In setting up to do RSA public key encryption, let p = 3 and q = 23 be the two initial prime numbers. Also let e = 5 be a randomly chosen value less than and relatively prime to Φ(n).Given the values above, compute the following. You must show all work to receive full credit:
What is the value of n ?
What is Φ(n) ?
Show that the value d = 9 is the modulo Φ(n) inverse of e.
What is the corresponding public key for these values?
What is the corresponding private key for these values?
Answers
Answer:
1. 69
2. 44
3. See explanation
4. (69,5)
5. (69,9)
Explanation:
1. n=p*q=23*3=69
2. Φ(n)=(p-1)(q-1)=2(22)=44
3. e=5,
ed mod Φ(n)=9*5 mod 44=45 mod 44=1
4. Public key=(n,e)=(69,5)
5. Private key=(n,d)=(69,9)
In this exercise, we have to use the encryption knowledge to calculate what is needed, so we have:
1. 69
2. 44
3. 1
4. (69,5)
5. (69,9)
What is public key encryption?
Public key encryption, or public key cryptography, is a method of encrypting data with two different keys and making one of the keys, the public key, available for anyone to use. The other key is known as the private key.
1.So to perform the calculations of N, we have:
2. For relatively prime calculations we have:
3. So for the inverse module, we have:
4. For the public key, we have:
5. For the private key, we have:
See more about encryption at brainly.com/question/8455171
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why is the disk method a special case of the general slicing method? choose the correct answer below. a. the cross sections of the slices are disks with holes through them. b. the functions that generate the solids are all lines. c. the functions that generate the solids are all parabolas. d. the cross sections of the slices are disks.
b. 2
c. 3
d. 4
Answers
Answer:
b. 2
Explanation:
Answers
Answer:
int main()
{
int A1= {5,3,4,8,9,0,7};
int SArri1 = sizeof(A1);
printf("Original array: ");
for (int i=0; i < SArri1;i++)
printf("", A1[i] );
int i, sum = 20, n= 0;
printf("\nArray pairs whose sum equal to 20: ");
for (int i=0; i<SArri1; i++)
for (int j=i+1; j<SArri1; j++)
if (A1[i]+A1[j] == sum)
{
Printf(“\n”, array1[i])
Printf(“,”,array1[j]);
n++;
}
printf("\nNumber of pairs whose sum equal to 20: ",n)
return 0;
}
Explanation:
First of all, you should create the array of integers, and put random numbers. Then you have to save in a constant the size of the array (in this code is called SArr1) With a for you can print all the numbers that are on the array because then you will print all array pairs whose sum is equal to a specified numer. in this code we are going to use 20.
then with a condition (if) you are going to compare one of number of the array with all the others and check if its equal to 20. If yes, it going to print the numbers that answer to that condition and it's going to add +1 to the variable n (for this you will need to use two bucles for)
Then you can print the number of pairs whose sum is equal to 20 by printing n
Answers
typing with macros
typing with only one hand
typing without looking at the keyboard
Answers
Last one
Answers
Answer:
pkt = int(input("Pocket Number: "))
if pkt == 0:
print("Green")
elif pkt >= 1 and pkt <=10:
if pkt%2 == 0:
print("Black")
else:
print("Red")
elif pkt >= 11 and pkt <=18:
if pkt%2 == 0:
print("Red")
else:
print("Black")
elif pkt >= 19 and pkt <=28:
if pkt%2 == 0:
print("Black")
else:
print("Red")
elif pkt >= 29 and pkt <=36:
if pkt%2 == 0:
print("Red")
else:
print("Black")
else:
print("Error")
Explanation:
The program was written in Python and the line by line explanation is as follows;
This prompts user for pocket number
pkt = int(input("Pocket Number: "))
This prints green if the pocket number is 0
if pkt == 0:
print("Green")
If pocket number is between 1 and 10 (inclusive)
elif pkt >= 1 and pkt <=10:
This prints black if packet number is even
if pkt%2 == 0:
print("Black")
Prints red, if otherwise
else:
print("Red")
If pocket number is between 11 and 18 (inclusive)
elif pkt >= 11 and pkt <=18:
This prints red if packet number is even
if pkt%2 == 0:
print("Red")
Prints black, if otherwise
else:
print("Black")
If pocket number is between 19 and 28 (inclusive)
elif pkt >= 19 and pkt <=28:
This prints black if packet number is even
if pkt%2 == 0:
print("Black")
Prints red, if otherwise
else:
print("Red")
If pocket number is between 29 and 36 (inclusive)
elif pkt >= 29 and pkt <=36:
This prints red if packet number is even
if pkt%2 == 0:
print("Red")
Prints black, if otherwise
else:
print("Black")
Prints error if input is out of range
else:
print("Error")
Answers
Answer: (A) Firewall; implement an ACL on the interface
Explanation:
According to the question, for re-mediate the issue firewall should be implemented the ACL (Access control list) on the given interface. The access control list is one of the type of logic which selectively give permission or deny the number of packet in the system which to through the interface.
Firewall is the type of device that basically examine the traffic in the network system and also make several decisions in the system. ACL is the set of rule which mainly define the route of the packet in the router interface state.