Consider the following reaction at equilibrium. What effect will adding 1.4 mole of He to the reaction mixture have on the system? 2 H2S(g) + 3 O2(g) ⇌ 2 H2O(g) + 2 SO2(g) Consider the following reaction at equilibrium. What effect will adding 1.4 mole of He to the reaction mixture have on the system? 2 H2S(g) + 3 O2(g) ⇌ 2 H2O(g) + 2 SO2(g) The reaction will shift to the left in the direction of reactants. No effect will be observed. The reaction will shift to the right in the direction of products. The equilibrium constant will increase. The equilibrium constant will decrease.

Answers

Answer 1
Answer:

Answer:

The reaction will shift to the left in the direction of reactants.

Explanation:

According to Le Chatelier's principle, when an external constraint is applied to a chemical system in equilibrium, the system adjust in order to annul the effect impose on it by the external system.

Also, from the principle, the addition of an inert gas can affect the equilbrium of a gaseous system, but only if the volume is allowed to change.

There are two cases on which equilibrium depends. These are:

1. Addition of an inert gas at constant volume:

When an inert gas is added to the system in equilibrium at constant volume, the total pressure will increase. But the concentrations of the products and reactants (i.e. ratio of their moles to the volume of the container) will not change.  Hence, there will be no effect on the equilibrium.  

2. Addition of an inert gas at constant pressure:

When an inert gas is added to a system in equilibrium at constant pressure, then the total volume will increase(i.e. the number of moles per unit volume of various reactants and products will decrease). Hence, the equilibrium will shift towards the direction in which there is increase in number of moles of gases.  

Considering the given reaction in equilibrium:

2H₂S(g) + 3O₂(g) ⇌ 2H₂O(g) + 2SO₂(g)

The addition of an inert gas at constant pressure to the above reaction will shift the equilibrium towards the backward direction because the number of moles of reactants is more than the number of moles of the products.

Answer 2
Answer:

Final answer:

Adding 1.4 moles of He to the reaction mixture will have no effect on the equilibrium of the system.

Explanation:

Adding 1.4 moles of He to the reaction mixture will have no effect on the system. The equilibrium of the reaction will not shift to the left or right, and there will be no change in the equilibrium constant. This is because He is considered an inert gas and does not participate in the reaction.

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Which of the following reactions would have the smallest value of K at 298 K? Which of the following reactions would have the smallest value of K at 298 K? A + B → 2 C; E°cell = -0.030 V A + 2 B → C; E°cell = +0.98 V A + B → C; E°cell = +1.22 V A + B → 3 C; E°cell = +0.15 V More information is needed to determine.

Answers

The reactions that would have the smallest value of K is

A + B → 2 C; E°cell = -0.030 V

Option A

Generally the equation for the number of electrons transferred  is mathematically given as

nFE^o_(cell)=RT\ln K

where

T= Temperature

F=25C(298K)

R = Gas constant

R= 8.314 J/K.mol

F = Faraday's constant

F= 96500 C

We see from the equation that the E-cell is directly proportional to K(equilibrium constant of the reaction)

Hence, The reactions that would have the smallest value of K is

A + B → 2 C; E°cell = -0.030 V

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Answer:

The reaction with smallest value of K is :

A + B → 2 C; E°cell = -0.030 V

Explanation:

nFE^o_(cell)=RT\ln K

where :

n = number of electrons transferred

F = Faraday's constant = 96500 C

E^o_(cell) = standard electrode potential of the cell

R = Gas constant = 8.314 J/K.mol

T = temperature of the reaction = 25^oC=[273+25]=298K

K = equilibrium constant of the reaction

As we cans see, that standard electrode potential of the cell is directly linked to the equilibrium constant of the reaction.

  • Higher E^o_(cell) higher will be the value of K.
  • Lower E^o_(cell) lower will be the value of K.

So, the reaction with smallest value of electrode potential will have smallest value of equilibrium constant. And that reaction is:

A + B → 2 C; E^o_(cell) =-0.030 V

Two identical sister chromatids are held together at whatregion on a duplicated chromosome?
a Chromatin
b Centromere
C Centriole
Check it

Answers

  • After DNA duplication, the chromosome becomes composed of two identical structures, called sister chromatids, which are joined at the centromere area.

Final answer:

Sister chromatids are held together at the centromere on a duplicated chromosome. The centromere serves as the point of attachment. Chromatin and centrioles do not serve this function. The correct option is b) Centromere.

Explanation:

Two identical sister chromatids are held together at the centromere on a duplicated chromosome. The centromere serves as the point of attachment for sister chromatids. During cell division, the spindle fibers attach themselves to the centromere to pull apart the sister chromatids into two separate cells. This process helps ensure that each new cell receives an identical and complete set of chromosomes. Neither chromatin nor centriole holds sister chromatids together. Chromatin refers to the material chromosomes are made up of, which includes DNA and protein, while centrioles are involved in cell division. In summary, the precise answer to your question is option b) Centromere.

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A buffer solution is 0.413 M in HF and 0.237 M in KF. If Ka for HF is 7.2×10-4, what is the pH of this buffer solution?

Answers

Answer:

2.90

Explanation:

Any buffer system can be described with the reaction:

HA~->~H^+~+~A^-

Where HA is the acid and A^- is the base. Additionally, the calculation of the pH of any buffer system can be made with the Henderson-Hasselbach equation:

pH=pKa~+~Log([A^-])/([HA])

With all this in mind, we can write the reaction for our buffer system:

HF~->~H^+~+~F^-

In this case, the acid is HF with a concentration of 0.413 M and the base is F^- with a concentration of 0.237 M. We can calculate the pKa value if we do the "-Log Ka", so:

pKa~=~-Log(7.2X10^-^4)=~3.14

Now, we can plug the values into the Henderson-Hasselbach

pH=~3.14~+~Log(([0.237~M])/([0.413~M]))~=~2.90

The pH value would be 2.90

I hope it helps!

Which of the characteristics below best describes organic compounds? produced by living organisms compounds of carbon and hydrogen limited to carbon compounds which are synthetic any compound containing carbon

Answers

Answer;

Compounds of carbon and hydrogen

Explanation;

An organic compound is any of a large class of chemical compounds in which one or more atoms of carbon are covalently linked to atoms of other elements, most commonly hydrogen, oxygen, or nitrogen.

The primary difference between organic compounds and inorganic compounds is that organic compounds always contain carbon while most inorganic compounds do not contain carbon. Additionally, nearly all organic compounds contain carbon-hydrogen or C-H bonds.

Organic compounds includes nucleic acids, fats, sugars, proteins, enzymes and hydrocarbon fuels. All organic molecules contain carbon, nearly all contain hydrogen, and many also contain oxygen.

Answer:

Compounds of carbon and hydrogen

To create an image, the lens of an eye ________focuses light on the cornea
reflects light away from the retina
bends the cornea to correct vision
focuses light on the retina

Answers

It focuses light on the retina.

Answer:

focuses light on the retina

Explanation:

What is a characteristic of property acids pls help

Answers

Answer:

General Characteristics of Acids:

Sour taste (though you should never use this characteristic to identify an acid in the lab) Reacts with a metal to form hydrogen gas. Increases the H+ concentration in water. Donates H+ ions. Turns blue litmus indicator red.

ph>7
also turns blue litmus red