The temperature drop of air if air is assumed to be an ideal gas for which C_p = ⁷/₂R is; Δt = 1546 K
We are given;
Final velocity; v₂ = 300 m/s
C_p = ⁷/₂R
At constant pressure, the change in enthalpy is;
Δh = C_p × Δt
Now, from first law of thermodynamics;
h₂ + (v₂²/2) = h₁ + (v₁²/2)
We are told initial velocity is negligible and as such v₁ = 0 m/s
Thus;
h₂ + (v₂²/2) = h₁ + 0
(h₁ - h₂) = (v₂²/2)
Thus; Δh = v₂²/2
Finally;
C_p × Δt = v₂²/2
Δt = v₂²/2/(C_p)
Δt = (300²/2)/(⁷/₂R)
where R is ideal gas constant = 8.314 Kj/kg.mol
Thus;
Δt = (300²/2)/(⁷/₂ × 8.314)
Δt = 1546 K
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Answer:
ΔH+U²/2=0
and
ΔH=×ΔT
∴to get the temperature drop of air, you make ΔT subject of the formula
ΔT=-U²/2Cp
=-300²/2××8.314
∴ΔT=-1546K
Explanation:
Answer:
A. True
Explanation:
Answer:
Option D
Material has uniform properties throughout.
Explanation:
A homogeneous material is a material that exhibits uniform properties throughout and these properties cannot be separated. These materials can be metals, ceramics or alloys that exhibit similar properties throughout. The similar properties may include evaporation point, density and other properties.
Answer:
The horizontal conductivity is 41.9 m/d.
The vertical conductivity is 37.2 m/d.
Explanation:
Given that,
Thickness of A = 8.0 m
Conductivity = 25.0 m/d
Thickness of B = 2.0 m
Conductivity = 142 m/d
Thickness of C = 34 m
Conductivity = 40 m/d
We need to calculate the horizontal conductivity
Using formula of horizontal conductivity
Put the value into the formula
We need to calculate the vertical conductivity
Using formula of vertical conductivity
Put the value into the formula
Hence, The horizontal conductivity is 41.9 m/d.
The vertical conductivity is 37.2 m/d.
Answer:
B) gate-source junction is reverse-biased
Explanation:
FET is described as an electric field that controls the specific current and is being applied to a "third electrode" which is generally known as "gate". However, only the electric field is responsible for controlling the "current flow" in a specific channel and then the particular device is being "voltage operated" that consists of high "input impedance".
In FET, the different "charge carriers" tend to enter a particular channel via "source" and exits through "drain".
Fluorescent lamps
Mercury-containing lamps
All of the above
Answer: D all above
Explanation:
Jus done it