A rancher needs to enclose two adjacent rectangular​ corrals, one for cattle and one for sheep. If the river forms one side of the corrals and 390 yd of fencing is​ available, find the largest total area that can be enclosed.

Answers

Answer 1
Answer:

Width  = 55 yards

Length   =  165 yards

Maximized area   =  9075 sq yd

Step-by-step explanation:

Here, the total length of fencing available  =  390 yd

Let L = length of the side parallel to river

W = width of other 3 sides.

So, total fencing L  +  3 W =  390 yd

or, L  = 390 - 3 W

Now, Area of the field  = L x W

= (390 - 3 w) (W)

or, A  =  -3 W² + 330 W

The maximum value of above function is  at W = ((-b)/(2a) ) = (-330)/(2* (-3))  =  55

So, W = 55 yards

Now, L = (390 - 3 (55) ) =  165 yards

Now, maximized area  = L x W

= 55 x 165  = 9075 sq yds


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why is the following incorrect? 296 divided by 6 equals 48 remainder 8.Write your answer before you complete the calculation

Answers

296 divided by 6 equals 49 remainder 2

Uses of partial fraction in daily life

Answers

Uses of partial fraction in daily life consist of money and other uses may consist of food portions and also weighing kilos grams and ounces

Final answer:

Partial fractions are used in numerous aspects of everyday life, especially in fields requiring mathematical calculations. This includes engineering, calculus, computer science, signal processing, and electrical circuits. While we may not directly observe their use, their applications make many of our daily operations possible.

Explanation:

The concept of partial fractions is widely used in numerous aspects of our daily life, especially in fields that require mathematical calculations. Partial fractions make complex mathematical processes simpler and easier to solve.

For instance, in the field of engineering, partial fractions are used to simplify complex fractions in control system design, particularly in Laplace Transform. Moreover, it's also used in calculus to integrate rational functions.

In the realm of computer science, partial fractions can assist with algorithm efficiency when dealing with fractions or rational numbers. They are also used in signal processing and electrical circuits, which are a major part of our daily life as most electronics operate on these principles.

In everyday life, the use of partial fractions might not be directly observed but their applications in various fields make many of our daily life operations and technologies possible.

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If the perimeter of an equilateral triangle is 24 inches, find a side of the triangle

Answers

Divide 24/3 since it's an equilateral triangle, all sides and angles are equal. THe answer is 8.

It is 8 because you take 24 and divide it by 3

Divide £56 in a ratio of 5:3

Answers

$1.43 is equal to £1

so...

1.43*56 would be $80.84


this would be around...$7.98 in US currency


Mr.mays drove 20 miles in 24 minutes. At this rate ,how many miles did he drive in 6 minuts

Answers

20 miles .... 24 minutes
x miles ... 6 minutes

We would like to know how many miles did he drive in 6 minutes (x miles). You can calculate this in the following way:

20 * 6 = 24 * x
120 = 24 * x     /24
x = 120 / 24
x = 5 (miles)

The result is 5 miles.

The suspect was spotted riding the swings earlier in the day. Each swing can hold a maximum weight of 500 pounds. In order to reach the maximum weight, you would have to double the weight of the suspect and add 20 pounds less than the weight of George. Write and solve an equation to represent the suspect's weight.

Answers

Answer:

s = 260 - g/2

Step-by-step explanation:

Given the following :

Maximum weight swing can hold = 500 pounds

Let suspect's weight = s

George's weight = g

To reach maximum weight :

Double weight of suspect + (George's weight - 20)

Hence, equation:

2s + (g - 20) = 500

2s + g - 20 = 500

2s + g = 500 + 20

2s + g = 520

2s = 520 - g

Divide through by 2

s = 260 - g/2

The question can be represented by the equation 2S + G - 20 = 500, where S is the suspect's weight and G is George's weight. To solve for the suspect's weight, we need to know George's weight.

The question asks for an equation to determine the weight of the suspect based on given conditions. We can express the condition as a mathematical equation. If we let S be the weight of the suspect and G be the weight of George, the information gives us the equation 2S + G - 20 = 500. To solve for the suspect's weight, we will need the weight of George. Without this, there are an infinite number of solutions for S. However, if we were given George's weight, we could subtract 20 from it, subtract that value from 500, and then divide by 2 to get the suspect's weight. As an example, if George weighed 220 pounds, the suspect would weigh (500 - (220 - 20)) / 2 = 150 pounds.

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