A 0.157kg glider is moving to the right on a frictionless, horizontal air track with a speed of 0.850m/s . It has a head-on collision with a 0.306kg glider that is moving to the left with a speed of 2.26m/s . Suppose the collision is elastic.Find the magnitude of the final velocity of the 0.157kg glider.Find the magnitude of the final velocity of the 0.306kg glider.

Answers

Answer 1
Answer:

Answer:

V1 = -3.260 m/s,  V2 = 1.303 m/s

Explanation:

Let mass of the left glider m1 = 0.157 kg and velocity v1 = 0.850 m/s

mass of the right glider m2 = 0.306 Kg and v2 = -2.26 m/s (-ve sign mean it is opposite to direction of left glider)

To Find:  Final Velocity of Left Glider is V1=? m/s  and  Velocity of right Glider is V2 =? m/s  (After Collision)

from law of conservation of momentum and energy we deduce a formula:

V1 = (m1-m2) v1 /(m1+m2) + 2 m2 v2/(m1+m2)

V1 = (0.157 kg - 0.306 Kg) × 0.850 m/s / (0.157 kg + 0.306 Kg)  + 2 ×0.306 kg × -2.26 m/s / (0.157 kg + 0.306 Kg)

V1 = -0.273 -2.987

V1 = -3.260 m/s

and V2 Formula

V2 = (m2-m1) v2/(m1+m2) + 2 m1 v1/(m1+m2)

V2 = (0.157 kg - 0.306 Kg) × -2.26 m/s / (0.157 kg + 0.306 Kg)  + 2 ×0.157 kg × 0.850 m/s / (0.157 kg + 0.306 Kg)

V2 = 0.727 + 0.576

V2 = 1.303 m/s

-0.149,  0.463


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Answers

15.23.....................
I think it would be 15.23 not so sure but
hope this helps! (:

A flat circular coil having a diameter of 25 cm is to produce a magnetic field at its center of magnitude, 1.0 mT. If the coil has 100 turns how much current must pass through the coil?

Answers

Answer:

The current pass through the coil is 6.25 A

Explanation:

Given that,

Diameter = 25 cm

Magnetic field = 1.0 mT

Number of turns = 100

We need to calculate the current

Using the formula of magnetic field

B =(\mu_(0)NI)/(2\pi r)

I=(B*2\pi r)/(\mu N)

Where, N = number of turns

r = radius

I = current

Put the value into the formula

I=(1.0*10^(-3)*2\pi*12.5*10^(-2))/(4\pi*10^(-7)100)

I=6.25\ A

Hence, The current passes through the coil is 6.25 A

If the solution described in the introduction is cooled to 0 ∘c, what mass of kno3 should crystallize? enter your answer numerically in grams.

Answers

14 g is the solubility per 100 g water, since it is difficult to read the graph. 
Then, in 130 g H20 the solubility would be 14 g KNO3/100 g H2O x 130 g H2O = 18 g KNO3 
The question asks how much crystallizes. 
Initial 34.0 g minus 18.0 g still dissolved = 16.0 g crystallizes.

KNO3 of 10g will undergo crystallization at 0 °

Because the heavier the KNO3 mass will require a higher temperature in the dissolution process.

Further explanation

Potassium nitrate is a nitrate salt compound from potassium with the molecular formula KNO3. Potassium nitrate salt can be made by reacting potassium chloride with sodium nitrate. If the saturated solution each of the solution is mixed with each other, then it will form sodium chloride salt because NaCl in water is small, the salt will settle. By cooling the filtered filtrate KNO3 will undergo crystallization

This compound decomposes with oxygen evolution at 500 ° C according to the reaction equation:

2 NaNO3 (s) -> 2NaNO 2 (s) + O2 (g)

Crystallization is separation by forming crystals so that the mixture can be separated. A gaseous or liquid substance can cool or condense and form crystals because it undergoes a crystallization process. Crystals will also form from a solution that will be saturated with a certain solvent. The more the number of crystals, the better, because the less likely to be polluted by dirt.

