PHYSICS COLLEGE

A cylinder with a diameter of 2.0 in. and height of 3 in. solidifies in 3 minutes in a sand casting operation. What is the solidification time if the cylinder height is doubled? What is the time if the diameter is doubled?

Answers

Answer 1

Answer:

Answer:

3 min 55 sec is the solidification time if the cylinder height is doubled

7min 40 sec if the diameter is doubled

Explanation:

see the attachment

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As shown in the figure below, Greta walks 30m toward her truck. She notices she forgot hercoffee and returns back to the house. Her total travel time is 240 seconds.
30 m
30 in
What is Greta's average velocity over the 240s period?
m/s
What is Greta's average speed over the 240s period?
m/s

Answers

Average velocity: 0 m/s. Average speed: 0.25 m/s. Greta returns to her starting point, so her displacement is 0m.

Greta's average velocity is 0 m/s because she ends up at the same point where she started. Her displacement is 0 meters, and since velocity is displacement divided by time, her average velocity is 0 / 240 = 0 m/s.

Her average speed, on the other hand, is calculated using the formula: Average Speed = TotalDistance / Total Time.

Initially, Greta walks 30 meters away from her truck, and then she returns 30 meters back to her starting point. So, the total distance she covers is 30 + 30 = 60 meters. Her total travel time is 240 seconds.

AverageSpeed = 60 meters / 240 seconds = 0.25 m/s.

In summary, Greta's average velocity is 0 m/s because her net displacement is 0 meters. Her average speed is 0.25 m/s because she covers a total distance of 60 meters in 240 seconds.

To learn more about Average velocity here

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Answer:

0 | for Velocity

.25 | for speed

Explanation:

If R = 12 cm, M = 430 g, and m = 60 g , find the speed of the block after it has descended 50 cm starting from rest. Solve the problem using energy conservation principles. (Treat the pulley as a uniform disk.)

Answers

Answer:

Explanation:

Given

Radius of Pulley r=12 cm

mass of block m=60 gm

mass of Pulley M=430 gm

Block descend h=50 cm

Applying Conservation of Energy

Potential Energy of block convert to rotational Energy of pulley and kinetic energy of block

i.e.

$mgh=(1)/(2)I\omega ^2+(1)/(2)mv^2$

where I=moment of inertia

$I=mr^2$

and for rolling $\omega =(v)/(r)$

$mgh=(1)/(2)Mv^2+(1)/(2)mv^2$

$v^2=(2mgh)/(m+M)$

$v=\sqrt{(2mgh)/(m+M)}$

$v=\sqrt{(2* 60* 9.8* 0.5)/(430+60)}$

$v=\sqrt{(60* 9.8)/(490)}$

$v=√(1.2)$

$v=1.095 m/s$

he magnetic field strength at the north pole of a 2.0-cmcm-diameter, 8-cmcm-long Alnico magnet is 0.10 TT. To produce the same field with a solenoid of the same size, carrying a current of 1.9 AA , how many turns of wire would you need? Express your answer using two significant figures.

Answers

Answer: 3400

Explanation:

Given

Magnetic field, B = 0.1 T

Diameter of magnet, d = 2 cm = 0.02 m

Length of magnet, l = 8 cm = 0.08 m

Current of the magnet, I = 1.9 A

Number of turns needed, N = ?

To solve this problem, we would use the formula,

N = (LB) / (μI), where

μ = 1.257*10^-6 Tm/A, so that

N = (0.08 * 0.1) / (1.257*10^-6 * 1.9)

N = 0.008 / 2.388*10^-6

N = 3350

N ~ 3400

Therefore, the number of turns of wire needed is 3400

A revolutionary war cannon, with a mass of 2260 kg, fires a 21 kg ball horizontally. The cannonball has a speed of 105 m/s after it has left the barrel. The cannon carriage is on a flat platform and is free to roll horizontally. What is the speed of the cannon immediately after it was fired?

Answers

Answer:

0.97566 m/s

Explanation:

$m_1$ = Mass of cannon = 2260 kg

$v_1$ = Velocity of cannon

$m_2$ = Mass of ball = 21 kg

$v_2$ = Velocity of ball = 105 m/s

As the momentum of the system is conserved we have

$m_1v_1=m_2v_2\n\Rightarrow v_1=(21* 105)/(2260)\n\Rightarrow v_1=0.97566\ m/s$

The velocity of the cannon is 0.97566 m/s

The surface pressure of the atmosphere is about 14.7 psi (pounds per square inch). How many pounds per square yard does that amount to

Answers

Answer:

14.7 psi is equal to 19051.2 pounds per square yard.

Explanation:

Dimensionally speaking, a square yard equals 1296 square inches. Therefore, we need to multiply the atmospheric pressure by 1296 to obtain its equivalent in pounds per square yard. That is:

$p = 14.7\,(lbf)/(in^(2))* 1296\,(in^(2))/(yd^(2))$

$p = 19051.2\,(lbf)/(yd^(2))$

14.7 psi is equal to 19051.2 pounds per square yard.

Two violin strings are tuned to the same frequency 294 H. The tension in one string is then decreased by 2.0%. What will be the beat frequency heard when the two strings are played together?