Hercules X-1 is a pulsating X-ray source. The X-rays from this source sometimes completely disappear for 6 hours every 1.7 days because the neutron star has a 1.7-day orbital period around its companion star, and it is eclipsed for ____ hours once every orbital period.

Answers

Answer 1

Answer:

Answer:

06 Hours

Explanation:

As per the details given in the question it self, the neutron star X-1 is revolving around its companion star. The orbital period is 1.7 years which means it will complete the revolution in 1.7 years. During the movement in the orbit we will be able to detect the x-rays except for the time when it goes behind the companion star and eclipsed by it as seen from Earth.

Since the x-rays disappear completely for around 6 hours. This clearly means that eclipse period is 06 hours.

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A uniform electric field, with a magnitude of 370 N/C, is directed parallel to the positive x-axis. If the electric potential at x = 2.00 m is 1 000 V, what is the change in potential energy of a particle with a charge of + 2.80 x 10-3 C as it moves from x = 1.9 m to x = 2.1 m?

Answers

Answer:

$\Delta U = 0.2072 J$

Explanation:

Potential difference between two points in constant electric field is given by the formula

$\Delta V = E.\Delta x$

here we know that

$E = 370 N/C$

also we know that

$\Delta x = 2.1 - 1.9 = 0.2 m$

now we have

$\Delta V = 370 (0.2) = 74 V$

now change in potential energy is given as

$\Delta U = Q\Delta V$

$\Delta U = (2.80 * 10^(-3))(74)$

$\Delta U = 0.2072 J$

A person pushing a stroller starts from rest, uniformly accelerating at a rate of 0.500 m/s2. What is the velocityof the stroller after it has traveled 6.32 m?

Answers

You're going to use the constant acceleration motion equation for velocity and displacement:

(V)final² = (V)initial²+2a(dx)

Given:

a=0.500m/s²

dx=6.32 m

(V)intial=0m

(V)final= UNKNOWN

(V)final= 2.51396m/s

Consult Interactive Solution 7.10 for a review of problem-solving skills that are involved in this problem. A stream of water strikes a stationary turbine blade horizontally, as the drawing illustrates. The incident water stream has a velocity of 16.0 m/s, while the exiting water stream has a velocity of -16.0 m/s. The mass of water per second that strikes the blade is 48.0 kg/s. Find the magnitude of the average force exerted on the water by the blade.

Answers

Explanation:

Initial speed of the incident water stream, u = 16 m/s

Final speed of the exiting water stream, v = -16 m/s

The mass of water per second that strikes the blade is 48.0 kg/s.

We need to find the magnitude of the average force exerted on the water by the blade. The force acting on an object is given by :

$F=(m(v-u))/(t)$

Here, $(m)/(t)=48\ kg/s$

$F=48* (-16-16)\ N\n\nF=-1536\ N\n\n|F|=1536\ N$

So, the magnitude of the average force exerted on the water by the blade is 1536 N.

Is it true or false if a force is a push or a pull on a object

Answers

Answer: true

Explanation: a force can be anything that effects an object, as long as the object moves

Answer:True

Explanation:Because anything that is being pushed of pulled is called force.

HOPE IT HELPED :)

A remote controlled car is moving in a vacant parking lot. The velocity of the car as a function of time is given by v= [5.00 m/s – (0.0180 m/s3)t^2 ]i+[2.00 m/s + (0.550 m/s2)t ]j .a) What are ax(t) and ay(t), the x- and y- components of cars acceleration as a function of time?
b) What are the magnitude and direction of the velocity of the car at t= 8 sec?
c) What is the magnitude and direction of cars acceleration at t=8 sec

Answers

Maybe try A for your answer

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