What is the molar mass of CHCI3?

Answers

Answer 1

Answer:

Answer:

119.38 g/mol

Explanation:

In chemistry, the formula weight is a quantity computed by multiplying the atomic weight (in atomic mass units) of each element in a chemical formula by the number of atoms of that element present in the formula, then adding all of these products together

Answer 2

Answer:

CHCI3 = Cyclohexanol

Molar mass 100.158 g/mol

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Consider this equilibrium for a buffer solution: CH3COOH + H2O CH3COO- + H3O + . When a small amount of acid is added to this system, which statement is true when equilibrium is reestablished? A. [CH3COO-] and pH have both increased. B. [CH3COOH] and pH have both decreased. C. [CH3COO-] has decreased and pH remains relatively constant. D. [CH3COOH] has decreased and pH remains relatively constant. E. [CH3COO-] has increased and pH remains relatively constant.

HELP WILL MARK BRAINLISTWhich of the diagrams is the correct model for the element beryllium?

#12

Answers

Answer:

B is the correct model of beryllium.

Explanation:

An atom consist of electron, protons and neutrons. Protons and neutrons are present with in nucleus while the electrons are present out side the nucleus.

All these three subatomic particles construct an atom. A neutral atom have equal number of proton and electron. In other words we can say that negative and positive charges are equal in magnitude and cancel the each other. For example if neutral atom has 6 protons than it must have 6 electrons. The sum of neutrons and protons is the mass number of an atom while the number of protons are number of electrons is the atomic number of an atom.

For example in case of beryllium:

The atomic number of beryllium is 4.

The atomic mass is 9 amu.

Number protons = 4

Number of electrons = 4

Number of neutrons = 9-4 = 5

So b is correct answer because 5 neutrons and 4 protons are present with in nucleus while 4 electrons are present out side.

I believe your answer is B.

Examples of solid mixtures in a classroom

Answers

chalk, the air, cement

What is the density of a block of marble that occupies 287cm3 and has a mass of 869g?

Answers

a REALLY helpful thing when doing physics is something called the DMV triangle. So how it works is you look at what you are trying to find, which in this case is density. So you cover the D and look at the remaining M and V. Everything below the M has to be divided, and if you are just left with the D and V then you x them. It’s really simple and easy to use. So you cover up the D, and are left with M and V. So now you have to do Mass divided by Volume. 869g divided by 287cm3 would be 3.02g/cm3

Which is a site where sedimentary rocks form? A. deep underground B. forests C. volcanoes D. ancient seas

Answers

Sedimentary rocks are formed in D. ancient seas because they are formed when layers of sediment (sand, mud, dead organisms, etc) builds up on top of each other and pressure compresses them into rock

C.volcanoes
Hope it Helped

A lab technician needs to create 570.0 milliliters of a 2.00 M solution of magnesium chloride (MgCl2). To make this solution, how many grams of magnesium chloride does the technician need?Refer to the periodic table for help. Express your answer to three significant figures.

The required mass is grams.

Answers

This question needs to use the molarity equation, $M=(n)/(V)$ , where M is molarity, n is number of moles and V is the volume. With this equation we can find the number of moles. The volume of 570ml should be converted to L for correct units.

$n=MV= (2mol)/(L)* 570ml * (L)/(1000ml)= 1.14mol$

Multiply the number of moles by the molecular mass of $MgCl_2$ which is 95.21 g/mol to get the mass.

$1.14 mol Mg(Cl_2) *(95.21 g)/(mol) = 108 g$ .

109 for brainly just did it 5/5 correct (Three significant figures)

A student lost part of his lab notebook and didn’t know what the original measure should have been. He knows that he calculated a 35.5% error and his experimental measurement was 15.6 cm. What are the two possible values for the actual measurement?

Answers

Answer:

21.1cm or 10.1cm

Explanation:

Since the percent error is 35.5% and the experimental measurement was 15.6cm, the two possible values for the actual measurement are 15.6 plus 35.5% of 15.6 or 15.6 minus 35.5% of 15.6.

This is this:

15.6 + (0.355 x 15.6)
= 15.6 + 5.54
= 21.1cm

Or this:

15.6 - (0.355 x 15.6)
= 15.6 - 5.54
= 10.1cm

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