Jeremy is 29 years old and in good health. What is the annual premium for the cheapest policy having a $90,000 face value that Jeremy can buy?For age 29, a male whole life if 18.25, 20-payment life is 31.39, and 20-year endowment is 39.69.

a.

$1,825

b.

$1,294

c.

$1,929

d.

$1,643

i just did it and its D

Answers

Answer 1

Answer:

1643 is the annual premium for the cheapest policy Jeremy can buy.

What is Annual Premium?

The amount of money a business or an individual pays for a policy annually is called the annual premium.

Face value is the amount of benefits in the form of money or other beneficiaries a policy holder receives at maturity.

Age of Jeremy = 29

Face value of the policy = $90,000

Estimated annual premium = (Face value ÷ 1000) × rate

Annual premium payable for a man whole life = (90,000 ÷ 1000) × 18.25

= 90 × 18.25

= 1642.5 ≅ 1643

Hence, Annual premium for the cheapest policy having a 90,000 face value that Jeremy can buy is $1643.

To learn more on Face value, click:

brainly.com/question/14294215

#SPJ3

Answer 2

Answer:

Step-by-step explanation:

Related Questions

The circumference of a circle is 19π in. What is the area, in square inches? Express your answer in terms of π.
A local little league has a total of 65 players, of whom 80% are left-handed. How many left-handed players are there?
Determine the theorem that justifies each if-then statement.Theorems:• Corresponding Angles Theorem• Corresponding Angles Converse Theorem• Same-Side Interior Angles Theorem• Same-Side Interior Angles Converse Theorem• Alternate Interior Angles Theorem• Alternate Interior Angles Converse Theorem• Same-Side Exterior Angles Theorem• Same-Side Exterior Angles Converse Theorem• Alternate Exterior Angles Theorem• Alternate Exterior Angles Converse Theorem• Perpendicular/Parallel Line Theorem
Which figures demonstrate a rotation? somebody please help!
What is the approximate area of a circle whose radius is 3 m long? (Use 3.14 for pi.)

Two classes have a total of 50 students. One of the classes has 6 more students than the other. How many students are in the larger class.

Answers

Let's say 'x' to number of the students in the smaller class. Since the larger one is 6 more than the smaller one, its number would be 'x+6'. So their sum is equal to

$x+x+6=2x+6$ and we know total is 50 so:
$2x+6=50\n 2x=50-6\n 2x=44\n x=\frac { 44 }{ 2 } \n x=22$

x is 22 so the larger number 'x+6' is equal to : $x+6=22+6=28$

There are 28 students in the larger class.

Let's assume the number of students in one class is x.

Since the other class has 6 more students, the number of students in the other class is x + 6.

The total number of students in both classes is 50.

Therefore, we can write the equation:

x + (x + 6) = 50

2x + 6 = 50

Subtracting 6 from both sides:

2x = 44

Dividing both sides by 2:

x = 22

So, the number of students in the larger class, which is x + 6, is:

22 + 6 = 28

Therefore, there are 28 students in the larger class.

To learn more on Equation:

brainly.com/question/10413253

#SPJ6

Name ScoreJulia 650
Andrew 550
Jason 380
Cathy 720
Jessica 710
Robert 550
The table gives the scores of 6 students from a class of 25 in a competitive exam. The point estimate of the mean score for the students is _____-
. (Round off your answer to the nearest tenth.)

Answers

Answer

593.3

Explanation

Mean is also called average. It represents the average mark of a given data.

For the question above, you to add all the marks of the students then you divide by the number of students.

Mean = (650+550+380+720+710+ 550)÷6

= 3,560 ÷ 6

=593.3333

Answer to the nearest tenth = 593.3

The point estimate of the meanscore for the students is 593.34 if the number of observation is 6.

What is mean?

It is defined as the single number that represents the mean value for the given set of data or the closed value for each entry given in the set of data.

We know,

Mean = (sum of observation)/(number of observation)

Sum of scores = 650+550+380+720+710+550 = 3560

Number of observation = 6

Mean = 3560/6 = 593.33 = 593.34

Thus, the point estimate of the meanscore for the students is 593.34 if the number of observation is 6.

Learn more about the mean here:

brainly.com/question/22871228

#SPJ5

If the trends in this table continue , after how many years y will the population of Manchester , NH be more than the population of Vallejo , CA ? Round your answer to the nearest tenth of a year

Answers

As soon as I read the first line and saw the words "in this table", I knew in my
guts that when I opened the question and saw the whole thing, there would be
no table. So I opened it and, sure enough, my guts were correct again.

Nobody ... including you ... can answer this question without seeing the table.
Maybe that's been your whole problem, and the reason you're having trouble
with it. Sit down, relax, and spend some time with the table.

Table:City: Lakewood, CoPopulation (2004): 141,301Population Change (2003): -830City : Vallejo, CAPopulation (2004): 118,349Population change (from 2003): -1155City: Carrollton, TXPopulation(2004): 117,823Population change (2003): +1170City: ManchesterPopulation (2004): 109,310Population change (from 2003): +261

HELP FAST PLEASE What is the value of the function at X=-3?
O y = 4
O y = 0
O y = 3
0y=-3

Answers

Answer:

To determine the value of the function at x = -3, we need to substitute -3 into the given function and evaluate it. Let's go through each option one by one:

1. y = 4: If this is the function, then substituting x = -3 would give us y = 4. However, this option does not match the given function.

2. y = 0: Substituting x = -3 into this function would give us y = 0. However, this option does not match the given function either.

3. y = 30: Substituting x = -3 into this function would give us y = 30. However, this option does not match the given function.

4. y = -3: Substituting x = -3 into this function would give us y = -3. This option matches the given function, so the value of the function at x = -3 is indeed y = -3.

Therefore, the correct answer is:

y = -3

MARK AS BRAINLIEST!!!

Can anyone do question 25 part c? :)

Answers

$\begin{cases}x^3\qquad\qquad\ \ \ when\ x\geq3\n5\qquad\qquad\quad \ when\ 0\ \textless \ x\ \textless \ 3\nx^2-x+2\quad\ when\ x\leq0 \end{cases}\n\n\n (a)\n f(0)\iff x=0\implies f(x)=x^2-x+2\n\nf(0)=0^2-0+2=2\n\n(b)\n \{f(2)\iff x=2;\ \ f(1)\iff x=1\}\implies f(x)=5\n\n f(2)=5\quad\wedge\quad f(1)=5\n\n f(2)-f(1)=5-5=0$

$(c)\n \big\forall \limits_( n\in R)\ n^2\geq 0\ \ \Rightarrow\ \ \big\forall \limits_( n\in R)\ (-n^2)\leq 0 \ \ \Rightarrow\ \ x\leq0\ \ \Rightarrow\ \ f(x)=x^2-x+2\n\nf(-n^2)=(-n^2)^2-(-n^2)+2=n^4+n^2+2$

Hey Help me out please, thanks!