A mothball, composed of naphthalene (C10H8), has a mass of 1.52g. How many naphthalene molecules does it contain?
Answers
10 x (12.01 g/ mol) + 8 x (1.01 g/mol) = 128.12 g/mol
Divide the given mass by the molar mass to determine the number of moles of naphthalene present in the ball.
n = 1.52 g / 128.12 g/mol = 0.01186 mole
Multiply the number of moles to number of moles per mole.
(0.01186 mol) x (6.022 x10^23 molecules / mole) = 7.14 x 10^21 molecules
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Help please! How many significant figures are in the measurement 0.00440 grams? 6 5 3 2
Explain the connection between Earth's magnetic field and iron.
Answers
Compare the electrical conductivity of the aqueous product in the reaction to the electrical conductivity of the white solid that remains after the water is evaporated from the solution.
Write the chemical name of the base produced in the reaction.
State one change in reaction conditions that will increase the rate of the reaction.
Answers
Answer:
- Calcium is more conductive than calcium hydroxide.
- Calcium hydroxide.
- Addition of more either calcium or water to the reaction vessel
Explanation:
Hello,
In this case, based on the given reaction and information, calcium's electrical conductivity 0.298 106/(cm*Ω) which is a relatively high value compared to it its base has due to its large insolubility.
In addition, the name of the formed base is calcium hydroxide based on the IUPAC rules.
Moreover, the addition of more either calcium or water to the reaction vessel will generate more calcium hydroxide.
Best regards.
Answers
According to zeroth law of thermodynamics, when two objects are kept in contact, heat (energy) is transferred from one to the other until they reach the same temperature (are in thermal equilibrium). When the objects are at the same temperature there is no heat transfer.
So, at equilibrium, =
,
+
q=m×c×T, where q = heat energy, m = mass of a substance, c = specific heat (units J/kg∙K), T is temperature
=(15X13X4.19)+(148X88.3X4.19)
= 81.37 ° C
Answers
Moles=volume*concentration
=0.1*.83
=.083 Moles of HC2H3O2
Mole ratio between HC2H3O2 and CO2 is 1:1
This means .083 Moles of CO2
Mass =Moles*Rfm of CO2
=.083*(12+16+16)
=3.7grams
Final answer:
By utilizing stoichiometry, we can determine that the given volume and molarity of acetic acid (HC2H3O2) would produce approximately 3.65 grams of carbon dioxide (CO2). The calculation involves determining the moles of HC2H3O2 used, which equals the moles of CO2 produced, and converting that to grams using the molar mass of CO2.
Explanation:
The amount of carbon dioxide produced can be determined through stoichiometry, using the provided balanced chemical equation and molarity (M) of the acetic acid HC2H3O2. According to the balanced chemical equation, one mole of NaHCO3 reacts with one mole of HC2H3O2 to produce one mole of CO2. In other words, the moles of HC2H3O2 used equals the moles of CO2 produced.
First, calculate the moles of HC2H3O2 by multiplying the given volume (0.100 L) by its molarity (0.83 mol/L): 0.100L x 0.83 mol/L = 0.083 mol.
So, according to the stoichiometric ratio, 0.083 mol of HC2H3O2 would produce 0.083 mol of CO2. If you want your answer in grams, note that the molar mass of CO2 is approximately 44.01 g/mol. Multiply the moles of CO2 by its molar mass: 0.083 mol x 44.01 g/mol = 3.65g.
So, the amount of CO2 produced would be 3.65 grams.
Learn more about Chemical Stoichiometry here:
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oxygen
water vapor
Answers
Other planets have an atmosphere, but Earth's is unique because it has large amounts of oxygen.
Answers
Thus, the following species exist in this buffer solution:
H2CO3: present in great quantity, therefore, being a weak acid, it suffers little ionization;
H +: from the ionization of H2CO3;
HCO3-: also present in high quantity, from ionization of H2CO3 and dissociation of salt (NaHCO3);
Na +: from ionization of NaHCO 3;
If this solution is added a small concentration of acid, its ionization will occur, generating H + cations, which will react with the HCO3- anions present in the medium, giving rise to non-ionized carbonic acid. There is no change in pH.
If a base is added, OH- anions will be generated. These ions combine with the H + cations from the ionization of H2CO3. Thus, the OH- anions are neutralized, maintaining the pH of the medium.
To better understand the annex follows: