What formula was used to find the answer

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Answer 1
Answer: Can you give more information?

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14) Describe the Cloud Model.

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Electron cloud is an informal term in physics. It is used to describe where electrons are when they go around the nucleus of an atom. The electron cloud model is different from the older Bohr atomic model by Niels Bohr. Bohr talked about electrons orbiting the nucleus.

Pls answer this question

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Answer:

A carbon dioxide and oxygen

A buffer solution is 0.413 M in HF and 0.237 M in KF. If Ka for HF is 7.2×10-4, what is the pH of this buffer solution?

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Answer:

2.90

Explanation:

Any buffer system can be described with the reaction:

HA~->~H^+~+~A^-

Where HA is the acid and A^- is the base. Additionally, the calculation of the pH of any buffer system can be made with the Henderson-Hasselbach equation:

pH=pKa~+~Log([A^-])/([HA])

With all this in mind, we can write the reaction for our buffer system:

HF~->~H^+~+~F^-

In this case, the acid is HF with a concentration of 0.413 M and the base is F^- with a concentration of 0.237 M. We can calculate the pKa value if we do the "-Log Ka", so:

pKa~=~-Log(7.2X10^-^4)=~3.14

Now, we can plug the values into the Henderson-Hasselbach

pH=~3.14~+~Log(([0.237~M])/([0.413~M]))~=~2.90

The pH value would be 2.90

I hope it helps!

An insulated container contains 0.3 kg of water at 20 degrees C. An alloy with a mass of 0.090 kg and an initial temperature of 55 degrees C is mixed with the water in the insulated container. When thermal equilibrium is reached, the temperature of the mixture is 25 degrees C. Assume that heat flows only between the alloy and the water. What is the specific heat of the alloy?

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Answer:

The specific heat of the alloy is 2.324 J/g°C

Explanation:

Step 1: Data given

Mass of water = 0.3 kg = 300 grams

Temperature of water = 20°C

Mass of alloy = 0.090 kg

Initial temperature of alloy = 55 °C

The final temperature = 25°C

The specific heat of water = 4.184 J/g°C

Step 2: Calculate the specific heat of alloy

Qlost = -Qwater

Qmetal = -Qwater

Q = m*c*ΔT

m(alloy) * c(alloy) * ΔT(alloy) = -m(water)*c(water)*ΔT(water)

⇒ mass of alloy = 90 grams

⇒ c(alloy) = the specific heat of alloy = TO BE DETERMINED

⇒ ΔT(alloy) = The change of temperature = T2 - T1 = 25-55 = -30°C

⇒ mass of water = 300 grams

⇒ c(water) = the specific heat of water = 4.184 J/g°C

⇒ ΔT(water) = The change of temperature = T2 - T1 = 25 - 20 = 5 °C

90 * c(alloy) * -30°C = -300 * 4.184 J/g°C * 5°C

c(alloy) = 2.324 J/g°C

The specific heat of the  alloy is 2.324 J/g°C

How much energy is required to heat the solid iron from 1535 ∘C to 2000 ∘C?

Answers

"206.46 J/g" energy required to heat the solid iron.

Energy due to change in temperature:

The movements or the activity of microscopic particles known as atoms, molecules, or ions in solids, solvents, as well as gases.

Thermal energy may go from one item towards the another one.

Given:

Temperature, T_1 = 1535°C

                       T_2 = 2000°C

Change, \Delta T = T_2-T_1

We know the relation,

Q = mC_p \Delta T

By putting the values,

      = 0.444(2000-1535)

      = 206.46 J/g

Thus the answer above is right.

Find out more information about energy here:

brainly.com/question/2033877

Answer:

Q=206.46(J)/(g)

Explanation:

Hello,

In this case, since the energy due to the change of temperature is computed via:

Q=mCp\Delta T

Thus, since the specific heat of iron is 0.444 J/(g°C), the heat per unit of mass turns out:

Q=0.444(J)/(g\°C)(2000-1535)\°C\n \nQ=206.46(J)/(g)

Best regards.

Convert a distance of 150 ft to its equivalent in cm

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Answer:

4572cm

Explanation: 1ft =30.48cm so you multiply the length value by 30.48