the length of the base of a triangle is twice its height. if the area of the triangle is 4 square kilometers, find the height

Answers

Answer 1

Answer:

The height of the triangle is 2 kilometer.

A triangle is a 3-sided polygon. The sum of the angles in a triangle add up to 180 degrees. The sides of a triangle are the length, base and the hypotenuse.

The area of a triangle = $(1)/(2)$ × base × height

Let:

t represent the height of the triangle.

Base = 2 x t = 2t

Area = 4

4 = $(1)/(2)$ × 2t x t

Multiply both sides of the equation by 2

8 = 2t²

Divide both sides by 2

4 = t²

Find the square root of both sides of the equation

t = 2 kilometer.

To learn more, please check: brainly.com/question/24865193?referrer=searchResults

Answer 2

Answer: let the height = x

Base = 2x

Area of triangle = (1/2)*base*height

Area = (1/2)*2x*x = 4

x² = 4

x = √4

x = 2

Height = 2 km.

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Answers

Answer:

07(8 + 3) is the right answer

Will upvoteChoose the correct simplification of the expression a to the 12th power times b to the 8th power all over a to the 2nd power times b to the 4th power.

a10b4

a6b2

1 over a to the 10th power times b to the 4th power

1 over a to the 14th power times b to the 12th power

Answers

$(a^(12)b^(8))/(a^(2)b^(4))$

remember
(ab)/(cd)=a/c times b/d

also $(x^(m))/(x^(n))= x^(m-n)$

split it up with like terms

$(a^(12))/(a^(2))$ times $(b^(8))/(b^(4))$

do subtraction
for a's
12-2=10

b's
8-4=4

answe is $a^(10)b^(4)$

first one

Answer:

the first one. a^10b^4

Step-by-step explanation:

i just took the test and double checked it :)

If AXB has a measure of 100, and is its angle bisector, what is the measure of BXY?

Answers

since xy is the bisector of AXB so it divides the angle to two equal parts
so AXB=AXY+BXY and we know AxY and BXy are equal. so the amount of each of them is half of AXB that means 50

Calculate the slope of the line going through A(-4,3) and B(0,6) PLEASE ANSWER

Answers

Answer:

6-3/0-(-4)

=3/4

Step-by-step explanation:

Given two points of a line to find the slope, we use the formula.y2-y1/x2-x1 hence the answer above. Our xs are x2=0 x=-4 y2=6 y1=3

The equation of line c is y=-4/3-4 Line d includes the point (4,-4) and is perpendicular to line c . what is the equation of line d?

Answers

Assuming that you mean that the equation of line c is

$y=-(4)/(3)x-4$

We can deduce that the slope of line c is

$m_c=-(4)/(3)$

since the slope is the coefficient multiplying x in the equation of a line. Since we want line d to be perpendicular to line c, their slope must be in the following relationship:

$m_cm_d=-1 \iff m_d=-(1)/(m_c)=-(1)/(-(4)/(3))=(3)/(4)$

So, line d has slope 3/4 and passes through point (4,-4). Use the equation

$y-y_0=m_d(x-x_0)$

to find the equation of line d, where

$x_0=4,\quad y_0=-4,\quad m_d=(3)/(4)$

Given x is an acute angle with sin(x)=1/3, find the value of cos (4x) .

Answers

Answer:

Step-by-step explanation:

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