Answers
Answer:
the equilibrium partial pressure of BrCl is pBC = 784.52 torr
Explanation:
Since
Br₂(g) + Cl₂(g) ⇌ 2BrCl(g) , Kp=1.112 at 150 K
denoting BC as BrCl , B as Br₂ , C as Cl₂, p as partial pressure , then
Kp = pBC²/[pB*pC]
solving for pBC
pBC = √(Kp*pB*pC)
replacing values
pBC = √(Kp*pB*pC) = √(1.112*751 torr*737 torr) = 784.52 torr
pBC = 784.52 torr
then the equilibrium partial pressure of BrCl is pBC = 784.52 torr
Final answer:
To calculate the equilibrium partial pressure of BrCl, use the equilibrium constant expression and substitute the given partial pressures of Br2 and Cl2. The equilibrium partial pressure of BrCl is approximately 0.0375 atm.
Explanation:
To calculate the equilibrium partial pressure of BrCl, we need to use the equilibrium constant expression:
Kp = ([BrCl]^2) / ([Br2] * [Cl2])
Given that the equilibrium partial pressures of Br2 and Cl2 are 0.450 atm and 0.115 atm, respectively, we can substitute these values into the expression:
1.112 = ([BrCl]^2) / (0.450 * 0.115)
Simplifying the expression, we find that the equilibrium partial pressure of BrCl is approximately 0.0375 atm.
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Related Questions
Use the following structures of amino acids to answer the questions below. Note that the difference in the structures (the side chains) is highlighted by gray shading.A student performed chromatography of the four amino acids and theresults were shown in the chromatogram below. If an anion exchangecolumn (column is positively charged) was used in a neutral buffer,assign each amino acid to the corresponding peak in the chromatogram.
Be sure to answer all parts.Calculate the percent composition by mass (to 4 significant figures) of all the elements in calciumphosphate (Ca3(PO4)2), a major component of bone.% Ca%P% 0
The air temperature surrounding a snowy driveway is 0ºC. One side of the driveway is shaded, while the other side is sunny. The snow on the sunny side melts. Which statement is true? The snow absorbed chemical energy to produce a chemical change. The snow absorbed heat energy to produce a chemical change. The snow released heat energy to produce a physical change. The snow absorbed radiant energy to produce a physical change.
If you keep adding sugar to water and there comes a point that you cannot dissolve any more sugar to it then this is called
Answers
Answer:
The mass per unit volume percentage is equal to 3.43%
Explanation:
given
mass=7 grams
volume = 2 * 102 ml = 204ml
The percentage mass per volume is given by
%(m/v) = w grams of solute * 100 / Volume of solution in ml
=
= 3.43%
Final answer:
The percent mass/volume (% m/v) for a solution containing 7.00 g of dextrose in 2.00×102 mL of solution is calculated as (7.00 g / 2.00×102 mL) * 100 = 3.47%, so the dextrose solution is 3.47% m/v.
Explanation:
The percent mass/volume (% m/v) is a way of expressing the concentration of a solute in a solution. It is calculated as the mass of the solute divided by the volume of the solution, multiplied by 100%. In this case, to calculate the % m/v for a solution that contains 7.00 g of dextrose in 2.00×102 mL of solution, you would use the following equation:
% m/v = (mass of solute / volume of solution) * 100
Substituting the given values into this equation, you get:
% m/v = (7.00 g / 2.00×102 mL) * 100 = 3.47%
Therefore, the dextrose solution is 3.47% m/v.
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Answers
[Co(H2O)2(ox)2]- it is an octahedral complex which has two of bidentate ligand and another two of ligand. It exists as cis-trans isomers.
[Co(en)3]³+ it is an octahedral complex which has three bidentate ligands and it cannot exist as cis-trans isomers.
[Ni(CO)2CL2] is a square planar complex which has two of one ligand another two of ligand. It exists as cis-trans isomers.
[Co(H2O)2 (NH3)2(ox)]+ it is an octahedral complex with one of bidentate ligand two of each another ligand. It exists as cis-trans isomers.
