The most soaring vocal melody is in Johann Sebastian Bach's Mass in B minor. In one section, the basses, tenors, altos, and sopranos carry the melody from a low D to a high A. In concert pitch, these notes are now assigned frequencies of 146.8 Hz and 880.0 Hz. (Use 343 m/s as the speed of sound, and 1.20 kg/m3 as the density of air.)a. Find the wavelength of the initial note.
b. Find the wavelength of the final note.
c. Assume the choir sings the melody with a uniform sound level of 70.0 dB. Find the pressure amplitude of the initial note.
d. Find the pressure amplitude of the final note.
e. Find the displacement amplitude of the initial note.
f. Find the displacement amplitude of the final note.

Answers

Answer 1
Answer:

Answer:

Detailed step wise solution is attached below

Explanation:

(a) wavelength of the initial note 2.34 meters

(b) wavelength of the final note 0.389 meters

(d) pressure amplitude of the final note 0.09 Pa

(e) displacement amplitude of the initial note 4.78*10^(-7) meters

(f) displacement amplitude of the final note 3.95*10^(-8) meters


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A uniform, solid sphere of radius 3.75 cm and mass 4.00 kg starts with a purely translational speed of 1.75 m/s at the top of an inclined plane. The surface of the incline is 3.00 m long, and is tilted at an angle of 26.0∘ with respect to the horizontal. Assuming the sphere rolls without slipping down the incline, calculate the sphere's final translational speed ????2 at the bottom of the ramp.

Answers

Answer:

v_2=4.53m/sv_2=4.53m/s

Explanation:

In order to solve the exercise it is necessary to apply the energy conservation equation,

The equation says the following,

mgdsin(\theta)+(1)/(2)mv^2_1=(1)/(2)mv^2_2+(1)/(2)Iw^2

Replacing the formula for I of a sphere, we have

mgdsin(\theta)+(1)/(2)mv^2_1=(1)/(2)mv^2_2+(1)/(2)(2)/(5)mr^2((v_2)/(r))^2

mgdsin(\theta)+(1)/(2)mv^2_1=(1)/(2)mv^2_2+(1)/(5)mv^2_2=(7)/(10)mv^2_2

(10)/(7)gdsin(\theta)+(5)/(7)v^2_1=v^2_2

In this way we get the expression

v_2=\sqrt{(10)/(7)gdsin(\theta)+(5)/(7)v^2_1}

We proceed to replace with the given values and obtain that

v_2=\sqrt{(10)/(7)*9.8*3sin(26))+(5)/(7)*1.75^2}

v_2=4.53m/s

v_2=4.53m/sv_2=4.53m/s

The equation says the following,

mgdsin(0) + 1/2mv2/1 = 1/2mv2/2 + 1/2Iw^2  

Replacing the formula for I of a sphere,

mgdsin(0) + 1/2mv2/1 = 1/2mv2/2 + 1/2 2/5mr^2 (v2/r)^2

mgdsin(0) + 1/2mv2/1 = 1/2mv2/2 + 1/5mv2/2 = 7/10mv2/2

10/7gdsin(0) + 5/7v2/1 = v2/2

In this way, we get the expression

v2 = sqrt(10/7gdsin(0) + 5/7v2/1)

v2 = sqrt(10/7 * 9.8 * 3sin(26)) + 5/7 * 1.75^2

v2 = 4.53m/s

Further Explanation  

The ball that rolls on the plane will experience two movements at once, namely the rotation of the axis of the ball and the translational field being traversed. Therefore, objects that do rolling motion have a rotational equation and a translational equation. The amount of kinetic energy possessed by the rolling body is the amount of rotational kinetic energy and translational kinetic energy. You will here learn about the ball rolling on a plane and incline.

An object can experience translational motion or rotational motion. Translational motion is the motion of objects whose direction is straight or curved. In translational motion using the concept of Newton II's law. While the rotational motion is the motion that has a rotation of a particular shaft. Rotational motion is caused by the torque, which is the tendency of a force to rotate a rigid body against a particular pivot point.