Potassium Nitrate has a physical white powder that is easily soluble in water and odorless. Meanwhile, to analyze the structure and characteristics of Potassium Nitrate MM2 data processing is used in the Chemoffice 15.0 application. This data processing is used to determine the shape of compounds, types of bonds in molecular movement compounds and other parts that can not be observed directly by the eye without the aid of tools. And for the form of compounds in 2 dimensions and 3 dimensions used Chemdraw 15.0 and Chem3D 15.0 applications

Learn more

Potassium nitrate brainly.com/question/10847775

Crystallization brainly.com/question/2575925

Details

Grade: High School

Subject: Chemistry

Keyword: kno3, nitrate, crystallization

A spring has a spring constant of 1350 N/m. You place the spring vertically with one end on the floor. You then drop a 1.3 kg book onto it from a height of 0.8 m above the top of the spring. Find the maximum distance the spring will be compressed. Express your answer with the appropriate mks units.

Answers

Answer:

0.123 m.

Explanation:

From Hook's law,

The potential energy of the book = the energy stored in the spring.

mgh = 1/2ke².................. Equation 1

Where m= mass of the book, g = acceleration due to gravity, h = height, k = spring constant of the spring, e = distance of compression.

make e the subject of the equation

e = √(2mgh/k).................. Equation 2

Given: m = 1.3 kg, h = 0.8 m, k = 1350 N/m

Constant: g = 9.8 m/s²

Substitute into equation 2

e = √(2×1.3×0.8×9.8/1350)

e = √(20.384/1350)

e = √(0.0151)

e = 0.123 m.

Answer:

0.015m (downwards)

Explanation:

When the book is dropped on the top of the spring at that height, the potential energy (E_(P)) of the book is converted to elastic energy (E_(E)) on the spring thereby causing a compression on the spring. i.e

E_(P) = E_(E)

But;

The potential energy E_(P) of the mass (book), is the product of the mass(m) of the book, the height(h) from which it was dropped and the acceleration due to gravity (g). i.e

E_(P) = - m x g x h         [the -ve sign shows a decrease in height as the mass (book) drops]

Also;

The elastic energy (E_(E)) of compression of the spring is given by

E_(E) = (1)/(2) x k x c

Where;

c = compression length of the spring

k = the spring's constant

Substitute these values of E_(P) and E into equation (i) as follows;

- m x g x h = (1)/(2) x k x c             ----------------(ii)

From the question;

m =  1.3kg

h =  0.8m

Take g = 10m/s²

k =  1350N/m

Substitute these values into equation (ii) as follows;

- 1.3 x 10 x 0.8 = (1)/(2) x 1350 x c

- 10.4 = 675c

Solve for c;

c = - 0.015 m          [The negative sign shows that the spring actually compresses]

Therefore, the maximum distance the spring will be compressed is 0.015m (downwards of course).

(a) How fast and in what direction must galaxy A be moving if an absorption line found at 550 nm (green) for a stationary galaxy is shifted to 450 nm (blue) for A? (b) How fast and in what direction is galaxy B moving if it shows the same line shifted to 700 nm (red)?

Answers

Explanation:

For Part (a)

Since the apparent wavelength decreases hence galaxy moving towards the stationary observer.

Δλ/λ=v/c

=(v)/(c)\n v=(550-450)/(550)*3*10^(8)\n v=5.4545*10^(7)m/s

For Part (b)

Since the apparent wavelength increases hence galaxy moving towards the stationary observer.

Δλ/λ=v/c

=(v)/(c)\n v=(700-550)/(550)*3*10^(8)\n v=8.1818*10^(7)m/s

Which statement accurately describes the relationship between force and momentum?A. As the mass of an object increases its momentum increases, and it takes more force to change its motion.
B. As the velocity of an object increases, its momentum decreases and it takes less force to change its motion.
C. As the mass of an object increases its momentum decreases and it takes less force to change it motion
D. As the velocity of an object decreases its momentum increases and it takes more force to change its motion

Answers

As the mass of an object increases its momentum increases, and it takes more force to change its motion. So, option A.

What is meant by momentum ?

Mass in motion is quantified by momentum, which is the measure of the amount of mass in motion.

Here,

Momentum of an object, which is under motion can be defined as the product of the mass and velocity of the object.

Momentum, P = mv

According to Newton's second law, the force is defined as the rate of change of momentum, or the momentum per unit time.

F = dP/dt

So, force is proportional to the amount of momentum imparted on the object.

Therefore, if the mass or velocity of the object increases, it will eventually cause the momentum to be increased and as a result, the force required to exert on the object will increase.

Hence,

As the mass of an object increases its momentum increases, and it takes more force to change its motion. So, option A.

To learn more about momentum, click:

brainly.com/question/30677308

#SPJ7

Answer:

A

Explanation:

just did it