[Ni(NH3)2 (en)2]²+ is an octahedral complex with one of a bidentate ligand and two each of another ligand. It exists as cis-trans isomers.
Following compounds exhibit geometric isomerism.
[Co(H2O)2 (ox)2]-
[Co(H2O2) (NH3)2 (ox)]+
[Ni(Co)2 CL2]
[Ni(NH3)2 (en)2]²+
Answers
Final answer:
The Gibbs free energy change (ΔG∘) for the reaction can be estimated using the equation ΔG∘ = ΔH∘ - TΔS∘. At a temperature of 718K, if ΔG∘ is negative, the reaction will be spontaneous.
Explanation:
The Gibbs free energy change (ΔG∘) for a reaction can be estimated using the equation ΔG∘ = ΔH∘ - TΔS∘, where ΔH∘ is the change in enthalpy and ΔS∘ is the change in entropy. At a temperature of 718K, you can estimate ΔG∘ by substituting the given values into the equation. If the value of ΔG∘ is negative, the reaction will be spontaneous. If it is positive or zero, the reaction will not be spontaneous.
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Answers
Answer:
C) Both
Explanation:
Whenever we mix any pure form of a compound with some other form of a compound which is not in the other standard pure state, this results in the melting point of mixture to get dispersed and it becomes broad form.
Thus, when a known compound of 3-Nitroaniline mixes with both 3-Nitroaniline and 4-Nitrophenol, the melting point of the compound becomes depressed and board.
Thus the correct option is (C).
B) Jet Fuel
C) steel
Answers
Option-C, STEEL is not a product of the fractional distillation of petroleum.
Explanation:
Petroleum is the mixture of Hydrocarbons *carbon and hydrogen containing compounds) present beneath the Earth's surface. Petroleum is formed from the remains of animals and plants beneath earth's surface in an anaerobic conditions.
Petroleum contains from small hydrocarbons (gases) to medium (liquids) and long chain hydrocarbons (Solids). These hydrocarbons are separated from each other by Fractional Distillation method (separation due to difference in boiling points)
Gasoline is a derivative of one of the fraction of petroleum used in internal combustion engines.
Jet Fuel is also derived from Kerosene and Naphtha fractions of petroleum.
While, Steel is inorganic Alloy (mixture of metals) composed of mainly Iron, Carbon and other elements.
Answers
Answer: Option (2) is the correct answer.
Explanation:
Atomic number of oxygen atom is 8 and its electronic distribution is 2, 6. So, it contains only 2 orbitals which are closer to the nucleus of the atom.
As a result, the valence electrons are pulled closer by the nucleus of oxygen atom due to which there occurs a decrease in atomic size of the atom.
Whereas atomic number of sulfur is 16 and its electronic distribution is 2, 8, 6. As there are more number of orbitals present in a sulfur atom so, the valence electrons are away from the nucleus of the atom.
Hence, there is less force of attraction between nucleus of sulfur atom and its valence electrons due to which size of sulfur atom is larger than the size of oxygen atom.
Thus, we can conclude that the oxygen atom is smaller than the sulfur atom because the outer orbitals of oxygen are located closer to the nucleus than those of sulfur.
Final answer:
The oxygen atom is smaller than the sulfur atom because the outer orbitals of oxygen are located closer to the nucleus than those of sulfur.
Explanation:
The correct option is (2) the outer orbitals of oxygen are located closer to the nucleus than those of sulfur.
To understand why the oxygen atom is smaller than the sulfur atom, we need to consider their electron configurations. Oxygen has 8 electrons and sulfur has 16 electrons. Oxygen's electron configuration is 1s²2s²2p⁴, while sulfur's electron configuration is 1s²2s²2p⁶3s²3p⁴.
The outer orbitals of an atom, which are the valence orbitals, are the ones involved in bonding. The electrons in these orbitals determine the size of the atom. In the case of oxygen and sulfur, the outer orbitals of oxygen (2p orbitals) are closer to the nucleus compared to sulfur's outer orbitals (3p orbitals). As a result, the oxygen atom is smaller than the sulfur atom.
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