of light. It emits light, which moves away from the star at the speed of light. Relative to us on earth, what is the speed of the light moving toward us from the star? a. 0.90c b. 1.9c c. 1.20c d. 1.1c e,) c
Answers
2cos2(θ)=1
cos2(θ)=1/2
2θ=arc cos1/2
2θ=60 degrees
θ=30 degrees
definition please:)
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Any star that is fusing hydrogen in its core and maintains a stable equilibrium between the inward pressure from gravity and the outward pressure from core nuclear fusion is called the main sequence star.
The main sequence is a continuous and recognisable band of stars in astronomy that may be seen on maps of stellar colour against brightness.
A star produces thermal energy in its dense core area by nuclear fusing hydrogen into helium after condensation and ignition. The star's location on the main sequence at this moment in its existence is mostly based on its mass, but also on factors like its age and chemical makeup.
Main-sequence stars' cores are in a state of hydrostatic equilibrium, where the inward pressure of gravitational collapse from the surrounding layers balances the outward heat pressure of the hot core.
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Answer:
1,803,036.67 W
Explanation:
Data provided in the question:
People per hour that can be moved by lift = 49800
Height of movement, h = 190 m
Average mass per person = 70 kg
Now,
Power = Rate of doing work
Thus,
Power = ΔU
= mgh
here,
m = total mass
g = acceleration due to gravity
or
Power = (70kg × 49800)(9.8)(190)
or
Power = 6,490,932,000 J per hour
also,
Watt = Joule/second
Therefore,
Power = 6,490,932,000 ÷ 3600
= 1803036.67 W
Final answer:
To estimate the maximum total power needed for Squaw Valley ski area to move 49800 people per hour on their lifts, we calculate the work done per person per hour and then divide it by the time taken to travel vertically by 190 m. The estimated maximum total power needed is 3.31 x 10^8 W.
Explanation:
To estimate the maximum total power needed to move 49800 people per hour on a skilift at Squaw Valley, we can calculate the work done per person per hour and then divide it by the time taken to travel vertically by 190m. The work done is equal to the potential energy gained, which is given by the formula mgh, where m is the average mass per person (70 kg), g is the acceleration due to gravity (9.8 m/s^2), and h is the vertical height gained (190 m). Multiplying this by the number of people per hour gives us the total work done per hour. Dividing this by the time taken to travel the vertical height gives us the maximum power needed. The power is given by the formula P = W/t, where W is the work done and t is the time taken.
Using the given values, we have:
Work done per person per hour: (70 kg) x (9.8 m/s^2) x (190 m) = 128660 J
Total work done per hour: 128660 J x 49800 = 6.40 x 10^9 J
Time taken to travel vertically by 190m: 190 m / (9.8 m/s^2) = 19.39 s
Maximum power needed: (6.40 x 10^9 J) / (19.39 s) = 3.31 x 10^8 W
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Answers
Answer: 20 minutes
Explanation:
Given the following :
Average speed of train = 120km/hr
Distance = 40km.
The time take by the train moving at an average speed of 120km/hr to cover a distance of 40km due is ;
Recall:
Speed = distance / time
Therefore,
Time taken = distance covered / speed
Time taken = 40km / 120km/hr
Time taken = 1/ 3 hr
Therefore, 1/3 rd of an hour equals
1/3 × 60 = 20 minutes.
Time taken) 20 minutes
Time taken by tain to cover distance is 20 minutes as:
Distance= 40 km
Speed= 120 km/h
Time= distance/speed
= 40/120
= 1/3 hour
= 20 min
or =0.33 hrs
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10^0.8 ≅ 6.309573445
The 7.5 earthquake is approximately 6.3 times as intense as the 6.7 earthquake
How to figure it using your equation:
M = log(i/s)
10^M = i/s
i = s·10^M
ratio of the intensities of the two earthquakes = (s·10^7.5)/(s·10^6.7)
= 10^(7.5-6.7)
= 10^0.8
≅ 6.3:1
Answer:
6.31 times ( approx )
Explanation:
Given formula to find the magnitude of an earthquake is,
Where,
I = intensity of the earthquakebeing measured,
S = theintensity of a standard earthquake,
By the above formula,
Since, S is constant,
If M = 7.5,
Then intensity of the earthquake,
If M = 6.7,
Then intensity of the earthquake,
Hence, the earthquake that measures 7.5 on the Richter scale is 6.3 times more intense than the earthquake that measures 6.7.