A substance with a high boiling point will also likely have A) a low melting point B) a low vapor pressure C) weak intermolecular interactions D) low surface tension E) low viscosity

Answers

Answer 1
Answer:

Answer: Option (B) is the correct answer.

Explanation:

Boiling point is defined as the temperature at which vapor pressure of a liquid becomes equal to the atmospheric pressure.

Surface tension is defined as the attractive forces experienced by the surface molecules of a liquid by the molecules present beneath the surface layer of the liquid. More stronger are the intermolecular forces present within the molecules of a liquid more will be its surface tension and lower will be its vapor pressure.

Hence, higher will be the boiling point of the liquid.

And, viscosity is defined as the ability of a liquid to resist its flow. When a substance has high viscosity then it is known as a viscous substance.

Thus, we can conclude that a substance with a high boiling point will also likely have a low vapor pressure.


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How do you fight off ADHD medication

Answers

Answer:A medication break can ease side effects. A lack of appetite, weight loss, sleep troubles, headaches, and stomach pain are common side effects of ADHD medication.

Explanation: It may boost your child’s growth. Some ADHD medications can slow a child’s growth in height, especially during the first 2 years of taking it. While height delays are temporary and kids typically catch up later, going off medication may lead to fewer growth delays.

It won’t hurt your child. Taking a child off ADHD medication may cause their ADHD symptoms to reappear. But it won’t make them sick or cause other side effects.

Give an example of coupling reaction​

Answers

Answer:

An example is the formation of ATP, which is an endergonic process and is coupled to the dissipation of a proton gradient.

Explanation:

Hope this helped!

NEED HELP FAST All living and nonliving things are made up of a combination of ______________.
Elements

Liquids

Crystals

Oxygen

Answers

Answer:

elements bruh

Explanation:

Final answer:

All living and nonliving things are made up of a combination of elements.

Explanation:

All living and nonliving things are made up of a combination of elements. Elements are pure substances that cannot be broken down into simpler substances and are the building blocks of matter. Examples of elements include oxygen, carbon, hydrogen, and nitrogen. These elements combine in different ways to form the various substances we see around us in the natural world.

Learn more about Elements here:

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50.0ml each of 1.0M Hcl and 1.0M Naoh at room temperature (20.0c) are mixed the temperature of the resulting Nacl solutions increase to 27.5cthe density if the resulting Nacl solutuion 1.02 g/ml
the specific heat of the resulting Nacl solutions is 4.06j/gc
calculate the heat of neutralisation of hcl and naoh in kj/mol nacl products​

Answers

Answer:

62.12kJ/mol

Explanation:

The neutralization reaction of HCl and NaOH is:

HCl + NaOH → NaCl + H₂O + HEAT

You can find the released heat of the reaction and heat of neutralization (Released heat per mole of reaction) using the formula:

Q = C×m×ΔT

Where Q is heat, C specific heat of the solution (4.06J/gºC), m its mass and ΔT change in temperature (27.5ºC-20.0ºC = 7.5ºC).

The mass of the solution can be finded with the volume of the solution (50.0mL of HCl solution + 50.0mL of NaOH solution = 100.0mL) and its density (1.02g/mL), thus:

100.0mL × (1.02g / mL) = 102g of solution.

Replacing, heat produced in the reaction was:

Q = C×m×ΔT

Q = 4.06J/gºC×102g×7.5ºC

Q = 3106J = 3.106kJ of heat are released.

There are 50.0mL ×1M = 50.0mmoles = 0.0500 moles of HCl and NaOH that are reacting releasing 3.106kJ of heat. That means heat of neutralization is:

3.106kJ / 0.0500mol of reaction =

62.12kJ/mol is heat of neutralization

Choose the option below that is a characteristic of ketones. a. They contain a carbonyl group that exhibits sp hybridization around the carbon atom.
b. They contain a carbonyl group with a nonpolar carbon-oxygen bond.
c. The functional group of this type of compound must always be on the end of a carbon chain.
d. The functional group of this type of compound must always be in the middle of a carbon chain.

Answers

Answer:

Option d.

Explanation:

Ketones contain a carbonyl groups as a functional group, which is a carbon bonded to oxygen with a double bond. In a ketone, the carbon is always bonded to two carbon atoms:

R-C(=O)-R'  

The carbon in the carbonyl group has a hybridization sp2 (3 hybrid orbitals with an unhybridized p orbital), where two of the orbitals form sigma (σ) bonds with the other two carbons (R-C-R') and the other hybrid orbital form a sigma bond with the oxygen (C-O). The unhybridized p orbital on the carbon atom is used to form a pi (π) bond with the oxygen, thus forming the double bond (C=O).  

The bond of a carbonyl group is polar, because of the difference of the electronegativity between the carbon atom and the oxygen atom.  

Hence, from all of the above we can discard the option a, (the carbonyl groups exhibits sp2 hybridization), the option b (carbon-oxygen bond is a bond polar) and the option c (the group must always be in the middle of a carbon chain, the groups that are always in the end, are a aldehyde groups).

Therefore, the correct option is d, the functional group of this type of compound must always be in the middle of a carbon chain.

I hope it helps you!

Answer:

d. The functional group of this type of compound must always be in the middle of a carbon chain.

Explanation:

In a lab experiment 80.0 g of ammonia [NH3] and 120 g of oxygen are placed in a reaction vessel. At the end of the reaction 72.2 g of water are obtained. Determine the percent yield of the reaction.

Answers

The percent yield of the reaction : 89.14%

Further explanation

Reaction of Ammonia and Oxygen in a lab :

4 NH₃ (g) + 5 O₂ (g) ⇒ 4 NO(g)+ 6 H₂O(g)

mass NH₃ = 80 g

mol NH₃ (MW=17 g/mol):

(80)/(17)=4.706

mass O₂ = 120 g

mol O₂(MW=32 g/mol) :

\tt (120)/(32)=3.75

Mol ratio of reactants(to find limiting reatants) :

\tt (4.706)/(4)/ (3.75)/(5)=1.1765/ 0.75\rightarrow O_2~limiting~reactant(smaller~ratio)

mol of H₂O based on O₂ as limiting reactants :

mol H₂O :

\tt (6)/(5)* 3.75=4.5

mass H₂O :

4.5 x 18 g/mol = 81 g

The percent yield :

\tt \%yield=(actual)/(theoretical)* 100\%\n\n\%yield=(72.2)/(81)* 100\%=89.14\%