MATHEMATICS COLLEGE

Problem 8-19 Because of high tuition costs at state and private universities, enrollments at community colleges have increased dramatically in recent years. The following data show the enrollment (in thousands) for Jefferson Community College for the nine most recent years. Click on the datafile logo to reference the data. Year Period (t) Enrollment (1,000s) 1 1 6.5 2 2 8.1 3 3 8.4 4 4 10.2 5 5 12.5 6 6 13.3 7 7 13.7 8 8 17.2 9 9 18.1 Use simple linear regression analysis to find the parameters for the line that minimizes MSE for this time series.If required, round your answers to two decimal places.
y-intercept, b0 = 4.7.17
Slope, b1 = 1.46
MSE = ???????? NEED THIS
What is the forecast for year 10? 19.283
Round your interim computations and final answer to two decimal places.

Answers

Answer 1

Answer:

Answer:

a) find the attached graph

b) find the attachment no 4 and 5

c) $T_(10)= 4.72+1.46(10) = 19.28$

Step-by-step explanation:

a) A trend pattern exist if the time series plot gradually shifts to higher or lower values over a long period of time

find the attached graph

b) Liner Trend Equation

$T_(1) =b_(0) +b_(1)t$

Where $T_(1)$ is the linear trend forecast in period t , $b_(0)$ is the intercept of the linear trend time, $b_(1)$ is the slope of the linear trend line, t is the time period

now computing the slope and intercept

formula is attached ( 3 no attachment)

$Y_(t)$ is the value of the time series in period t, n is the number of time periods

Y(bar) is the average value and t(bar) is the average value of t

due to unavailability of equation in math-script i attached the calculation part of this question( 4th and 5th no attachment)

thus the linear trend equation is $T_(t)= 4.72+1.46t$ (1)

$T_(10)= 4.72+1.46(10) = 19.28$

Answer 2

Answer:

Final answer:

To find the Mean Squared Error (MSE), you can calculate the difference between the actual and predicted values, square these differences, and find their average. To forecast for a specific year, you can insert the year as the 'x' value into the simple linear regression equation.

Explanation:

The question is asking for the Mean Squared Error (MSE) for a simple linear regression model based on the enrollment data of Jefferson Community College. This involves using the y-intercept (b0) and slope (b1) values provided, and the given data points. You can calculate the MSE by taking the difference between the actual and predicted values (errors), squaring these differences, and then finding the average of these squared differences for the entire dataset.

Then, to forecast for year 10, you use the simple linear regression model equation, y = b0 + b1*x, where y represents the predicted enrollment. So, for year 10, you would insert 10 as your 'x' value into the equation, which results in the forecast value provided which is 19.283.

Learn more about Simple Linear Regression here:

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I need help with this one pleaseeeeeee (first will get brainliest)

Answers

Answer:

y = x + 15

Step-by-step explanation:

I tried all of them but that one works. U can try it on each number. Brainliest plz! Hope this helps!

Answer:

Y=2x is the answer

Step-by-step explanation:

Match the postions on the number line with the numbers they represent

Answers

1.8,-2.2,1.8,-2.2,-1.8,-1.8,2.2,2.2

they are listed from top to bottom

What the area of the polygon below

Answers

Answer:

i how are you

Step-by-step explanation:

A farmer notes that in a field full of horses and chickens there are 35 heads and 98 feet. How many of each animal are there?

Answers

Answer:

There are 14 horses and 21 chickens.

Step-by-step explanation:

First, you have to make expression for horse and chicken. So we can let x be the number of horses and y will be the number of chickens. Next, given that the total number of feet for both animals is 98 so you have to make simultaneous equation :

$4x + 2y = 98$

(horse has 4 feet and chicken has 2 feet)

There are a total of 35 heads so the other equation will be :

$x + y = 35$

Lastly, you have to solve it :

$4x + 2y = 98$

$2(2x + y) = 98$

$2x + y = 49 - - - (1)$

$x + y = 35 - - - (2)$

$(1) - (2)$

$2x + y - x - y = 49 - 35$

$x = 14$

$substitute \: x = 14 \: into \: (2)$

$14 + y = 35$

$y = 35 - 14$

$y = 21$

out of 24 students, 6 preferred to use pastels for their portraits while 4 preferred to use watercolours watercolours. what percentage of the class preferred pastels? % Jasmin bought a box of 40 assorted coloured pastels, 1/5 are blue, 3/10 are green, 20% are red and 5 are yellow. Of which colour are there most pastels? How many pastels are colours other than blue, green, red or yellow?

Answers

The percentage of the class-preferred pastels will be 25%. The color there has most pastels will be Green. And the number of pastels that are colors other than blue, green, red, or yellow will be 7.

What is the percentage?

The quantity of anything is stated as though it were a fraction of a hundred. A quarter of 100 can be used to express the ratio. Per 100 is what the term percent signifies. The symbol ‘%’ is used to symbolize it.

Out of 24 students, 6 preferred to use pastels for their portraits while 4 preferred to use watercolors. Then the percentage of the class preferred pastels will be

P = 6 / 24 x 100

P = 0.25 x 100

P = 25%

Jasmin bought a box of 40 assorted colored pastels, 1/5 are blue, 3/10 are green, 20% are red and 5 are yellow. Then the number of pastels of each color will be

Blue = 1/5 = 8 / 40 = 8

Green = 3/10 = 12 / 40 = 12

Red = 0.2 = 1/5 = 8 / 40 = 8

Yellow = 5

The number of pastels are colors will be

⇒ 40 - 8 - 12 - 8 - 5

⇒ 40 - 33

⇒ 7

The color there has most pastels will be Green. And the number of pastels that are colors other than blue, green, red, or yellow will be 7.

More about the percentage link is given below.

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Answer:

4% used pastels.

Step-by-step explanation:,,

green is the most

5 isnt blue.green,yello or red

A rental company rents big-screen televisions for $22 down plus $4 a day. If the final bill is $46, how many days did you rent the television for? *