the average adult human male has a total blood volume of 5.0 L. if the concentration of sodium ion in this average individual is 0.135 M, what is the mass of sodium ion circulating in the blood?

Answers

Answer 1

Answer: Molarity is a way of expressing concentration that is equal to the ratio of the moles of the solute to the liters of solution. The amount of substance in moles can be calculated through,
moles = (molarity) x (volume in liters)
Substituting the values,
moles = (0.135 M) x (5.0 L) = 0.675 moles
Multiply this value with the molar mass of sodium ion,
mass = (0.675 moles) x (23 g/ mole) = 15.525 grams
Therefore, the mass of sodium ion in the blood is 15.525 grams.

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Within a single molecule of water, two hydrogen bonds are bonded to a single oxygen atom by_______.However when there are multiple water molecules, the partial negative charge at one end of a water molecule attracted to the partial ositive charge of another water molecule forms ____________.

Answers

Answer:

covalent bonding, hydrogen bonding

Explanation:

The molecular formula of water is $H_2O$ in which the two hydrogen atoms are connected to the oxygen atom via covalent bonds which means that the electrons are shared in the bond.

Hydrogen bonding is a special type of the dipole-dipole interaction and it occurs between hydrogen atom that is bonded to highly electronegative atom which is either fluorine, oxygen or nitrogen atom.

Partially positive end of the hydrogen atom is attracted to partially negative end of these atoms which is present in another molecule. It is strong force of attraction between the molecules.

Thus, when multiple water molecules are there, there are connected by hydrogen bonding.

I have to write a 150 word paragraph or two that describes at least three everyday things that exist or occur because of science. I also have to make sure i use examples. I don't have a clue where to start ??? PLEASE help!

Answers

You can do something like natural disasters and explain why they happen

Consider the following equilibrium:4KO2(s) + 2H2O(g) 4KOH(s) + 3O2(g)

Which of the following is a correct equilibrium expression?

A.
`"K"_("eq") = (["KOH"]^4["O"_2]^3)/(["KO"_2]^4["H"_2"O"]^2)`

B.
`"K"_("eq") = (["H"_2"O"]^2)/(["O"_2]^3)`

C.
`"K"_("eq") = (["KO"_2]^4["H"_2"O"]^2)/(["KOH"]^4["O"_2]^3)`

D.
`"K"_("eq") = (["O"_2]^3)/(["H"_2"O"]^2)`

Answers

Answer:

Answer is option D

Explanation:

The explanation is embedded in the word document attached

Answer:

Keq= [KOH]^4 [O2]^3/[[KO2]^4

Explanation:

4KO2(s) + 2H2O(l) → 4KOH(s) + 3O2(g)

Looking at the equation, the correct equilibrium expression is shown in the answer. The equilibrium constant for a reaction is given by the active masses of species involved in the reaction. The relative molar coefficients of species are raised to the power of their molar concentrations to give the active mass of each specie. This active mass now goes into the equilibrium equation.

Water is not included in the equilibrium equation because, as a solvent, it is present in large excess.

A substance that can be separated into two or more substances only by a chemical change is

Answers

A substance that can be separated into two or more substances only by a chemical change is known as a heterogeneous mixture

Determine the new pressure of o2(g) in the cylinder in atmospheres

Answers

It is an ideal gas therefore we can use the ideal gas equation to solve the problem. The ideal gas equation is expressed as PV = nRT where P is the pressure, V is the volume, n is the number of moles, R is the universal gas constant and T is the temperature. V, n, and T should be known to solve this problem.

How many hybrid orbitals are found in CCl4?

Answers

CCl4

For central atom C

The formula to calculate hybridization is:

n= 1/2 [group no. central atom +no. of monovalent atoms attached to central metal atom (except oxygen) + magnitude of negative charge - magnitude of positive charge]

n= 1/2 [4 +4 + 0-0]

n= 1/2 [8)

The hybridization is sp3 and the electron geometry is tetrahedral

the answer is FOUR 4
hope this helps ;)

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