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Details

Grade: College

Subject: Physics

Keyword: object, ball, roll

A 72.0-kg person pushes on a small doorknob with a force of 5.00 N perpendicular to the surface of the door. The doorknob is located 0.800 m from axis of the frictionless hinges of the door. The door begins to rotate with an angular acceleration of 2.00 rad/s 2 . What is the moment of inertia of the door about the hinges?

Answers

Answer:

Moment of inertia will be I=2kgm^2

Explanation:

We have given mass of the person m = 72 kg

Radius r = 0.8 m

Force is given  F = 5 N

Angular acceleration \alpha =2rad/sec^2

Torque is given by \tau =F* r=5* 0.8=4N-m

We know that torque is also given by

\tau =I\alpha, here I is moment of inertia and \alpha is angular acceleration

So 4=I* 2

I=2kgm^2

For every increase in mass the gravitational force blank If the total mass increase by effective for the gravitational force

Answers

For every increase in mass, the gravitational force increases. Gravitational force is directly proportional to the mass of the object.

What is gravitational force?

Gravitational force is the force by which an object attracts other objects into its center of mass. Earth attracts other objects gravitationally and that keep everyone stand to the ground.

Gravitational force directly proportional to the mass and inversely proportional to the distance between the objects. The expression relating the force and mass is written as:

g = G m/r²

Where G is the universal gravitational constant.

Therefore, as the mass of the object increase, the gravitational force exerted also increases. Similarly massive object experience more gravitation force by earth.

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Answer:

Increases by the same amount.Increases by a factor of 4.

Explanation:

i took it

Which statement describes how a machine can help make work easier? It can put out more force than the input force by decreasing the distance over which force is applied. It can increase the amount of work performed if the output force is in the same direction as the input force. It can apply a greater output force over a greater distance compared to the input force and distance. It can increase the distance over which output force acts by applying less output force than input force.

Answers

Answer:

It can apply a greater output force over a greater distance compared to the input force and distance.

Explanation:

A machine helps to multiply force input and makes it easier to do work. Simple and complex machines are need to make work easier.

  • Most machines are designed to increase the input force by a system of mechanics.
  • Machines allow force to be applied over great distances and this allows for the input work done to be duly compensated for.

The statement describes how a machine can help make work easier, (c) It can apply a greater output force over a greater distance compared to the input force and distance is correct option.

A machine is a device designed to perform a specific task or work by using mechanical, electrical, or other forms of energy. Machines are created to make tasks easier, more efficient, or possible to accomplish that would be difficult or impossible to achieve using human effort alone.

They can range from simple tools like levers and pulleys to complex systems like engines and computers. Machines typically involve the conversion of input energy (such as human effort or electricity) into some form of output energy (such as mechanical motion or computation) to achieve a desired result.

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A beam of light, which is traveling in air, is reflected by a glass surface. Does the reflected beam experience a phase change, and if so, by how much is the phase of the beam changed?

Answers

The reflected beam experienced a phase change of about 180°.

What is reflection in the glass surface?

According to Snell's law, the light that incident on the glass surface will be reflected and transmitted at an angle equals to the angle of incidence.  

By the observation of refractive index of the glass for the normal incidence only 4% of the light is transmitted or reflected.

The light passing through glass is not only reflected on the front surface, but also on the back. For several times the light will gets reflected back and forth. So, the total reflectance through a glass window can be calculated as

                                    2·R / (1+R).

Thus, A light wave travelling in air is reflected by a glass barrier will undergo a  phase change of 180°, while light travelling in glass will not undergo a phase change if it is reflected by a boundary with air.

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Answer:

180 degree phase change

Explanation:

Why is there so much more carbon dioxide in the atmosphere of Venus than in that of Earth? Why so much more carbon dioxide than on Mars?

Answers

Explanation:

The reason for the more concentration of carbon dioxide in the atmosphere of Venus than in the Earth -

On the Earth , most amount of the carbon dioxide is in the ocean water and in sea sediments .

Considering Venus , in the planet Venus , there is no Ocean water , hence , carbon dioxide can not get dissolved into the water , hence , it is found in the atmosphere .

So , the escape velocity for carbon dioxide on Mars is smaller than Venus .