A hummingbird is flying toward a large tree that has a radius of 6 feet. When it is 33 feet from the center of the tree, its lines of sight form two tangents. What is the measure of the arc on the tree that the hummingbird can see?

Final answer:

The experimental probability of rolling the given results are: a. 0.16, b. 0.18, c. 0.22, d. 0.1. The correct answer is b. 0.18.

Explanation:

To find the experimental probability of rolling a given result, divide the frequency of that result by the total number of rolls. In this case, the frequency of rolling a 1 is 32, and the total number of rolls is 200. So the experimental probability of rolling a 1 is 32/200 = 0.16. Repeat this process for the other results:

• Experimental probability of rolling a 2: 36/200 = 0.18
• Experimental probability of rolling a 3: 44/200 = 0.22
• Experimental probability of rolling a 4: 20/200 = 0.1
• Experimental probability of rolling a 5: 30/200 = 0.15
• Experimental probability of rolling a 6: 38/200 = 0.19

Based on these calculations, the experimental probability of rolling the given results are:

• a. 0.16
• b. 0.18
• c. 0.22
• d. 0.1

Therefore, the correct answer is b. 0.18.

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Answer: D) 0.44

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Explanation:

Add up all the frequencies that correspond to outcomes that are more than 3

So we'll add up the last three frequencies (since they correspond to outcomes of 4, 5 and 6 all of which are greater than 3) to get 20+30+38 = 88

We have 88 occurrences of rolling either a 4, a 5 or a 6. This is out of 200 rolls total.

The empirical (or experimental) probability of getting more than 3 on the die is 88/200 = 0.44

By using sample space we can say that complement of 4 heads in the toss of 4 coins is at least one tail .

What is sample space ?

set of all possible outcomes experiment is called sample space .

To find compliment of 4 heads we will first find sample space Sample space= S

= { HHHH, HHHT, HHTH, HHTT, HTHH, HTHT, HTTH, HTTT, THHH, THHT, THTH, THTT TTHH, TTHT, TTTH, TTTT }

Given case is 4 heads Say A= { HHHH}

Now we can calculate A complement as

A' = S-A

= { HHHH, HHHT, HHTH, HHTT, HTHH, HTHT, HTTH, HTTT, THHH, THHT, THTH, THTT TTHH, TTHT, TTTH,TTTT }- { HHHH}A'={ HHHT, HHTH, HHTT, HTHH, HTHT, HTTH, HTTT, THHH, THHT, THTH, THTT TTHH, TTHT, TTTH,TTTT }

By using sample space we can say that complement of 4 heads in the toss of 4 coins is at least one tail .

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Answer:

b i believe the answer is

Given :-

• Ben is 4 times as old as Ishaan.

• Ben is 6 years older than Ishaan.

To find :-

• age of Ben

Let :-

• Ishaan age be x
• Ben age be 4x

Solution :-

✪According to question:-

Ben is 6 years older than Ishaan

So :-

• Ben age - Ishaan age = 6 years

put supposed values

• 4x - x = 6
• 3x = 6
• x = 6 ÷ 3
• x = 6/3
• x = (2 × 3)/3
• x = 2/1
• x = 2

Original Ages :-

• Ishaan age = x
• Ishaan age = 2 years

• Ben age = 4x
• Ben age = 4(2)
• Ben age 4 × 2
• Ben age = 8 years

✪Verification :

1st condition:-

• Ben age - Ishaan age = 6 years

put original ages

• 8 - 2 = 6
• 6 = 6

LHS=RHS

Hence verified !

Required answer :-

Ben's age =8years

Answer:

No, a square is NOT the cross section of a rectangular and triangular prism.

Step-by-step explanation:

Prisms have a uniform cross-section and are named after their cross-section. Hence, the cross-section of a rectangular prism is a rectangle and the cross-section of a triangular prism is a triangle. The only prism with a square cross-section is a cube.