How can a high school student have more momentum than a truck

Answers

Answer 1
Answer:

Answer:

When truck is at rest while student is under motion

Explanation:

Since it is obvious that the mass of a truck is more than that of a student, we know that momentum is a product of mass and velocity

P=mv where m represent mass, v is velocity. When the student has more speed than that of truck, he exerts more momentum. The only way a student can exert more momentum is by having more speed while the truck is at rest. In such case, the momentum of truck will be zero while momentum of student will have a value


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Tom left for his friend's house. He drove 60 km in an hour. When he got to John's house, he wondered how fast he had been driving. What formula would he use to determine his speed?

What two variables are being graphed?In what units is each variable measured?
What is the force of gravity on the rocket at the planet's surface?
What is the force of gravity on the rocket at a distance of two units (twice the planet's radius from its center)?
In general, how does the force of gravity pulling on the rocket change as the distance between it and the planet increases?

Answers


-- The relationship between the distance from the planet's center and the force of gravity on the ship has been graphed.  That's the reason for the labels on the axes.

-- The distance from the planet's center is labeled in multiples of the planet's radius.

The force of gravity on the ship is labeled in multiples of 1 million newtons.

-- The force of gravity on the rocket at the planet's surface  (1 radius from the center) is  4 million newtons. (about 899,203 pounds)

-- The force of gravity on the rocket at a distance of two units (twice the planet's radius from its center) is 1 million newtons.

--
In general, as the distance between the rocket and the planet increases, the force of gravity pulling on the rocket decreases. 

From our studies of the nature of gravity, we know that the force is inversely proportional to the square of the distance between the center of the rocket and the center of the planet.  We might not notice it from the graph
, because there's only one labeled point that clearly shows it.  (2radius, 1/4 of the surface force).

If we have been really attentive to our studies and have done all of our gravity homework, we know that the equation of the purple line on the graph is

  Force  =  (4 million newtons) / (Distance)²     for  Distance >= 1 radius.


A cylindrical rod of mass M. length L and radius R has two cords wound around it whose ends are ato the ceiling as shown. The rod is held horizontally with the two cords vertical. When the rod s mecase
cords unwind the rod rotates. Find the tension in the cords as they unwind.​

Answers

Answer:

T = mg/6

Explanation:

Draw a free body diagram (see attached).  There are two tension forces acting upward at the edge of the cylinder, and weight at the center acting downwards.

The center rotates about the point where the cords touch the edge.  Sum the torques about that point:

∑τ = Iα

mgr = (1/2 mr² + mr²) α

mgr = 3/2 mr² α

g = 3/2 r α

α = 2g / (3r)

(Notice that you have to use parallel axis theorem to find the moment of inertia of the cylinder about the point on its edge rather than its center.)

Now, sum of the forces in the y direction:

∑F = ma

2T − mg = m (-a)

2T − mg = -ma

Since a = αr:

2T − mg = -mαr

Substituting expression for α:

2T − mg = -m (2g / (3r)) r

2T − mg = -2/3 mg

2T = 1/3 mg

T = 1/6 mg

The tension in each cord is mg/6.

Why is it important for scientists to be curious?

Answers

it is important for scientists to be curious because they will never find out the answer to their curiosity unless they well find out
It's important for scientists to be curious because everyday we live in a specticul world. and as soon as we learn how to talk our language starts to get more and more advance. But then we start to ask question's that lead up to our curiosity. this is very important because we can make a difference in life. we can uncover new mysteries that appear based on a theory. 

I hopee this helped you 

a wagon is pulled at a speed of 0.40 m/s by a horse exerting an 1,800 newton horizontal force. what is the power of this horse.

Answers

1,800/0.40=4500 this is the equation you need F=ma then you take f which is 1800 and divided by a which is 0.40 to find m

Wispy, feathery clouds made mostly of ice crystals that form at high altitudes, usually above 6 kilometers.

Answers

Cirrus clouds are the clouds mostly made of ice becasue of the high altitudes           

A metal ball of mass 2 kg is supported by a massless inextensible string, 12 cm long. A horizontal force displaces the ball by 30oto the vertical so that the string remains taut. Find:a) the horizontal force.b) the tension in the thread.

Answers

As it is given that 2 kg mass is suspended by 12 cm long thread and then a horizontal force is applied on it so that it remains in equilibrium at 30 degree angle

So here we can use force balance in X and Y directions

now for X direction or horizontal direction we can use

F = Tsin30

for vertical direction similarly we can say

mg = T cos30

so here we first divide the two equations

(F)/(mg) = (sin 30)/(cos 30)

(F)/(mg) = tan 30

F = mg tan30

now plug in all values in the above equation

F = 2 * 9.8 * tan30

F = 11.3 N

Part b)

now in order to find the tension in the thread we can use any above equation

F = T sin30

11.3 = T sin30

T = (11.3)/(sin30)

T = 22.6 N

so tension in the thread will be 22.6 N