MATHEMATICS MIDDLE SCHOOL

How much money did Larry borrow from the bank?

Answers

Answer 1

Answer:

Answer:

$7,200

Step-by-step explanation:

started with 7,500

has 300 now

instead of going through the list just subtract what he has now and what he started with (7,500-300) to get how much he borrowed. 7,200

Answer 2

Answer:

$20

Step-by-step explanation:

I'm high a.f. but I'm certain it's $20

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Please tell me the answer

Answers

This is easy. You all need to do this:
100÷2 it equals 50.
You need to subtract one 50 from either Caroline/Mohamed(Take Caroline's for example)
Caroline = 50-16=34.
Then you add 16 to 50(Mohamed's)
50+16=66
Therefore, Caroline sold 34 tickets, however, Mohamed sold 66 tickets.
To prove: add 66+34
66+34=100

Mohamed sold 58, and Caroline sold 42.

Jazmin has 5 movies that are dramas, 8 comedy movies, and 11 adventure movies in her movie collection. What is the ratio of adventure movies to the total number of movies in her collection?

Answers

There are numerous important information's already given in the question. Based on those information's the answer to the question can be easily determined.
Number of movies that are drama = 5
Number of comedy movies = 8
Number of adventure movies = 11
Total number of movies that Jazmin has = 5 + 8 + 11
= 24
Then
Ratio of adventure movies to the total number of movies = 11:24
This ratio of 11:24 cannot be simplified further. So this is the answer to the given question. I hope the procedure is clear enough for you to understand.

The total number of movies in Jazmin's collection is:
5+ 8+ 11= 24

11 adventure movies: 24 movies

The ratio of adventure movies to the total number of movies in Jazmin's collection is 11:24~

Help this is really hard

Answers

(2^8 *3^-5* 6^0)^-2 * ((3^-2)/(2^3))^4 * 2^28

anything to the 0 power is 1

(2^8 *3^-5* 1)^-2 * ((3^-2)/(2^3))^4 * 2^28

using the power of power property to take the power inside

(2^(8*-2) *3^(-5* -2) * (3^-2*4)/(2^3*4) * 2^28

simplify

2^ -16 * 3^10 * 3^-8 /2*12 * 2^28

get rid of the division by making the exponent negative

2^-16 * 3^10 * 3^-8 *2*-12 * 2^28

combine exponents with like bases

2^(-16-12+28) * 3^(10-8)

2^(0) *3^2

anything to the 0 power is 1

1*9

$(2^8\cdot3^(-5)\cdot6^0)^(-2)\cdot\left((3^(-2))/(2^3)\right)^4\cdot2^(28)\n\n\text{use}\n(a\cdot b)^n=a^n\cdot b^n\n(a^n)^m=a^(nm)\n\left((a)/(b)\right)^n=(a^n)/(b^n)\n a^0=1\ for\ a\neq0\n\n=(2^8)^(-2)\cdot(3^(-5))^(-2)\cdot1^(-2)\cdot((3^(-2))^4)/((2^3)^4)\cdot2^(28)=2^((8)(-2))\cdot3^((-5)(-2))\cdot1\cdot(3^((-2)(4)))/(2^((3)(4)))\cdot2^(28)$

$=2^(-16)\cdot3^(10)\cdot(3^(-8))/(2^(12))\cdot2^(28)=(2^(-16)\cdot2^(28))/(2^(12))\cdot3^(10)\cdot3^(-8)\n\n\text{use}\ a^n\cdot a^m=a^(nm)\n\n=(2^(-16+28))/(2^(12))\cdot3^(10+(-8))=(2^(12))/(2^(12))\cdot3^2=1\cdot3^2=3^2=9\n\nAnswer:\ \boxed{9}$